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How many times can we re register?

How many times can we re register?


  • N times..i guess..as long as you can pay... 24m.
  • (N - M * 10%N) times...... 1s.
Looks like knocking at CL's door early in the morning helped. They gave me a new access code and I could resume my test. :D QA - 99 marks ( 35/41 ) VA - 62 ( 24/34 ) OA - 161 .. ( 59 / 75 )

Looks like knocking at CL's door early in the morning helped. They gave me a new access code and I could resume my test. :D 

QA - 99 marks ( 35/41 )

VA - 62 ( 24/34 ) 

OA - 161 .. ( 59 / 75 ) 

  • 2 Likes   11Comments
  • @SilverCrow So almost 100 it is for QADI!!. 1m.
In the decimal number of numeration ,the number of 6 digit numbers in which the sum of the digits is divisible by 5 is

In the decimal number of numeration ,the number of 6 digit numbers in which the sum of the digits is divisible by 5 is 

2 people answered this question.
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Is anybody else experiencing problem with IMS site or is it just me! Am trying to open it since morning to no avail!! @OfficialIMS Please resolve.

Is anybody else experiencing problem with IMS site or is it just me! Am trying to open it since morning to no avail!!

@OfficialIMS Please resolve. 

  • me too :disappointed:. 4m.
This might help. PS: I have availed it for myself , checked the contents, hence sharing. http://catstudymaterial.wordpress.com/ http://imojo.in/cat100

This might help. PS: I have availed it for myself , checked the contents, hence sharing.


http://catstudymaterial.wordpress.com/


http://imojo.in/cat100


CAT study material
CAT study material
CONTENT CHECKLIST: OF: A TOTAL OF 858 PERFECTLY DESIGNED MOCKS WITH DETAILED SOLUTIONS SCORE VS. PERCENTILE ANALYSIS, VIDEO SOLUTIONS. TIME AIMCAT SERIES: 2014,2013, 2012, 2011, 2010, 2009, 2008, 2007, 2006, 2005 KEYS DETAILED SOLUTIONS ANALYSIS SCORE VS PERCENTILE STATISTICS FOLLOW UP DISCUSSIONS CUM WORKSHOPS STRATEGIES. CAREER LAUNCHER SERIES:Proctored mock 2014,2013, 2012, 2011, 2010, 2009, 2008.

Instamojo

  • 193 Likes   84Comments
  • Aap mahaan ho bhaai..__/\\_ Bacha liye aapne... 11h.
  • Thanks. Amazing compilation.. 7m.
  84 Comments
Find out error in the following sentence if any and mark Sr. no. of the relative part. In case of no error mark Sr no.4. Ignore punctuation error . *For more similar exercises www.englishgrammarlesson.blogspot.com.* *EXERCISE NO. E. 214* 1\. If I would have realised the hazard 2. involv...


Find out error in the following sentence if any and mark Sr. no. of the relative part. In case of no error mark Sr no.4. Ignore punctuation error .

For more similar exercises  www.englishgrammarlesson.blogspot.com.

EXERCISE NO. E. 214

1.  If I would have realised the hazard 2. involved in this adventure I

3. would never have advised you to participate in it.

69 people answered this question.
8 Comments
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The present time seems ___________ to bad ideas. In the process of throwing off the shackles of tradition, we have ended up being quite __________ incipient theories and untested solutions.


The present time seems ___________ to bad ideas. In the process of throwing off the shackles of tradition, we have ended up being quite __________ incipient theories and untested solutions.


6 people answered this question.
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If x,y,z are in GP and a^x,b^y and c^z are equal, than a,b,c are in which progression?


If x,y,z are in GP and a^x,b^y and c^z are equal, than a,b,c are in which progression?

  • GP. 1h.
  • taking x, y, z as 1,2,4. then we get a, b, c as 16,4 ,2. .... 11m.
where can i get cl mocks of new pattern....with separate answers at the end...guys please help.

where can i get cl mocks of new pattern....with separate answers at the end...guys please help.

Hi, I am looking to do a BBA program in Australia. Can anyone suggest some colleges?

Hi, I am looking to do a BBA program in Australia. Can anyone suggest some colleges?


  • 6Comments
  • That's really good. Let me take a look at their website.. 24m.
  6 Comments
aan54
aan fan @aan54

That's really good. Let me take a look at their website.

what is the difficulty level of 1513?

what is the difficulty level of 1513? 

  • 4Comments
  • @kundan2007 I see you are quite consistent with these aim.... 40m.
  • @Huey thanks..i don't keep record of the things..i m just.... 31m.
Yesh007
Shade™ . @Yesh007 93

Quant was slightly tough and verbal was slightly easier**....

**compared to 1514 and 1515...



Huey
Huey_00 @Huey 404

@kundan2007 I see you are quite consistent with these aimcat threads And adding to that, your guesses are also good. Keep it up. My question was how do you manage to keep a record of all these things, that too with a good accuracy level ?  

kundan2007
kundan kumar @kundan2007 66

@Huey thanks..i don't keep record of the things..i m just a time aimcat sudent and predicting the percentiles based on my experience..

Find the sum of all numbers co prime to 30 and less than 300. (a) 9000 (b) 12000 (c) 15000 (d) 20000

Find the sum of all numbers co prime to 30 and less than 300. (a) 9000 (b) 12000 (c) 15000 (d) 20000


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How many ordered natural numbers (J,K) are there such that (J - K) = 3 and difference in the number of zeroes of J! and K! = 2, given that both J, K are less than 300.

How many ordered natural numbers (J,K) are there such that (J - K) = 3 and difference in the number of zeroes of J! and K! = 2, given that both J, K are less than 300.

  • 8Comments
  • How do we solve this kind of problems?. 4h.
  • 27 ... (22, 25) (23,26) (24 , 27) like that for every mu.... 34m.
  8 Comments
catKrazy2.0
Nagraj Gunda! @catKrazy2.0 7

27 ...  (22, 25) (23,26) (24 , 27) like that for every multiple of 25 and not multiple of 125..

total 9 such groups .. 9*3  

What is the remainder when 40! is divided by 41? (a) 0 (b) 1 (c) 29 (d) 40

What is the remainder when 40! is divided by 41? (a) 0 (b) 1 (c) 29 (d) 40


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h(n) = 2.4.6. … n (i.e. for every positive integer n, the function h(n)=product of all the even integers from 2 to n). If P is the smallest prime factor of h(100)+1, then P is

h(n) = 2.4.6. … n (i.e. for every positive integer n, the function h(n)=product of all the even integers from 2 to n). If P is the smallest prime factor of h(100)+1, then P is



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