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Easy paper messed up in va- section quant was very easy ...could be a stress reliever for many ....qa 90(32/38) va 42(18/30)....and yes I m not xpectin too good a percentile this time

PS: I scored just 76 in the last one and were oscillating around 100 in all the others..

I IM possible!!!
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Directions for question: In each question, the word at the top is used in four different ways, numbered A to D. Choose the option in which the usage of the word is INCORRECT or INAPPROPRIATE.

SHADOW


3 people answered this question.
You can view the comments after answering or skipping this question.
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Question 51, the World cup problem is solved wrong.

In solution it is assumed that the team which proceeds to the Super 6 are having points as 4, 2 and 0.

But they have assigned 4 points to India, which is impossible, because, one of the teams which is advancing hasn't lost any match and other team is one which has lost its only match to the first team. India is the 3rd team which happens to advance with just 3 wins and that too against other 5 teams in its group. So India's carry forward point should be zero.

Solution ahead of this is made on assumption that India has 4 points.

Any view @shashwatdgr8 ?

  • uhm and where exactly in the solution have they assigned .... 2h.
  • In the video solution, the teachers assigns 4 points to I.... 43m.
Always learning and evolving
shashwatdgr8
Shashwat Gangwar @shashwatdgr8 610

uhm and where exactly in the solution have they assigned 4 points to India?

ajhavery
Ankur Jhavery @ajhavery 123

In the video solution, the teachers assigns 4 points to India at the End of group stage, which is wrong.

Nevermind, I just see that in text solution, it has been solved correctly.

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MC1510N:

QA:89(31C 4W)

VA:71(25C 4W)

OA:160

1h ago 220 CAT

The PaGaLGuY UnderDogs Team 2014

Do you love taking up the challenge where you are considered as a person who cannot achieve the pinnacle easily but t...

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CL mock 10.. such an easy mock with so many sitters and I managed to screw it.. OA-124  (QA- 26C,4W VA- 21C, 13W  )

1. Decided to start with VA- bad decision

2. Mouse was not working properly. I wasn't able to figure out whether I need to double click or single click and had to click 8-10 times for every answer.

3. A friend was calling continuously in ast 15mins of my test and phn was on vibrations..

well, still it's no time to give excuses,you never know how the D-day would be.. But I am really disappointed after this mock..


  • 1 Like   17Comments
  • 115(69+46) only :disappointed:. 12h.
  • @Sabya1590 Same hi situation hai.. but now let's prepare .... 1h.

1h ago 12.7k CAT Quant CAT

Official Quant Thread for CAT 2014!!

This is the Official CAT 2014 Quantitative preparation group. Solve questions & discuss answers/solutions shortcuts &...

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QADI: 32C/41A = 87

VALR: 40C/47A = 113  

Total: 72C/88A = 200  

First ever CL double centuryy!! Yayyyeee  

Found the center to be quiet for the first time, maybe the reason for my score  But yeah it was surely the easiest CL Mock everrr!

  • 16 Likes   16Comments
  • and i thought there were only around 14 LR's in section 2.... 1h.
  16 Comments
jamesbond77
Sumit 92 @jamesbond77 50

and i thought there were only around 14 LR's in section 2 

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T.I.M.E. has changed the way the questions are presented to the candidate, the way u can navigate to the questions. I find it more user-friendly. Probably that's the way it is gonna be even in the main CAT exam. Hope so...

Whatsoever ye shall ask in prayer, believing ye shall receive it..:)

2h ago 21 CAT

PUNE STUDY CIRCLE CAT14

Puneities..! 6 months to CAT.. Lets begin with the group study !

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Anyone in magarpatta for cat prep ?

  • @frediey Yep!!!! I work in magarpatta..... 2h.
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Hello!Are people with workex preferred over freshers ?

  • 7Comments
  • @slhk fms give high weightage to cat score but to crack t.... 11h.
  • @slhk Yes people with work ex are preferred over freshers.... 2h.
  7 Comments
aseth1985
A S @aseth1985 443

@slhk fms give high weightage to cat score but to crack the final work exp is given an edge.....companies like consultancy/s, technology, financial services or investment bankers prefer work exp guys..however there are companies like banks, fmcg, retail etc who take freshers and if u get through fms ur sure gonna get placed well

princeankitsingh
Prince Ankit Singh @princeankitsingh 11

@slhk Yes people with work ex are preferred over freshers besides it goes unsaid that work ex is a prerequisite for MBA

2h ago 549 CAT

[OFFICIAL] IMS SIMCAT scores and Discussion for the entire 2014-15 season !!!

Dear Puys & Pirls, Use this thread for scores and discussion for all the IMS SIMCATs!! It will serve as a repository ...

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Puys who used to take Proc Sims in Take Home mode on the last day of the window.... Pl let me know the process (I m planning to take Sim 12 in that mode)... Do I have to book slot in that case ?

Pl guide 

  • 18Comments
  • @Sabya1590 bhai i gave SIMCAT 11 on the first day itself .... 3h.
  • @Sabya1590 yeh lo link :stuck out tongue: http://imsin.... 2h.
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1509:72+25=97 qa was too easy,still couldnt score much

1510:62+49=111 (okay typs)

3h ago 82 CAT Quant CAT

Quant Concepts thread for CAT 2014

Hey puys, As we all are geared up to prepare ALL NEW CAT 2014, let us refresh our quant concepts bit by bit. All we n...

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Circular Motion:

(Nitin Gupta- Alpha Numeric)



These types of problems deal with athletes running on a circular track and questions being asked about when, where and how often would two or more athletes cross each other.


Meeting for the First Time When running in opposite directions:

Consider two friends, A and B, who are separated by 1500 meters and they move towards each other at speeds of 40 m/s and 10 m/s. After how much time would they meet?This is a straight question on relative speed and the time taken to meet = 1500/(40+10) = 30 sec


When running in the same direction:

Consider a police traveling at 40 m/s chasing a thief traveling at 10 m/s.
If the distance between the police and thief when the chase starts is 1500 meters, find the time after which the police catches up with the thief.
Again, the solution should be known by now as 1500/(40-10) = 50sec


Thus time taken to meet = Track Length /Relative Speed

Frequency of meeting:


Say two athletes start running from a same point on a circular track and meet after t units of time. When they meet they are again together at a point (not necessarily the same point where they started but nevertheless they are together). And if they continue running in the direction they were running and at their respective speeds, then this instance can be thought of as a new beginning, two athlete starting to run from a same point. And thus, from this instant onwards, they would again meet after t units of time. And the reasoning could be again argued similarly at their 2nd meeting. So considering the 2nd meeting as a fresh start, they will again meet after t duration of time. Thus, the time after which they meet for the first time is also the frequency with which they keep meet if they continue running at their respective speeds and respective directions. 

If the first meeting takes place after t duration after start, the nth meeting will take place after n x t duration after start.

*Where would the first meeting take place?


Once the time is known after which two athletes, running on a circular track, meet, we can find the distance run individually by them (rather
by any one of them) and find the exact position on the track where the meeting takes place. Rather than measuring this distance in absolute terms, it is more beneficial to measure this distance in terms of the track length.

*Meeting for the First Time at Start :

The question of identifying after how much time would two or more athletes meet at the starting point is an application of LCM rather than a problem of Time Speed Distance. The key word here is meeting at the starting point. Please realize that this may not be the first time that they meet. The could have crossed each other (met) at some other point on the track but then that would not be counted as a meeting point for this question as it has not occurred at the starting point.

Consider two athletes, A and B running on a circular track and taking x and y units of time to complete one full circle.A would reach the starting point for the first time after x units and thereafter would be at the starting point after every x units. Similarly B would reach the starting point for the first time after y units and thereafter would be at the starting point after every y units.Thus, A and B would both be at the starting time after common multiple of x and y and the first time that this would occur would be the LCM of x and y.For these types of problems, it does not matter in which direction the two athletes are running. Even if both are running clockwise or if one is running clockwise and other anticlockwise, the time when they would be at the starting point would remain the same.

Another Important Approach: 'Relative' Distances or Rounds run
When running in opposite directions ............ they meet whenever together they have covered one full round ............ and hence at the nth meeting, together they would have covered n rounds.
This is easy to understand. Since both start from common point and run in opposite directions, at 1st meeting, if one runs f fraction of the track, the other has to run (1 - f ) fraction of the track so that he is at same point. Thus, sum of distances run = f + (1 - f ) i.e. 1 full round.
This is new beginning, and from now onwards, till 2nd meeting they would together again cover 1 full round i.e. they would together cover 2 rounds since start. And so on.
When running in same directions ......
...... they meet whenever the faster one has covered 1 round more than the slower one ............ and hence at the nth meeting, the faster one would have covered n rounds more than the slower one.
Consider both start from same point and run in same direction. Focus on the gap between them. The faster one will race ahead of the slower one and a gap will start emerging between them. As time passes the gap will start increasing.

Three or more people meeting
To find time when three or more people meet, find the time after which pairs of athletes meet, such that at least one athlete is common to all the pairs (say, A & B, A & C, A & D, ......). The respective pairs will keep meeting after any multiple of the time found. At the LCM of these durations of time, we are sure that A & B have met, that A and C have met, that A & D have met and so on. But the only way that A could have met all these people at the same instant is when all of them are together.

Position of the meeting points:


These types of questions do not deal with when or how often do the
athletes meet when they are running on a circular track. These questions pertain to the number of points and their placement on the circular track where the athletes can possibly meet.
When running in the opposite directions:

If the ratio of speeds of two athletes (in the most reducible form) is a : b, the number of distinct meeting points on the track would be would be a + b.

Position of the meeting points :

When running in the same direction:

If the ratio of speeds of two athletes (in the most reducible form) is a : b, the number of distinct meeting points on the track would be would be |a - b|.

1. Two men , Jain Abhishek & Sood Saransh ,walk round a circle 1200 metres in circumference. Jain walks at the rate 150 meters/miute , and sood walks @80 minutes per minute. if both start at the same time from the same point & walk in the same direction.

(a) when will they 1st be together again at starting point.

(b) when will they be together again

(c) no. of distinct meeting points.

A.

a) lcm (time taken by jain to complete 1 round,time taken by sood to complete 1 round) = lcm (1200/150,1200/80) = 120 min.

c) since ratio of speed is 15:8 ===> no. of distinct point = 15-8 = 7

b) from the previous 2 question we can say that they are meeting 7 times in 120 min==> 1st meeting will take after 120/7min( no need to use relative speed funda-- always work on ratio of speed)

In question 1-(d) find the distance travelled & time required by Sood Saransh & Jain Abhishek when they meet for 100th time.

(e) when they meet for 100th time what is the distance from the starting point to the point at which they will meet..in anticlockwise direction.

A.

d) ratio of speed = ratio of no. of rounds ===> no. of rounds covered by jain to sood = 15:8 ==> here there is agap of 7 but for first meeting there must be a gap of 1 round so distance covered by jain & sood when they meet for the first time = 15/7 & 8/7( in terms of rounds) so at 100th meeting distance covered is 15/7*100 & 8/7&*100 ( in terms of round 1 round =1200m) & time required = 120/7* 100.( avoid using relative speed work on ratio)

(e) since there are 7 distinct points : 100 = 7k+2; so 100th meeting point will coincide with 2nd meeting point & when they meet for 2nd time no. of rounds covered covered by sood = 8/7 *2 = 16/7=2 +2/7==> 2/7 clockwise or anticlockwise depending upon whether they started clockwise or anticlockwise respectively. CBD


Q. For opposite direction: 2. two men , Jain Abhishek & Sood Saransh ,walk round a circle 1200 metres in circumference. Jain walks at the rate 150 meters/minute , and sood walks @80 minutes per minute. if both start at the same time from the same point & walk in the opposite direction.

(a) when will they 1st be together again at starting point.

(b) when will they be together again

(c) no. of distinct meeting points.

(d) find the distance travelled & time required by Sood Saransh & Jain Abhishek when they meet for 100th time. (e) when they meet for 100th time what is the distance from the starting point to the point at which they will meet..in anticlockwise direction

2. a) lcm (time taken by jain to complete 1 round,time taken by sood to complete 1 round) = lcm (1200/150,1200/80) = 120 min.c) since ratio of speed is 15:8 ===> no. of distinct point = 15+8 = 23 b) from the previous 2 question we can say that they are meeting 23 times in 120 min==> 1st meeting will take after 120/23min( no need to use relative speed funda-- always work on ratio of speed) d) ratio of speed = ratio of no. of rounds ===> no. of rounds covered by jain to sood = 15:8 ==> for first meeting distance covered by jain & sood when they meet for the first time = 15/23 & 8/23( in terms of rounds) so at 100th meeting distance covered is 15/23*100 & 8/23&*100 ( in terms of round 1 round =1200m) & time required = 120/23* 100.( avoid using relative speed work on ratio) e) (e) since there are 23 distinct points : 100 = 23k+7; so 100th meeting point will coincide with 8th meeting point & when they meet for 12nd time no. of rounds covered covered by sood = 8/23 *8 = 64/23=2 +18/23==> 18/23 clockwise or anticlockwise depending upon whether they started clockwise or anticlockwise respectively

Q.Three athletes A, B and C are running on a
circular track of length 1200 meters with speeds 30 m/s, 50 m/s and 80 m/s. A is running clockwise and B and C are running anticlockwise.
3: Find the time after which A and B will meet for the first time and
the frequency (in seconds) after which they will keep meeting.
Also find the sum of the distance (in fraction of the track length)
run by them till their first meeting.

no. of meeting points for a & b = 3+5 = 8 ( as direction is opposite so at first meeting a & b will travel 3/8 & 5/8 ; at 2nd meeting 3/*2 & 5/8*2; at third meeting 3/8*3& 5/8*3 & so on.................( i hope that concept is clear now)

Q. Which of the following cannot be the ratio of speeds of two joggers running on a circular jogging track if while running they meet at a diametrically opposite point to the point from where both of them started?

(1) 3 : 5 (2) 1 : 3 (3) 1 : 5 (4) 2 : 5

5. Consider athletes A , B & C running at speeds of 150 m/s , 70 m/s &110 m/s respectively on a circular track of 1000 meters, A & B running clockwise and C anti-clockwise. If they keep running indefinitely, at how many distinct point on the circle would they meet? what is the distance covered by each when they meet for 100th time.

a:b = 15:7 so A&B will meet @ 8 points(as direction is same). b:c =7:11 so B&C will meet at 18 points ( as direction is opposite) so no. of distinct meeting points for all 3 = hcf(8,18) = 2, QED

since ac = 15:7:11 so at first meeting distance covered is 15/2,7/2&11/2 rounds ; at 2nd meeting 15/2 *2,7/2 *2&11/2*2 rounds respectively & so on.

6. In a circular track, there are two points P and Q which are diametrically opposite.C starts running clockwise with a speed of 4m/s from P. At the same time, from Q, A starts running clockwise with a speed of 3 m/s and B starts running anti clockwise with a speed of 5 m/s. If the length of the track is 300m, then after how much time will C be equidistant from A and B for the first 

6. B and C meets after 150/(4 + 5) = 50/3 seconds.

At this point distance between A and C is 150 + 50 - 200/3 = 400/3

So, suppose that from this moment on wards it take them t time to reach the situation when C is equidistant from A and B

After time t, distance between A and C will be 400/3 + 3t - 4t = 400/3 - t and distance between B and C will be 9t

9t = 400/3 - t
=> t = 40/3

So, after 50/3 + 40/3 = 30 seconds C will be equidistant from A and B for the first time

7. Three boys A, B and C start running at constant speeds from the same point P along the circumference of a circular track. The speed of A, B and C are in the ratio 5:1:1. A and B run clockwise while C runs in the anticlockwise direction. Each time A meets B or C on the track he gives them a card.What is the difference in the number of cards received by B and C if A distributes 33 cards in all?

ac= 5:1:1 ===> a&b meet at 4 distinct points ; a&c will meet at 6 distinct points. when a complete 5 round b& c will complete 1 round ==> a meets b 4times & a meets c 6times ( one cycle is completed. so at the end of 3 cycle a meets b 12 times & with c 18 times.now in his 16th round A wiil meet with c but not with b ( as a& b are travelling in same direction so a will be ahead of b) & in his 17th round he meet b & c once. so for b = 12+1 = 13 & for c = 18+2 = 20 ; so difference = 20-13=7 

 8. Seven children A, B, C, D, E, F and G started walking from the same point at the same time, with speeds in the ratio of 1 : 2 : 3 : 4 : 5 : 6 : 7 respectively and they are running around a circular park. Each of them was carry flags of different colours. Whenever two or more children meet then they place their respective flag at that point, however nobody places more than 1 flag at a same point. They arerunning in anti-clockwise direction. How many flags will be there in total, when there will be no scope of putting more flags?

9. Sarah and Neha start running simultaneously from the diametrically opposite ends of a circular track towards each other at 15km/h and 25km/h respectively. After every 10 minutes their speed reduces to half of their current speeds. If the length of thecircular track is 1500 m, how many times will Sarah and Neha meet on the track? (1) 6 (2) 9 (3) 11 (4) 7 (5) 8

Total distance Shrikant can cover = 10/60*(15 + 15/2 + 15/4 + ...) = 5 km Total distance Sachin can cover = 10/60*(25 + 25/2 + 25/4 + ...) = 25/3 km First time they cover 750 m and subsequently they cover a distance of 1500 m to meet. The total distance they cover together is 40/3 km. Number of meetings possible is 1 + (40000/3 - 750)/1500 = 9.4 => choice (B) is the right answer


  • 3 Likes  
  • :b: Is taken : b :. 3h.
  • Please bear with the change due to wesite. 3h.

Tryst with destiny!

4h ago 103 CAT

The PaGaLGuY Dream Team 2014

*THE PaGaLGUY Dream Team !!!!!* Most of us joined this place with *one dream*, the dream that we live every moment. W...

4h ago 639 CAT

Logical Reasoning

The question is followed by two statements X and Y. Answer using the following instructions: Choose 1 if the question...

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In a dance academy, there are 60 students learning the bharatnatyam dance, 50 students learning the classical dance and 65 students learning the disco dance. 18 students are learning both the bharatnatyam and the classical dance. 20 students are learning both the disco and the bharatnatyam dance. 27 students are learning both the disco and the classical dance. All the students are learning at least one of the three dances. What is the maximum number of students that could be learning all the three dances?

(a) 15 
(b) 18 
(c) 20 
(d) 22

  • 6Comments
  • 18. 4h.
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I have mailed the scan copy of the signed application letter for cancellation of my admission,but didin't received any mail from the admission department..please help me
  • You have to write them a letter with all the details.. pl.... 30 May.
  • I am facing the same issue... Plz help!!!. 4h.
sirsa_m
Siirsa Majumder @sirsa_m 71
You have to write them a letter with all the details.. please be patient, you will get your money...

2d ago 33 CAT

Testfunda Mocks 2014

Hey everyone! The 2014-15 season unfolds with the TF mocks. iCAT01 and 02 are out now! Please post your TF mock score...

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any thread fr inmats?

5h ago 100 CAT

CAT 14 - SYSTEMATIC

CAT is not just about being awesome in any one of the sections(QUANTS/DATA INTERPRETATION/VERBAL/LOGICAL REASONING) b...

5h ago 545 CAT MICA, Ahmedabad

MICA Ahmedabad: Official Discussion Forum (MICAT - 2015)

Hello Everyone, It gives us immense pleasure to kick-start another season of admissions for the 2 year PGDM (C) progr...

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as far as I have observed, a 90%ile and above in cat/xat plays a significant role in getting selected at MICA, if  u say that there is no weightage given to these exams then why is it so that people I saw and had an interaction with, wrote shit in the paper of creative writing in MICAT 2014, and they were selected

  • 7Comments
  • @nidhitoke86 the percentile in CAT in no factor in select.... 8h.
  • getting a 20 %ile or 90 %ile in cat is the same for mica..... 5h.
  7 Comments
Fizz_Sid
Faizan Siddiqui @Fizz_Sid 4.4 k

@nidhitoke86 the percentile in CAT in no factor in selections for MICA. I would still suggest you to give your best across all the exams that you appear. Good luck with the preps

MANC-LONDON
waka waka @MANC-LONDON 562

getting a 20 %ile or 90 %ile in cat is the same for mica.. no seperate weightage... 

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I made the mistake of putting the wrong DoB and made the payment as well. I talked to the executive (3 times to confirm) and I was told that it's totally okay. Just have to carry the Original Document to prove.

Just call at 18002100151 to let them know.

  • 1 Like   16Comments
  • @coolShades Same here - 8 feb changed to 2 august - someh.... 5h.
  16 Comments
yyxx
vasu hooda @yyxx

@coolShades Same here - 8 feb changed to 2 august - somehow day and month are automatically swapped. And it is same for my friend - 25 Dec(25-12)  changed to 12 jan(25 - 12+12+1  - 1   |   So same thing day month swapped).