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  • JEE Main Cutoff for Top IITs

    JEE which stands for Joint Entrance Examination is a competitive exam which can get you into top Engineering colleges in India. This exam is targeted towards the candidates who aspire to build a career through engineering and wish to get into one of the top colleges for engineering in India which are IITs and NITs. It is mandatory to clear JEE exams if one wishes to get into one of the above-mentioned colleges. Upon clearing this exam, you will be able to pave your ways into IIT, NIT or any other government-funded engineering colleges.

    History

    JEE was previously called AIEEE or in other words, All India Engineering Entrance Exam. This examination has been, from initial days, composed by the National Testing Agency (NTA) in India and has been introduced in the year 2002. This examination came into existence to help students compete in national level for entrance into various under graduation as well as design courses based on the AIEEE scores. There are a total of 31 National Institute of Technology (NIT) and 23 Indian Institute of Technology (IIT) which accept the score of JEE and provide admission based on the same.

    Number of papers

    The numbers of papers which follow in the examination are TWO. The first paper is for the candidates seeking admission in B.E. or B.Tech. The second paper is however for the candidate who wishes to be admitted in B.Arch courses. There are no terms and conditions related to being able to attempt only one paper. You can either write one paper based on the course you seek or you may write both the papers.

    The form of writing the examination is OMR based as well as PC based mode. However, since this year i.e. 2019, there are no alternatives provided anymore and it is solely PC based test also called online mode. You will have to visit the centres which would be provided to you, which have the certification to take up the exam. For the detailed information on the syllabus for JEE.

    Exam pattern

    There are various sections provided in the paper which have to be answered by the candidate and are going to be in the form of multiple choice questions. Through the process of Normalisation, JEE evaluates the final score from all the provided sections and contrasts competitive scores crosswise. This pattern is just like any other pattern which is generally followed by entrance exams of every other field. To sort out the deserving candidates, NTA will do so by deriving a percentile from the hereby normalisation process. This normalisation is a vast process and can be understood well by hitting various search engines.

    Percentile scores are derived from the overall performance of each of the candidate who happens to appear and answer the exam. The final percentile hence derived from the entire performance is set to range somewhere from 100 to 0 for every session. It is essential to note that there is even negative marking for the wrong questions you attempt.

    Stay connected with fellow students on PaGaLGuY for JEE Main 2019 Exam Discussion

    Cut off

    There is a JEE Main cut off which states the required score which has to be scored by a candidate which would help him/her qualify for the NITs. This score also acts as a qualifying criterion to be able to answer the JEE Advance exam which would grant you admission in IITs. Every year the number of students appearing the examination ranges somewhere between 14-15 lakhs while only a number of 2,24,000 students are finally selected. Below mentioned are the present cutoffs.

    Category and cut off

    • General 80-85
    • OBC 48-53
    • SC 31-36
    • ST 27-32

    The cut off marks for JEE mains vary because of a number of factors such as: –

    • Number of applications received
    • Number of questions asked in the paper
    • The difficulty level of the exam
    • Performance of the candidates
    • Previous years’ cut off trends

    The JEE main cut off for the year 2018 was: –

    • General 74
    • OBC 45
    • SC 29
    • ST 24

    Other information

    This year the first JEE main Exam was held on 8th, 9th and 10th of January and was directed by NTA. The examination on all the days was held as two shifts over 258 urban areas nationwide and abroad. The scores for the same were released on 19th January 2019, which was, to be precise 12 days ahead of the scheduled date of the results announcement.

    If you wish to enroll for a second try, you may enroll for it again and, dates for the same will be in the month of April. Though dates for the application process is out. The application process for the next JEE (Main) examination will start by 8th February 2019 and will last until 7th March 2019 (1 month).

    2 comments
    1. @username12345
      This is not how it works.Galat hai.
      April 2019
    2. @infomatica001
      The minimum marks required for admission will be known as JEE Advanced 2019 cutoff for IITs. The cutoff of JEE Advanced 2019 for IITs carries the opening and closing rank within which candidates need to score to get admission to desire institute and branch. The opening ranks in the cutoff of JEE Advanced will indicate the score at which admissions will start, while closing ranks will the score at which admission ends. JEE Advanced 2019 cutoff for IITs will be released category, institute, and branch-wise. Candidates must note that they will have to score marks more than or equivalent to the cutoff of JEE Advanced 2019 for IITs, in order to get admission. Also, JEE Advanced cutoff for IITs will vary from one institute to another and one B.Tech programme to another due to certain influential factors that will be considered while preparing it. For more information, visit https://infomaticaacademy.com/
      last month

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