Official Quant thread for CAT 2013

@scrabbler said:
That is for the second question. He asked about my reasoning for the first question...since we had different answers for that.Second one we both had agreed on 3/7 already!regardsscrabbler
Ahh...sorry my bad...
@scrabbler 100%ile laaye ho CAT ya QA mein...???
Great work..
@ScareCrow28 said:
Haha.. Really sir, you have become an ID KA CHAAND! Just love watching (rather reading) you doing maths. Is baar b 100%ile laaye ho na??
Of course of course. Why not? 😛 Aur kuch expectations?

regards
scrabbler

@saurav205 said:
@scrabbler 100%ile laaye ho CAT ya QA mein...???Great work..
@scrabbler said:
Of course of course. Why not? Aur kuch expectations?regardsscrabbler
Aye nahi b honge to kya hua sir ?? 😛 Ajayenge..Afterall you are too good in maths! And let's not spam anymore I'm feeling guilty of starting the sequence 😉
The average score of 42 candidates in CAT is 110. In the three rankers' scores are removed the averag drops by 2. If the paper is out of 180 marks, and the second-highest score is less than 131, then the highest score should be what value, is all scores are integers???
A cricketer had played a certain number of innings during the year. He finds that if he had not played the last game when he made 20 runs, or if he had played an extra innings and made 56 runs, he would have increased his average by 1. What was his average?
The average age of 5 men today is the same as that it was 7 years ago, with one man being replaced bu much a younger man. What is the difference between the ages of the man replaced and the new man???
@jashholmes said:
The average score of 42 candidates in CAT is 110. In the three rankers' scores are removed the averag drops by 2. If the paper is out of 180 marks, and the second-highest score is less than 131, then the highest score should be what value, is all scores are integers???
42*110 - 1st - 2nd - 3rd = 39*108
1st + 2nd + 3rd = 42*110 - 39*108
1st + 2nd + 3rd = 408
highest score = 408 - 2*130 = 148 ?
@mailtoankit Yeah!!!
@mailtoankit Y did u chose 2nd highest as 130!!!
If second higest is 130 thn 3rd highest should evn b less thn tht???
@jashholmes said:
A cricketer had played a certain number of innings during the year. He finds that if he had not played the last game when he made 20 runs, or if he had played an extra innings and made 56 runs, he would have increased his average by 1. What was his average?
37 ?

nx - 20 = (n - 1)(x + 1)....i
nx + 56 = (n + 1)(x + 1)...ii

solve these 2 eqns
n = 18 , x = 37
so average = 37 ??....calculation mistake..@jashholmes
@mailtoankit No!!!
@jashholmes said:
The average age of 5 men today is the same as that it was 7 years ago, with one man being replaced bu much a younger man. What is the difference between the ages of the man replaced and the new man???
If average age 7 years ago was A by now it should have been A+7.But it is still A.So average age decreased by 7.As a older man was replaced by a younger man diff should be 7*5=35
@jashholmes said:
The average score of 42 candidates in CAT is 110. In the three rankers' scores are removed the averag drops by 2. If the paper is out of 180 marks, and the second-highest score is less than 131, then the highest score should be what value, is all scores are integers???
149..??

Consider 2nd highest as 130 and 3rd as 129..! (If everyone has got distinct marks )

else,

148.!

PS: Tag me with OA

@jashholmes said:
A cricketer had played a certain number of innings during the year. He finds that if he had not played the last game when he made 20 runs, or if he had played an extra innings and made 56 runs, he would have increased his average by 1. What was his average?
37..?
@sbharadwaj Thre is nothing mention about distinct marks!!!
I gt 149 bt it's nt correct!!!
The correct answer is 148!!!
@sbharadwaj Yeah...How???

@jashholmes said:
A cricketer had played a certain number of innings during the year. He finds that if he had not played the last game when he made 20 runs, or if he had played an extra innings and made 56 runs, he would have increased his average by 1. What was his average?
Suppose say A=average of n games.With n-1 games average increases by 1 with a score of 20.
So,20=A-(n-1)*1;
Next with n+1 games average increases by 1 with a score of 56.
So,56=A+1 +n*1

Solving A=37

Edited---
@sbharadwaj said:
37..?
37 is correct
@mailtoankit said:
42*110 - 1st - 2nd - 3rd = 39*1081st + 2nd + 3rd = 42*110 - 39*1081st + 2nd + 3rd = 408highest score = 408 - 2*130 = 148 ?
why did you choose 130 ?