Hello all, As the CAT 2K12 come to a close, starting this thread for all the discussions of quant for CAT 2013. Here is the link for old thread of quant http://www.pagalguy.com/forums/quantitative-ability-and-di/official-quant-thread-c-t…
Hello all,
As the CAT 2K12 come to a close, starting this thread for all the discussions of quant for CAT 2013.
Here is the link for old thread of quant
http://www.pagalguy.com/forums/quantitative-ability-and-di/official-quant-thread-c-t-83384/p-3577256/r-4005959?page=1
Also wishing everyone(who wrote CAT 2K12) to have their convert in 2K12 itself and just guide the fresh aspirants through out this forum 😃 😃 
P.S : too formal , too emotional but chalta hai 😛 😛
PPS(Just Arrived) : Please do not post any MOCK CAT(AIMCAT SIMCAT CL TESTFUNDA JO bhi ho) QUESTIONS UNTIL THE TEST WINDOW FOR THAT TEST HAS FINISHED .
Starting off with an easy question
The numbers x and y are three-digit positive integers, and x + y is a four-digit integer. The tens digit of x equals 7 and the tens digit of y equals 5. If x
@chandrakant.k said:Starting off with an easy questionThe numbers x and y are three-digit positive integers, and x + y is a four-digit integer. The tens digit of x equals 7 and the tens digit of y equals 5. If x
Let x = a7b and y = c5d
Given: x a (a+c) > 9
Take the minimum case i.e. when a+c =10
Also a can only be 4 and c can take value only 6, to satisfy x c > 5
=> The third statement is partially true. Since the value of c has to be greater than 5 but cannot be equal to 5
Given: x a (a+c) > 9
Take the minimum case i.e. when a+c =10
Also a can only be 4 and c can take value only 6, to satisfy x c > 5
=> The third statement is partially true. Since the value of c has to be greater than 5 but cannot be equal to 5
x= abc & y= def
x = a7c & y= b5f
x > y and x+y = wxyz.
As the unit digit of x + y is greater than the units digit of either x or y. It can carryover one digit. False
The tens digit of x + y equals 2. It can be 2 or 3. False
The hundreds digit of y is at least 5.
a+b+1 >= 10 =>a >b so a at least 5. True.
x = a7c & y= b5f
x > y and x+y = wxyz.
As the unit digit of x + y is greater than the units digit of either x or y. It can carryover one digit. False
The tens digit of x + y equals 2. It can be 2 or 3. False
The hundreds digit of y is at least 5.
a+b+1 >= 10 =>a >b so a at least 5. True.
@chandrakant.k said:Starting off with an easy questionThe numbers x and y are three-digit positive integers, and x + y is a four-digit integer. The tens digit of x equals 7 and the tens digit of y equals 5. If x
@mbajamesbond said:Let x = a7b and y = c5dGiven: x a (a+c) > 9Take the minimum case i.e. when a+c =10Also a can only be 4 and c can take value only 6, to satisfy x c > 5=> The third statement is partially true. Since the value of c has to be greater than 5 but cannot be equal to 5
bhai but in C it is mentioned that C has to be at least 5.. which means it can be greater than 5 also.. SO c has to be true isn't it??
@chandrakant.k said:Starting off with an easy questionThe numbers x and y are three-digit positive integers, and x + y is a four-digit integer. The tens digit of x equals 7 and the tens digit of y equals 5. If x
I. Nothing is mentioned about unit digits. So, this statement is not always correct!!
II. This will be correct only if sum of unit digits of x and y is less than 10. So, this is not always correct!!
III. Its always correct!!
abc + def > 1000
and abc => 2*def > 1000
=> def > 500
Hence, hundred's digit of y will be atleast 5.
II. This will be correct only if sum of unit digits of x and y is less than 10. So, this is not always correct!!
III. Its always correct!!
abc + def > 1000
and abc => 2*def > 1000
=> def > 500
Hence, hundred's digit of y will be atleast 5.
Courtesy Chill Saar !! :)
P.S. Please keep this Quant Thread Clean. What I mean is stick to Quant Questions only with less of Bakar. I know we need to interact also while solving because that makes it fun and interesting but then don't reply with posts containing ONLY Bakar Stuff or something on those lines. If you want to talk to somebody in a light way, add it after your post in which you've solved any question or posted a question. That would keep the thread sticking to its purpose and won't add posts or comments including no knowledgeable stuff - Just the number of pages increase because of that and thread becomes long unnecessarily. Rather aisa karne se questions bhi rahenge and it won't become a boring journey for you all too. Just a request from my side. :)
@chandrakant.k said:bhai but in C it is mentioned that C has to be at least 5.. which means it can be greater than 5 also.. SO c has to be true isn't it??
Partially true as c cant be equal to 5
how much percentile do i need in order to get a call from any of the iims????
@jhag said:how much percentile do i need in order to get a call from any of the iims????
Please post your question here http://www.pagalguy.com/discussions/2012-which-b-schools-should-you-apply-to-25083927/3594168 And delete your post on this thread.
@mbajamesbond said:Partially true as c cant be equal to 5
take ths for example.. 472+559 = 1031 all conditions are statisified...
A mixture comprises two chemicals A and B. The price of A is Rs. 100/- per litre and that of B is Rs.
200/- per litre. We can spend a maximum of Rs. 600/- for making the mixture. The densities of A and
B are 10 kg/litre and 12 kg/litre respectively. The mixture must contain each of the chemicals to the
extent of at least 25% by weight. The maximum weight of the mixture that can be made is closest
to:
a. 60 kg b. 51 kg c. 54 kg d. 48 kg
200/- per litre. We can spend a maximum of Rs. 600/- for making the mixture. The densities of A and
B are 10 kg/litre and 12 kg/litre respectively. The mixture must contain each of the chemicals to the
extent of at least 25% by weight. The maximum weight of the mixture that can be made is closest
to:
a. 60 kg b. 51 kg c. 54 kg d. 48 kg
Bhai itni jaldi kar di?
Chalo is baar mai bhi aata hu
@chandrakant.k said:Starting off with an easy questionThe numbers x and y are three-digit positive integers, and x + y is a four-digit integer. The tens digit of x equals 7 and the tens digit of y equals 5. If x
I. Not True. We can take any case and prove the same
II. NOt always true. Depends on Carryover.
III. Otherwise Four digit wala nahi ho payega..ek ko to 500 se jyada hona hi hai!
II. NOt always true. Depends on Carryover.
III. Otherwise Four digit wala nahi ho payega..ek ko to 500 se jyada hona hi hai!
@chandrakant.k said:take ths for example.. 472+559 = 1031 all conditions are statisified... A mixture comprises two chemicals A and B. The price of A is Rs. 100/- per litre and that of B is Rs.200/- per litre. We can spend a maximum of Rs. 600/- for making the mixture. The densities of A andB are 10 kg/litre and 12 kg/litre respectively. The mixture must contain each of the chemicals to theextent of at least 25% by weight. The maximum weight of the mixture that can be made is closestto:a. 60 kg b. 51 kg c. 54 kg d. 48 kg
54?
@chandrakant.k said:take ths for example.. 472+559 = 1031 all conditions are statisified... A mixture comprises two chemicals A and B. The price of A is Rs. 100/- per litre and that of B is Rs.200/- per litre. We can spend a maximum of Rs. 600/- for making the mixture. The densities of A andB are 10 kg/litre and 12 kg/litre respectively. The mixture must contain each of the chemicals to theextent of at least 25% by weight. The maximum weight of the mixture that can be made is closestto:a. 60 kg b. 51 kg c. 54 kg d. 48 kg
Thoda upar neeche kar ke..54 hona chahiye
@chandrakant.k said:take ths for example.. 472+559 = 1031 all conditions are statisified... A mixture comprises two chemicals A and B. The price of A is Rs. 100/- per litre and that of B is Rs.200/- per litre. We can spend a maximum of Rs. 600/- for making the mixture. The densities of A andB are 10 kg/litre and 12 kg/litre respectively. The mixture must contain each of the chemicals to theextent of at least 25% by weight. The maximum weight of the mixture that can be made is closestto:a. 60 kg b. 51 kg c. 54 kg d. 48 kg
Equation will be -
(3x/4)*100*(1/10) +(x/4)*200*1/12 = 600
(3x/4)*100*(1/10) +(x/4)*200*1/12 = 600
Solving, x = 51 kg (Approx.) :splat:
@chandrakant.k said:take ths for example.. 472+559 = 1031 all conditions are statisified... A mixture comprises two chemicals A and B. The price of A is Rs. 100/- per litre and that of B is Rs.200/- per litre. We can spend a maximum of Rs. 600/- for making the mixture. The densities of A andB are 10 kg/litre and 12 kg/litre respectively. The mixture must contain each of the chemicals to theextent of at least 25% by weight. The maximum weight of the mixture that can be made is closestto:a. 60 kg b. 51 kg c. 54 kg d. 48 kg
Answer kya hai?
On buying a camera, the shopkeeper gives three rolls of film free. On buying a camera and six rolls of film, the shopkeeper gives additional four rolls of film free. If the equivalent discount is the same in both cases, then how many rolls will be equal in value to a camera?
12, 15, 18, 24
@[103935:chandrakant.k] : Thanks for starting the thread! 😃 :D
@ All: __/\__
@krum said:54?
@billuisback said:Answer kya hai?
51 hai...
@Estallar12 @vijay_chandola : 18??? used options 😛 😛
@vijay_chandola said:On buying a camera, the shopkeeper gives three rolls of film free. On buying a cameraand six rolls of film, the shopkeeper gives additional four rolls of film free. If the equivalent discount is the same in both cases, then how many rolls will be equal in value to a camera? 12, 15 18 24@chandrakant.k : Thanks for starting the thread! @ All: __/\__
x*z/100=3y
(x+6y)*z/100=4y
=>(x+6y)/x=4/3
=>3x+18y=4x
=>x=18y
18
(x+6y)*z/100=4y
=>(x+6y)/x=4/3
=>3x+18y=4x
=>x=18y
18