@chandrakant.k
yar ur post #18112 is it correct?
@vbhvgupta said:now we have 3 ans267,265,266
:nono:
I'll tell you how.
1000, not allowed, so upper limit=999
div by 2= 499, by 3= 333, by 5= 199
div by 6=166, div by 10 = 99, div by 15= 66
div by 30 =33.
numbers div by 2 or 3 or 5=499+333+199-166-99-66+33=733
so not div= 1000-733=267
Wait it is 267, sorry :splat:
@cynara said:I'll tell you how.1000, not allowed, so upper limit=999div by 2= 499, by 3= 333, by 5= 199div by 6=166, div by 10 = 99, div by 15= 66div by 30 =33.numbers div by 2 or 3 or 5=499+333+199-166-99-66+33=733so not div= 1000-733=267Wait it is 267, sorry
y 1000.....it should be 999 - 733 = 266
@mailtoankit said:y 1000.....it should be 999 - 733 = 266
achcha haan. You're right. Forgot again :banghead:
@vbhvgupta said:@anytomdickandhary @chandrakant.k
Q1 how to find the last two non zero numbers of a factorial
Q2 How many numbers between 1 to 1000 are not divisible by 2,3 or 5?
2) Numbers divisble by 2 = 499
numbers divisble by 3 = 333
numbers divisble by 5 = 199
now we have considered some numbers twice
for 2 and 3 = 166
for 2 and 5 = 99
for 3 and 5 = 66
for 2 3 and 5 = 33
so 499+333+199-(166+99+66)+33
= 733
999-733 = 266?
@vbhvgupta said:@chandrakant.k
yar ur post #18112 is it correct?
nope. it has some restriction as pointed out der. there is one more method i will update it by EOD and tag you. right now in office
In a locality there are ten houses in a row. On a particular night a thief planned to steal from three houses of the locality. In how many ways can he plan such that no two of them are adjacent to each other. ans
120
56
73
none
120
56
73
none
pls post the approach
A hexagon of maximum area is inscribed in a equilateral triangle .What is the ratio of the area of hexagon to the ratio of equilateral triangle.
1)1:2
2)1:4
3)1:3
4)none
Plz post the approach
1)1:2
2)1:4
3)1:3
4)none
Plz post the approach
how many 6-digit numbers contain exactly 4 different digits?
Consider the houses a x x x x x x x x x x in a row.
Now consider he chooses any of the houses which i will indicate by '+' signs.
x + x x + x x x + x (Selected houses are replaced by '+')
Formulating same as Permutation,
A+B+C+D = 7 [Not 10 excluding the 3 selected houses]
Now A and D can be zero i.e. whole numbers.
But B and C must be at least 1 i.e. natural numbers.
Now the equation will be a + b + c + d = 5 and number of solutions will be C(8,3) = 8*7*6/1*2*3 = 8*7 = 56
@abhishekhenry
Now consider he chooses any of the houses which i will indicate by '+' signs.
x + x x + x x x + x (Selected houses are replaced by '+')
Formulating same as Permutation,
A+B+C+D = 7 [Not 10 excluding the 3 selected houses]
Now A and D can be zero i.e. whole numbers.
But B and C must be at least 1 i.e. natural numbers.
Now the equation will be a + b + c + d = 5 and number of solutions will be C(8,3) = 8*7*6/1*2*3 = 8*7 = 56
@abhishekhenry
@abhishekhenry said:A hexagon of maximum area is inscribed in a equilateral triangle .What is the ratio of the area of hexagon to the ratio of equilateral triangle.1)1:22)1:43)1:34)none Plz post the approach
none??
Need help in solving this question...
Q - Find the 44th digit from the left
(1111....... 72 times)^2
Please provide explanation
@abhishekhenry said:In a locality there are ten houses in a row. On a particular night a thief planned to steal from three houses of the locality. In how many ways can he plan such that no two of them are adjacent to each other. ans
120
56
73
nonepls post the approach
letx represent the 3 houses
_x_x_x_
a+b+c+d = 7
here b and c >1
so a+b'+c'+d = 5
so 8C3 = 56
@Kvothe. said:Need help in solving this question...Q - Find the 44th digit from the left (1111....... 72 times)^2Please provide explanation
2??
@abhishekhenry said:In a locality there are ten houses in a row. On a particular night a thief planned to steal from three houses of the locality. In how many ways can he plan such that no two of them are adjacent to each other. ans 1205673none pls post the approach
8c3 = 56...
@abhishekhenry said:In a locality there are ten houses in a row. On a particular night a thief planned to steal from three houses of the locality. In how many ways can he plan such that no two of them are adjacent to each other. ans
120
56
73
nonepls post the approach
Take 10 - 3 = 7 houses fixed.
a X a X a X a X a X a X a X a : X represents 7 houses fixed. a represents the houses where he's going to perform theft.
So, 8C3 = 56 is the answer.
PS: Tag me with OA
Find the number of ways of distributing 15 balls in three boxes in such a way that each box contains at least 1 ball and also the number of balls in each box are unequal ?
ans is 72..approach plz
ans is 72..approach plz
@Kvothe. said:Need help in solving this question...Q - Find the 44th digit from the left(1111....... 72 times)^2
Please provide explanation
@ani4588
1^2 = 1
11^2 = 121
111^2 = 12321
1111^2 = 1234321
So, if you observe the pattern,
(1111...72times) ^2 goes like 1234567890123...
So 44th digit will be 4 I guess.. Not sure though.
Please do tag me when you provide the OA.
@ani4588 said:
2??
method???
@sbharadwaj said:@ani45881^2 = 111^2 = 121111^2 = 123211111^2 = 1234321So, if you observe the pattern,(1111...72times) ^2 goes like 1234567890123...So 44th digit will be 4 I guess.. Not sure though.Please do tag me when you provide the OA.
no this logic fails beyon some point
when there are 11..11times
the number would be
12345679012321....
note 8 is missing
also later pattern is different
@vbhvgupta said:how many 6-digit numbers contain exactly 4 different digits?
for first position the number can be filled in 9 ways
2nd position canbe filled in 10 ways
3rd in 10
4th in 10 ways
now 4th and 6th can be selected in 4C2 = 6 ways
now total numbers = 9*10*10*10*6*6 = 3240000???