Official Quant thread for CAT 2013

MBA CAT 2024
18026
@chandrakant.k sorry even i commited the same mistake...
18027
@CrookDinu said:
Find the number of ways of distributing 15 balls in three boxes in such a way that each box contains at least 1 ball and also the number of balls in each box are unequal ?

ans is 72..approach plz
1,2,12
1,3,11
1,4,10
1,5,9
1,6,8
2,3,10
2,4,9
2,5,8
2,6,7
3,4,8
3,5,7
4,5,6 are the ways.. Each in 6 ways. Hence, 72.
18028
@CrookDinu said:
Find the number of ways of distributing 15 balls in three boxes in such a way that each box contains at least 1 ball and also the number of balls in each box are unequal ?

ans is 72..approach plz
cards identical or different??
if identical then it is easy
if non identical then govinda govinda 😁 :D
ok since you have given answer as 72 it has to be identical
method :
a+b+c = 15
14C2 = 91
in this same cases are also considered
1) 1 1 13 - 3cases
2) 2 2 11 - 3cases
3) 3 3 9 - 3cases
4) 4 4 7 - 3
5) 5 5 5 -1
6) 6 6 3 - 3
7) 7 7 1 - 3
total such cases = 3*6 +1 = 19
so 91-19 = 72 😁 😁
18029
@chandrakant.k said:
for first position the number can be filled in 9 ways2nd position canbe filled in 10 ways3rd in 10 4th in 10 waysnow 4th and 6th can be selected in 4C2 = 6 waysnow total numbers = 9*10*10*10*6*6 = 3240000???
OA is 294840
18030
@anytomdickandhary said:
the digits he has are 0,1,4,6,8,9 (i.e 6 digits) so the counting would be in a base of sixin this base of 6, first digit is 0, second digit =1, third digit=4, fourth digit = 6, fifth digit=8 and sixth digit =9value of 100 when converted in base of 6 = 244so replacing the third digit and 5th digit from the above list we get 488.ATDH.

Maine bhi yehi kiya tha, base 6 waala logic 😃 Could not express it properly!

regards
scrabbler
18031
@chandrakant.k said:
for first position the number can be filled in 9 ways2nd position canbe filled in 10 ways3rd in 10 4th in 10 waysnow 4th and 6th can be selected in 4C2 = 6 waysnow total numbers = 9*10*10*10*6*6 = 3240000???
you are forgetting the case when the no starts with a 0
18032
@CrookDinu said:
Find the number of ways of distributing 15 balls in three boxes in such a way that each box contains at least 1 ball and also the number of balls in each box are unequal ?ans is 72..approach plz
bhai balls identical hai?? i mean if ans is 72 toh ofcrs hai...

a+b+c = 15
a'+b'+c' = 12
14c2 = 91 cases
but this also includes similar wala case...
A...B...C
1...1...13 - 3!/2! = 3
2...2...11 - 3
3...3...9 - 3
4...4...7 - 3
5..5....5 - 1
6...6...3 - 3
7...7...1 - 3
total = 19
hence, our answer = 91 - 19 = 72...
18033
@vbhvgupta said:
OA is 294840
YAr u have to rule out 0 as u have consider that too.
18034
http://education.oneindia.in/news/2013/02/04/iim-indore-to-conduct-cat-2013-entrance-exam-003902.html


18035
@SBRPhoenix said:
CAT 2013 is expected to be more tougher this year as per the one of the IIM directors.
18036
@Logrhythm said:
CAT 2013 is expected to be more tougher this year as per the one of the IIM directors.
I just highlighted this part, but the sad thing is ----The post submission got hanged....

The IIM people dont want to leak this nes in PG.....
18037
@Kvothe. said:
Need help in solving this question...

Q - Find the 44th digit from the left

(1111....... 72 times)^2

Please provide explanation
is it 6??
18038

A container is filled up to half of its total volume with liquids L1 and L2 in the ratio 3:7 .L1 and L2 evaporate at the rate of 25litre/hr and 20litre/hr respectively.. after an hour the container is filled completely by adding another mixture which contains L1 and L2 in the ratio 2:3 the final ratio of L1 and L2 in the container becomes 1:2.. what is the volume of the container (in litres) ??

18039
@pavimai said:
A container is filled up to half of its total volume with liquids L1 and L2 in the ratio 3:7 .L1 and L2 evaporate at the rate of 25litre/hr and 20litre/hr respectively.. after an hour the container is filled completely by adding another mixture which contains L1 and L2 in the ratio 2:3 the final ratio of L1 and L2 in the container becomes 1:2.. what is the volume of the container (in litres) ??
140??
18040
@ani4588 said:
140??
no..oa is 420 litres

18041
@pavimai said:
A container is filled up to half of its total volume with liquids L1 and L2 in the ratio 3:7 .L1 and L2 evaporate at the rate of 25litre/hr and 20litre/hr respectively.. after an hour the container is filled completely by adding another mixture which contains L1 and L2 in the ratio 2:3 the final ratio of L1 and L2 in the container becomes 1:2.. what is the volume of the container (in litres) ??
420 ltr
18042
@ani4588 yeah sorry its 420 litres.. let initially be 20x
half 10x(full) and 10x (empty)
Initially
L1=3x
L2=7x
after 1 hour
L1=3x-25
L2=7x-20

now the container is filled up .. so 20x-(10x-45)=10x+45 (this is the amount that is filled up)
and L1:L2=2/3
L1=(10x+45)*2 /5= 4x+18
L2=(10x+45)*3/ 5 = 6x+27

now L1:L2(Finally is ) = 1:2
L1:L2= (3x+25 + 4x+18 ) :(7x-20 +6x+27 )= 1:2
on solving x=21
Hence container volume is 20*21=420

18043

initially 3x+7x=V/2


3x-25+2y/7x-20+3y=1/2 this equation gives y-x=30


and also 3x-25+2y+7x-20-3y=V

V=20x from initial equation

so y-2x=9

now solve both u will get x=21

V=20x
V=420

18044
@pavimai
yeah sorry its 420 litres.. let initially be 20xhalf 10x(full) and 10x (empty)
Initially
L1=3x
L2=7x
after 1 hour
L1=3x-25
L2=7x-20
now the container is filled up .. so 20x-(10x-45)=10x+45 (this is the amount that is filled up)
and L1:L2=2/3
L1=(10x+45)*2 /5= 4x+18
L2=(10x+45)*3/ 5 = 6x+27
now L1:L2(Finally is ) = 1:2
L1:L2= (3x+25 + 4x+18 ) 7x-20 +6x+27 )= 1:2
on solving x=21
Hence container volume is 20*21=420
18045
@pavimai said:
A container is filled up to half of its total volume with liquids L1 and L2 in the ratio 3:7 .L1 and L2 evaporate at the rate of 25litre/hr and 20litre/hr respectively.. after an hour the container is filled completely by adding another mixture which contains L1 and L2 in the ratio 2:3 the final ratio of L1 and L2 in the container becomes 1:2.. what is the volume of the container (in litres) ??
Let volume of container be 2V.
=>Quantity of L1 and L2 initially
L1=3V/10
L2=7V/10

=>After an hour 25 lit of L1 and 20 lit of L2 evaporate
So quantity remaining
L1=3V/10 -25
L2=7V/10 -20
Now the volume empty V+45.

=>Quantity added of L1 and L2
L1=2/5(V+45)
L2=3/5(V+45)

=>Total of liquid L1 and L2.
L1=3V/10-25+2/5(V+45)=7V/10 -7
L2=7V/10-20+3/5(V+45)=13V/10+7
=>Solving L1:L1=1:2
V=210
Volume of container 2V=420 lit