@bs0409 said:OA-13340.14141414 is a base 12 number and it can be written as p/q in base 12, then find p and q.
0.141414... *144 = 14.14141414.... (in base 12)
so 14/143 is the answer???
Guys little help on how to solve such problems....detailed explanation will be appreciated..
@bs0409 said:OA-13340.14141414 is a base 12 number and it can be written as p/q in base 12, then find p and q.
16/143??
1/12 + 4/12^2 + 1/12^3 + 4/12^4 +.... = (1/12 + 1/12^3 + 1/12^5 + ...) + 4(1/12^2 + 1/12^4 + 1/12^6 + ...) = {(1/12)/(1-1/12)^2} + {(4/12^2)/(1-1/12)^2} = 16/143...
This 16/143 is in base 10....if you need the answer in base 12 then it would be 14/bb (base 12 equivalent of 16/143)
Q 5
@bs0409 said:OA-13340.14141414 is a base 12 number and it can be written as p/q in base 12, then find p and q.
0.14141414 = 16/143 in base 10
If I am not wrong.. 143 is bb in base 12 
So, 14/bb ?? I am not sure of bb
An ant starts from a point on the bottom edge of a right circular cylinder and moves in spiral manner along the curved surface area such that it reaches the top of cylinder at a point directly above the starting point in exactly 2 identical spirals. Find the distance covered by the ant if the radius of the cylinder is 6/pie and height is 20 units.
@bs0409 said:An ant starts from a point on the bottom edge of a right circular cylinder and moves in spiral manner along the curved surface area such that it reaches the top of cylinder at a point directly above the starting point in exactly 2 identical spirals. Find the distance covered by the ant if the radius of the cylinder is 6/pie and height is 20 units.
Is it 31.2 units??
the base is 2pi*r = 12..
and height of one spiral = 10..
since the ant takes two such spirals -> 2*rt(12^2 + 10^2) = 31.2 units....
@ScareCrow28 said:0.14141414 = 16/143 in base 10If I am not wrong.. 143 is bb in base 12 So, 14/bb ?? I am not sure of bb
@Logrhythm said:16/143??1/12 + 4/12^2 + 1/12^3 + 4/12^4 +.... = (1/12 + 1/12^3 + 1/12^5 + ...) + 4(1/12^2 + 1/12^4 + 1/12^6 + ...) = {(1/12)/(1-1/12)^2} + {(4/12^2)/(1-1/12)^2} = 16/143...This 16/143 is in base 10....if you need the answer in base 12 then it would be 14/bb (base 12 equivalent of 16/143)
@pratskool said:0.141414... *144 = 14.14141414.... (in base 12)so 14/143 is the answer???
OA=14/bb
In a three digit number , the difference between it's hundred and it's tens digit is equal to the difference between it's ten digits and it's units digit . Also the sum of the digits is 9 . How many are possible which satisfy the given conditions ?
In a three digit number , the difference between it's hundred and it's tens digit is equal to the difference between it's ten digits and it's units digit . Also the sum of the digits is 9 . How many are possible which satisfy the given conditions ?
@bs0409 said:An ant starts from a point on the bottom edge of a right circular cylinder and moves in spiral manner along the curved surface area such that it reaches the top of cylinder at a point directly above the starting point in exactly 2 identical spirals. Find the distance covered by the ant if the radius of the cylinder is 6/pie and height is 20 units.
Distance traveled by ant in "x" axis = 2*2*pie*r = 24
Distance traveled by ant in y axis = 20
Total distance = Root ( 20^2 + 24^2 ) = 4 root (61) ?
@bs0409 said:An ant starts from a point on the bottom edge of a right circular cylinder and moves in spiral manner along the curved surface area such that it reaches the top of cylinder at a point directly above the starting point in exactly 2 identical spirals. Find the distance covered by the ant if the radius of the cylinder is 6/pie and height is 20 units.
2*pi*r = 2*pi*6/pi = 12
for 1 spiral height = 10
so total distance traveled = 2*rt(12^2 + 10^2) = 31.2
@bs0409 said:If you form a subset of integers chosen from between 1 to 3000, such that no two integers add up to a multiple of nine, what can be the maximum number of elements in the subset.a.1668 b.1332 c.1333 d.1334
1334?
@bs0409 said:OA=14/bbIn a three digit number , the difference between it's hundred and it's tens digit is equal to the difference between it's ten digits and it's units digit . Also the sum of the digits is 9 . How many are possible which satisfy the given conditions ?
6??
abc
a-b=b-c
so a+c = 2b...
a+b+c=9
=> b=3..
hence, a+c=6..
(a,c) = (6,0);(1,5);(2,4);(3,3)
so, 6 such numbers...
@ScareCrow28 said:Distance traveled by ant in "x" axis = 2*2*pie*r = 24Distance traveled by ant in y axis = 20Total distance = Root ( 20^2 + 24^2 ) = 4 root (61) ?
@Logrhythm said:Is it 31.2 units??the base is 2pi*r = 12..and height of one spiral = 10..since the ant takes two such spirals -> 2*rt(12^2 + 10^2) = 31.2 units....
OA=31.2
@bs0409 said:OA=14/bbIn a three digit number , the difference between it's hundred and it's tens digit is equal to the difference between it's ten digits and it's units digit . Also the sum of the digits is 9 . How many are possible which satisfy the given conditions ?
11
@bhatkushal said:Guys little help on how to solve such problems....detailed explanation will be appreciated..
Please guys if some one can tell how to proceed on such questions...
@bhatkushal said:Please guys if some one can tell how to proceed on such questions...
Which questions??
@bs0409 said:OA=14/bbIn a three digit number , the difference between it's hundred and it's tens digit is equal to the difference between it's ten digits and it's units digit . Also the sum of the digits is 9 . How many are possible which satisfy the given conditions ?
x - y = y - z
x + z = 2y
x + y + z = 9
2y + y = 9
y = 3
x + z = 6
531,135,432,234,333,630
so 6 numbers?
Kidhar ho ppls with questions??
@mailtoankit said:x - y = y - zx + z = 2yx + y + z = 92y + y = 9 y = 3x + z = 6531,135,432,234,333,630so 6 numbers?
there can be another case when
x-y=z-y
x=z
so six numbers are possible
171
252
333
414
but 333 is repeated here so total 9 numbers
x-y=z-y
x=z
so six numbers are possible
171
252
333
414
but 333 is repeated here so total 9 numbers