@DreamBikerzz said:@Logrhythm answer to 8 hi diya hai. thoda expain bhi kar do yaar
@Logrhythm said:Is it 0m??See for every 50m that Plant travels Page travels 20m...so they would at the 5th meeting meet at A...Now when Plant has completed 10 laps, he would be at his base location...and page and plant would have met 9 times by then...another 10 laps does the same thing....and they wld have met 18 times...total meetings = 9+9 = 18...we need 5 more meetings...hence they would meet at A...so 0m from A..
@Logrhythm said:Is it 0m??See for every 50m that Plant travels Page travels 20m...so they would at the 5th meeting meet at A...Now when Plant has completed 10 laps, he would be at his base location...and page and plant would have met 9 times by then...another 10 laps does the same thing....and they wld have met 18 times...total meetings = 9+9 = 18...we need 5 more meetings...hence they would meet at A...so 0m from A..
i have a doubt. when plant completes 10 laps, how did u calculate that they would have met 9 times? @pratskool said:how do you know bro, that after he completes 50m it would be 5th meeting, and not 4th or 6th? how did u come to this conclusions? its true they would meet after plant completes, but you can check manually for 1st few meetings1st = 50/7 m covered by plant2nd = 50/7 + 100/73rd = 50/7 + 200/74th = 50/7 + 300/7 = 50m
@pratskool said:how do you know bro, that after he completes 50m it would be 5th meeting, and not 4th or 6th? how did u come to this conclusions? its true they would meet after plant completes, but you can check manually for 1st few meetings1st = 50/7 m covered by plant2nd = 50/7 + 100/73rd = 50/7 + 200/74th = 50/7 + 300/7 = 50m
@techgeek2050 said:right answer. u nailed it. i have a doubt. when plant completes 10 laps, how did u calculate that they would have met 9 times?
@Logrhythm said:are u guys taking into account that when plant reaches A, page is still btwn A and B..plant meets page @ 129/21 from A for the 2nd time...and then also page is btwn A and B....so here total distance traveled by them after their first meeting is not 20m..hence yahan par D+2D(n-1) wala formula valid ni hoga...ye thoda figure bana kar karne wala question hai agat imagine nahi ho paa raha toh....
@pratskool said:how do you know bro, that after he completes 50m it would be 5th meeting, and not 4th or 6th? how did u come to this conclusions? its true they would meet after plant completes, but you can check manually for 1st few meetings1st = 50/7 m covered by plant2nd = 50/7 + 100/73rd = 50/7 + 200/74th = 50/7 + 300/7 = 50m
which question u guys discussing??
@ankittripathi said:Hi bro,the trick u r using has a fault. u r assuming that for every meeting after the first one the total distance would be 2D, that is not the case here.Here, during second meeting, and even third meeting, the page has still not reach the other end. while plant completes his one lap.the first meeting happens at. 20/7 m from A.the second meeting at 20/3 m from Athird meeting at 60/7 m from Afourth at 30/7 m from B ( here page reaches b and returns)and fifth at A itself. At this point both are at A.For next 50 metres, they will meet 4 times.AT THIS TIME THEY R AT THERE original positons.So, for 100 metres they have met 9 times
PPL need help on numbers & PnC...anyone willing to discuss on that!!! ???
In order to buy a car a man borrowed 180000 on the condition that he had to pay 7.5% interest every year. He also agree to repay the principal in equal annual installments over 21 years . After a certain no of years however the rate of interest has been reduced to 7%. It is also known that at the end of the agreed period, he will have paid in all rs 270900 in interest.
@vbhvgupta said:In order to buy a car a man borrowed 180000 on the condition that he had to pay 7.5% interest every year. He also agree to repay the principal in equal annual installments over 21 years . After a certain no of years however the rate of interest has been reduced to 7%. It is also known that at the end of the agreed period, he will have paid in all rs 270900 in interest.For how many years does he pay at the reduced interest?
Suppose the rate is reduced after x years.
Now, The total interest is Rs. 270900/-
(180000 * 7.5 * x / 100 ) + ( 180000 * 7 * ( 21- x ) / 100 ) = 270900
0.5 x = 3.5
x = 7 years.
No. of years he paid at reduced interest = 21 - 7 = 14 years.
Q2
