@vbhvgupta said:Yar koi inhe bhi solve kar do..
First q: Rs 9274.19
Second : Rs. 29100
Second : Rs. 29100
@techgeek2050 said:Page and Plant are running on a track AB of length 10 metres. They start running simultaneously from the ends A and B respectively. The moment they reach either of the ends, they turn around and continue running. Page and Plant run with constant speeds of 2m/s and 5m/s respectively. How far from A (in metres) are they, when they meet for the 23rd time?
@techgeek2050 said:Page and Plant are running on a track AB of length 10 metres. They start running simultaneously from the ends A and B respectively. The moment they reach either of the ends, they turn around and continue running. Page and Plant run with constant speeds of 2m/s and 5m/s respectively. How far from A (in metres) are they, when they meet for the 23rd time?
@ScareCrow28 said:0 metresWhen Plant travels 50m then Page travels 20m each time they meet on the way. When plant has covered 50m they would have met for the 5th time. Similarly when plant covers 100mtrs...page covers 40mtrs. hence after covering 100mtrs they have met for 9 times.Hence after 200mtrs...they hav met for 18 timesTherefore their 23rd meeting = (18+5) will be at A
@techgeek2050 said:after covering 100m , won't they have met 10 times?
@vbhvgupta said:Yar koi inhe bhi solve kar do..
@vbhvgupta said:Yar koi inhe bhi solve kar do..
@pratskool said:Vinay deposit 8000 in a bank which pays him 12% interest per annum compounded quarterly. What is the amount that he receives after 15 months?A = 8000(1 + (12/3*100))^5?? is it right?@vbhvgupta said:A makes a FD of Rs 20000 with the bank for a period of 3 years. If the rate of interest be 13%SI per annum charged half yearly, what will he get after 42 months.1) interest per quarter = 3%, total 5 quarters...so 8000( 1 + 3/100)^52) in SI doesn matter, annunaly or semi-annualy as we can take time in decimalso ans is 20000 + 20000*3.5*13/100
@vbhvgupta said:explain kar do
@vbhvgupta said:yar for 1st it will be 12/3 or 12/4 because in time we have taken 15/3 = 5
@ankittripathi said:A = p ( 1 + 12 / 4 * 100 ) ^ 5For second question... Its simple interest, so doesn't matter whether the interest is charged annually or half yearly.. the amount will remain the same... Do it using standard formula u will get the answer.
@pratskool said:the 1st time, they meet at 10/(5-2) = 10/3 ... 2nd after 20/3s so 23rd at 10/3 + 22*20/3 = 450/3 = 150safter 150 s, plant would have travelled 150*5 = 750mafter 10m he is at A, after 30 m he is at A so they would meet at A itself for the 23rd time

@vbhvgupta said:yar for 1st rate will be 12/3 or 12/4? because in time we have taken 15/3 = 5
@techgeek2050 said:dint get you brofor the 1st time dey'l meet at 20/7 m from A .... how 10/3?
@vbhvgupta said:How u calculated 1st becoz calculation is bit complex.
@ankittripathi said:If compound interest is compounded n times in a year, then after t years the amount wll beA = P ( 1 + r / 100n ) ^ n * tPut values, we will getA = 8000 ( 1 + 12 / 4 * 100 ) ^ 4 * 5/4A= 9274.19
Q1
@pratskool said:sorry, my bad.... i wanted to say they meet after 10/3 sec....