@audiq7 how could this be the difference ???
@audiq7 said:formula lagaya: diffrnce= p (r/100)^nfir calculator use kiya...
@vbhvgupta said:no, it is 5,00,000. I applied the formula but not getting it.
checked manually naswer is right, but what is the formula you put
@audiq7 said:formula lagaya: diffrnce= p (r/100)^nfir calculator use kiya...
are bhai formula for 3yr is p (r/100)^2 (r/100 + 3)
@techsurge said:@audiq7 how could this be the difference ??? checked manually naswer is right, but what is the formula you put
p (r/100)^2 (r/100 + 3)
@techsurge said:@audiq7 how could this be the difference ??? checked manually naswer is right, but what is the formula you put
p (r/100)^2 (r/100 + 3)
@techsurge said:@vbhvgupta sahi to haip(0.02)^2(3.02) =0.001208p =604p=604/0.001208=5 lakh
bhai used calc ya calculate kia khud se???
@techsurge said:@vbhvgupta sahi to haip(0.02)^2(3.02) =0.001208p =604p=604/0.001208=5 lakh
bhai used calc ya calculate kia khud se???
@vbhvgupta said:Vinay deposit 8000 in a bank which pays him 12% interest per annum compounded quarterly. What is the amount that he receives after 15 months?A = 8000(1 + (12/3*100))^5?? is it right?
@vbhvgupta said:A makes a FD of Rs 20000 with the bank for a period of 3 years. If the rate of interest be 13% SI per annum charged half yearly, what will he get after 42 months.
Yar koi inhe bhi solve kar do..
@vbhvgupta said:If the diff between the CI and SI on a certain sum of money for 3 years at 2% p.a is Rs 604, what is the sum?
A(1 + x/100)^3 - A - A*3*x/100 = 604
substituting x = 2
A(51/50)^3 - A - 6*A/100 = 604
132651/125000 - 106*A/100 = 604
151*A/125000 = 604 = 500000
@vbhvgupta said:If the diff between the CI and SI on a certain sum of money for 3 years at 2% p.a is Rs 604, what is the sum?
CI - SI = 604
=> P[ (1+2/100 )^3 - 1 ] - 6*P/100 = 604
From here, P = 500000
Page and Plant are running on a track AB of length 10 metres. They start running simultaneously from the ends A and B respectively. The moment they reach either of the ends, they turn around and continue running. Page and Plant run with constant speeds of 2m/s and 5m/s respectively. How far from A (in metres) are they, when they meet for the 23rd time?
@techgeek2050 said:Page and Plant are running on a track AB of length 10 metres. They start running simultaneously from the ends A and B respectively. The moment they reach either of the ends, they turn around and continue running. Page and Plant run with constant speeds of 2m/s and 5m/s respectively. How far from A (in metres) are they, when they meet for the 23rd time?
0 metres
When Plant travels 50m then Page travels 20m each time they meet on the way.
When plant has covered 50m they would have met for the 5th time.
Similarly when plant covers 100mtrs...page covers 40mtrs. hence after covering 100mtrs they have met for 9 times.
Hence after 200mtrs...they hav met for 18 times
Similarly when plant covers 100mtrs...page covers 40mtrs. hence after covering 100mtrs they have met for 9 times.
Hence after 200mtrs...they hav met for 18 times
Therefore their 23rd meeting = (18+5) will be at A