How many of the following numbers can be expressed as a product of 4 natural numbers in arithmetic progression, of which exactly 3 are in geometric progression? The numbers are 384, 1944, 945, 15000.
945 cannot be expressed
384 = 2*4*6*8
1944 = 3*6*9*12
15000 = 5*10*15*20
But 945 = 3*5*7*9..not possible as it does not satisfy the GP condition
หลก(x-3) ห = (3-x)Ha sahi h Equal he ayga. galti se likh diya tha Square root k ander square h na to under root m to kabhi -ve to nahi ayga is ques m. Vaise i (iota) ajate h agar -ve ka under root lenge to.
Nai mera matlab tha, root of 25, plus minus 5 Hota hai to? Ki sirf +5?
It's +5 and +5 only!!! ๐ -5 is no solution of root 25
Root doesn't give -ve values. Now, here, don't say that (-5)^2 = 25 so root(25) = -5 because by squaring you are adding a root here. If only root 25 is given then it's +5 only!
@ScareCrow28 : bhai ... i dont know why ... but i think u should write the value instead of comments i still think that if x^2 = 25 then x= +-5and same is for under root 25 ...and for check put value x= -5 and check whether it satisfy or not .. also check whether it is given +ve integers only or not
Dude, As I said, x^2 = 25 has TWO roots. Of course it has -5 as one of the roots.
But, if the question is x = 25, what is Root(x) ??
I suppose you would say it's +5 and -5 and you are wrong here! :)