Official Quant thread for CAT 2013

@krum thank you very much
@grkkrg said:
Please stop spamming this thread with empty posts sir.
thnks for reminding me...i myself hve noticed it now..really dnt know how its happening..i hvnt posted a single post yet..smone may plz help...
@manasvr said:
thnks for reminding me...i myself hve noticed it now..really dnt know how its happening..i hvnt posted a single post yet..smone may plz help...
@deepu Sir
Empty posts are automatically being added. Please look into this. :)
@grkkrg said:
@deepu SirEmpty posts are automatically being added. Please look into this.
@sonnes check this once.

Can anyone explain questions in attachment?
@gnehagarg said:
Can anyone explain questions in attachment?
14. (e) None of the above?

For getting even product, at least one throw should give an even number.
p = 1 - 1/2^n

For each positive integer n, define a sequence;


Here [x] denotes the largest integer not greater than x, for any real number x.

If n {1, 2, 3, …, 2012} then what is the number of n for which an > an + 1.

OPTIONS
1) 41
2) 43
3) 45
4) 47
@grkkrg said:
14. (e) None of the above?For getting even product, at least one throw should give an even number.p = 1 - 1/2^n
Agree...
@karan20 said:
For each positive integern, define a sequence;Here [x] denotes the largest integer not greater than x, for any real number x.If n ˆˆ{1, 2, 3, €Ś, 2012} then what is the number of n for which an > an + 1.OPTIONS 1) 41 2) 43 3) 45 4) 47
prove x>x+1??? hmmm...
sure there is no typing error??
@karan20 said:
For each positive integern, define a sequence;Here [x] denotes the largest integer not greater than x, for any real number x.If n ˆˆ{1, 2, 3, €Ś, 2012} then what is the number of n for which an > an + 1.OPTIONS 1) 41 2) 43 3) 45 4) 47
will be true n+1 is a perfect square hence C) 43 is the answer since there are 43 perfect squares (not including 1 for obvious reasons) between 1 and 2012

Abcd is a parallelogram Ab = 8 , Ad = 4 and Ec = 4 . If DE is an angle bisector of adc then find the length of Ed ?

Find tow length of the common chord of the two circles of radii 6 and 8 with their centers 10 cm apart ?

Ed=4...?

@meenu05 said:
Find tow length of the common chord of the two circles of radii 6 and 8 with their centers 10 cm apart ?
9.6??
@meenu05 said:
Find tow length of the common chord of the two circles of radii 6 and 8 with their centers 10 cm apart


edit: ah shit silly mistake......happens when mentally solving sums like these sometimes.
did (64-6.4)^1/2 instead of (64-6.4^2)^1/2
9.6
@mailtoankit yes it is 9.6 . Can you explain it ?
@meenu05 said:
Abcd is a parallelogram Ab = 8 , Ad = 4 and Ec = 4 . If DE is an angle bisector of adc then find the length of Ed ?
4.8
@meenu05 said:
@mailtoankit yes it is 9.6 . Can you explain it ?
it is a rt angle tringle...
so..1/2*8*6=1/2*10*h
h=4.8
length of chord=2h=9.6
@mailtoankit how did you deduce that the entire thing is right angle triangle...its nowhere specified o.o
@anantn Dude I did draw the right angle triangle symbol .