@soumitrabengeri said:How did you solve it? Can you please share your approach?
@scrabbler said:Didn't solve (not yet, at any rate)...just figured the distance from 4th house is rt(58)...so diag is > 20 and also Uske baad got stuck and gave up regardsscrabbler
@chillfactor said:How many different ways can you spell the word β¬ΕCONTEST β¬? by only moving right and /or down. C O N T E S TO N T E S TN T E S TT E S TE S TS TTa) 30 b) 32 c) 64 d) 128 e) none of these
@bullseyes said:Min. value of f(x) = (x β 5)^2 + (x β 7)^2 β (x β 4)^2 β (x β 8)^2 + (x β 3)^2 + (x β 9)^2
@Torque024 said:Alby, Benny, Cindy and Dan houses forms a square field ABCD. A cow, in a square field, is 13 meters from Benny's house, 17 meters from Dan's house, and 20 meters from Cindy's house. Find the area of the field. Assume house to be a point object and field to be flat.
@krum said:@soumitrabengeri now what? u got it?
@bullseyes said:how abt wdout expanding??
@bullseyes said:there is a formula for this rit?? any point in the midst of square is sum of squares from opposite points.
@bullseyes said:Min. value of f(x) = (x β 5)^2 + (x β 7)^2 β (x β 4)^2 β (x β 8)^2 + (x β 3)^2 + (x β 9)^2
@krum said:how? thats what i used for AO, what now, couldn't figure out how to proceed
@bullseyes said:does he provided u wd options? i will write down all.. just need to confirm my answer.
@soumitrabengeri said:Thanks..got it
@krum said:are i was asking if u got the solution, i can't figure out how to proceed
@bullseyes said:Min. value of f(x) = (x β 5)^2 + (x β 7)^2 β (x β 4)^2 β (x β 8)^2 + (x β 3)^2 + (x β 9)^2
@bullseyes said:Min. value of f(x) = (x β 5)^2 + (x β 7)^2 β (x β 4)^2 β (x β 8)^2 + (x β 3)^2 + (x β 9)^2
ABCD is a square. P is the mid point of AB. The line passing through A and perpendicular to DP intersects the diagonal at Q and BC at R. If AB=2 then PR=_______?