A thief steals four gallons of liquid soap kept in a train compartment's bathroom from a container that is full of liquid soap.He then fills it with water to avoid detection. Unable to resist the temptation he steals 4 gallons of mixture again,and fills it with water. When the liquid soap is checked at a station it is found that the ratio of liquid soap now left in the container to that of the water in it is 36:13. What was the initial amount of the liquid soap in the container if it is known that the liquid soap is neither used nor augmented by anybody during the entire period?a 7 gal b 14 gal c 21 gal d 28 galplease tell
Suppose he steals and leave a fraction x/y of the original soap. After two thefts it will be (x^2)/(y^2) of original.
But soap to water = 36:13 => soap to total = 36: 49. Hence (x^2)/(y^2) = 36/49 and x/y = 6/7. So he stole 1/7th of original - but this is 4 gallons, so original must be 28 gallons. regards scrabbler
Ashish is studying late into the night and id hungry . He opens his mother's snack cupboard without switching on the lights . Knowing that his mother has kept 10 packets of chips and biscuits in the cupboards . He pulls out 3 packets from the cupboards and all of them turn out to be chips . what is the probability that the snack cupboard contains 1 packets of biscuits and 9 packets of chips ?
Prob with this question was the language .. Hence it was tough to work out during exam
Forward is much harder - more ramifications possible. Backward, if you take one step at a time you can cover all possible cases with no chance of missing any. There is some formal theory behind this I believe (the stagecoach problem I had mentioned), but I cannot recollect it...Try it for a standard grid, say a 5x3 rectangular one with no diagonal routes.... We know the answer will be 8C3 there, but it is a good way to practice this approach. regardsscrabbler
I think it doesn't matter which end we start from, answer will be same unless the grid is not symmetric wrt to the two extremes
Ashish is studying late into the night and id hungry . He opens his mother's snack cupboard without switching on the lights . Knowing that his mother has kept 10 packets of chips and biscuits in the cupboards . He pulls out 3 packets from the cupboards and all of them turn out to be chips . what is the probability that the snack cupboard contains 1 packets of biscuits and 9 packets of chips ?
I think it doesn't matter which end we start from, answer will be same unless the grid is not symmetric wrt to the two extremesSolve the question in the attachment
I think it doesn't matter which end we start from, answer will be same unless the grid is not symmetric wrt to the two extremesSolve the question in the attachment
join efgh to form a rhombus. area=1/2(product of diagonals)=1/2(ab)=6 area gkf=1/2(efgh)=3
I think it doesn't matter which end we start from, answer will be same unless the grid is not symmetric wrt to the two extremesSolve the question in the attachment
Answer will be the same, no doubt. Just that if you start from the front you won't know which paths to continue and which to close off. So you will have to list the full path in detail (or at least, I had to)! So I prefer from the back. YMMV of course :)
And the answer to the question will be 3 I guess. Tri half of EFGH which is half of original figure.... regards scrabbler
I think it doesn't matter which end we start from, answer will be same unless the grid is not symmetric wrt to the two extremesSolve the question in the attachment
AEF,HDG,GFC,EFB,AHE have area 1/8*ABCD(1/8*12=3/2)
How many different ways can you spell the word €œCONTEST €? by only moving right and /or down. C O N T E S TO N T E S TN T E S TT E S TE S TS TTa) 30 b) 32 c) 64 d) 128 e) none of these
Possible ways; 6R=1; 6D=1; 1R,5D=6; 2R,4D=15; 3R,3D=20; 4R,2D= 15; 5R,1D=6; Total 64 ways?
How many different ways can you spell the word €œCONTEST €? by only moving right and /or down. C O N T E S TO N T E S TN T E S TT E S TE S TS TTa) 30 b) 32 c) 64 d) 128 e) none of these
Each step 2 options (either right or down). Hence 2^6 = 64.
Alternatively, have to go total 6 steps. Could be 6R, or 5R1D, or 4R2D etc till 0R6D....so 6C6 + 6C5 + 6C4 +... 6C0= 2^6 = 64.
Alby, Benny, Cindy and Dan houses forms a square field ABCD. A cow, in a square field, is 13 meters from Benny's house, 17 meters from Dan's house, and 20 meters from Cindy's house. Find the area of the field. Assume house to be a point object and field to be flat.
Alby, Benny, Cindy and Dan houses forms a square field ABCD. A cow, in a square field, is 13 meters from Benny's house, 17 meters from Dan's house, and 20 meters from Cindy's house. Find the area of the field. Assume house to be a point object and field to be flat.
Aila itne close hai! I got it has to be between 200 and 392 and closer to the upper side of that range, so thought ki options dekhke kuch hoga... back to the ol' drawing board.... regards scrabbler
Aila itne close hai! I got it has to be between 200 and 392 and closer to the upper side of that range, so thought ki options dekhke kuch hoga... back to the ol' drawing board....regardsscrabbler
How did you solve it? Can you please share your approach?
