Official Quant thread for CAT 2013

MBA CAT 2024
7061
@Shray14 yaar tu yahan pe bhi mujhe darane aa gaya ... ab batao main question kaise solve karunga...
7062
@Zedai said:
no mann
What is A?? Area?
7063

ABCD is a rectangle with AD =10. P is a point on BC such that Ang(APD)=90. If DP=8 then the length of BP is________??


(1) 6.4

(2)5.2

(3)4.8

(4)3.6

(5) none of the above
7064
@ScareCrow28 said:
What is A?? Area?
sorry bhai, Corrected. :)
7065
@Improver said:
@Shray14 yaar tu yahan pe bhi mujhe darane aa gaya ... ab batao main question kaise solve karunga...
Sirf question solve kar..daar mat..
7066
@Zedai A?=2
7067
@Improver said:
@Zedai A?=2
edited. it's AB.
7068
@Zedai sqrt (2)
7069
@Zedai said:
ABCD is a square. P is the mid point of AB. The line passing through A and perpendicular to DP intersects the diagonal at Q and BC at R. If AB=2 then PR=_______?A) 1/2B) sqrt(3)/2C) sqrt(2)D) 1E) None of these
C) sqrt(2)
7070
@Improver said:
@Zedai sqrt (2)
correct. Approach?
7071
@Zedai angle(ADP)=angle(RAB)
angle(ARB)= 90-angle(RAB)
use tan(APD)=2=tan(ARB)
get RB
then use pytho
7072
@Zedai said:
ABCD is a rectangle with AD =10. P is a point on BC such that Ang(ABC)=90. If DP=8 then the length of BP is________??(1) 6.4(2)5.2(3)4.8(4)3.6(5) none of the above
phr se kuch gadbad hai ... ang(ABC)=90???
7073
@Zedai said:
ABCD is a square. P is the mid point of AB. The line passing through A and perpendicular to DP intersects the diagonal at Q and BC at R. If AB=2 then PR=_______?A) 1/2B) sqrt(3)/2C) sqrt(2)D) 1E) None of these
Put A to origin
P(1,0) let R be (2,y)
Slope AR* Slope PD=-1;
y=1;
Distance PR=sqrt(1+1)=sqrt(2)?
7074
@Zedai 3.6 ?????
7075
@Zedai said:
ABCD is a rectangle with AD =10. P is a point on BC such that Ang(ABC)=90. If DP=8 then the length of BP is________??(1) 6.4(2)5.2(3)4.8(4)3.6(5) none of the above
Ang(ABC)=90? This will always holds, check your question.
7076
@Torque024 said:
Ang(ABC)=90? This will always holds, check your question.
sorry mann, it's APD
7077
@Zedai said:
ABCD is a rectangle with AD =10. P is a point on BC such that Ang(APD)=90. If DP=8 then the length of BP is________??(1) 6.4(2)5.2(3)4.8(4)3.6(5) none of the above
3.6
..If /_ APD = 90
7078
@Zedai check your questn. nd correct it......its not d angle (ABC)....its angle APD=90....!!!thn u will get d right ans
7079
@Zedai said:
ABCD is a rectangle with AD =10. P is a point on BC such that Ang(APD)=90. If DP=8 then the length of BP is________??(1) 6.4(2)5.2(3)4.8(4)3.6(5) none of the above
Put A to origin , Let P be (x,y)
slopePD* slopeAP=-1
y(y-10)=-x^2
x^2+(y-10)^2=64, as distance is 8
10y=36; y=3.6?
BP=3.6?
7080
@Zedai then ans is 3.6
angleDAP=angleAPB
hence equate their cos you will get the answer