@nick_baba said:u r right ..but did u got this condition for y using sum
Best option if no.s are small... 
@nick_baba said:A wooden unit cube rests on a horizontal surface. A point light source a distance x above an upper vertex casts a shadow of the cube on the surface. The area of the shadow (excluding the part under the cube) is 35. Then x is(1) 1/5 (2) 2/7 (3) 1/4 (4) 1/6P.S: was jus fed up of that "rest" question...thought of giving it a rest..
consider the two similar triangles..
x/(x+1) = 1/6
==> x = 1/5 :)
The average marks of section A students are 20% less than the average marks of section B students. On the other hand, the total marks of section A are 20% more than the total marks of section B. Thus, the number of students in section B is what percent of the number of students in section A?
@gupanki2 said:The average marks of section A students are 20% less than the average marks of section B students. On the other hand, the total marks of section A are 20% more than the total marks of section B. Thus, the number of students in section B is what percent of the number of students in section A?
A = 0.8B
na * A = 1.2 * nb * B
nb = 0.8/1.2 * na
So 66(2/3) %
Was solved recently
na * A = 1.2 * nb * B
nb = 0.8/1.2 * na
So 66(2/3) %
Was solved recently
@nick_baba said:Number y is defined as the sum of the digit of the number x, and z as the sum of the digits of the number y. How many natural numbers x satisfy the equation x+y+z = 60?(1) 1 (2) 3 (3) 4 (4) 2 (5) more than 4
x is less than 60..
Now first number that satisfies is 50,5,5
you need to check only till 40.. After that no number can logically satisfy..
2nd set would be 47,11,2
3rd 44,8,8
So 3..
@gupanki2 said:The average marks of section A students are 20% less than the average marks of section B students. On the other hand, the total marks of section A are 20% more than the total marks of section B. Thus, the number of students in section B is what percent of the number of students in section A?
Was solved today morning..please check the previous posts..
Answer is 66.67%
@soumitrabengeri @grkkrg ...... jus saw previous page's.... Glad to see PUYS fully active on this thread :)
@gupanki2 said:@soumitrabengeri@grkkrg ...... jus saw previous page's.... Glad to see PUYS fully active on this thread
quant thread is always active :)
@SarayuSheshadri said:x is less than 60..Now first number that satisfies is 50,5,5 you need to check only till 40.. After that no number can logically satisfy..2nd set would be 47,11,23rd 44,8,8So 3..
any ohter way apart from hit and trial..???...this does not luks like a "solution" though
@nick_baba said:Number y is defined as the sum of the digit of the number x, and z as the sum of the digits of the number y. How many natural numbers x satisfy the equation x+y+z = 60?(1) 1 (2) 3 (3) 4 (4) 2 (5) more than 4
3 nos
44,47 & 50
44,47 & 50
The set M consists of p consecutive integers with sum 2p. The set N consists of 2p consecutive integers with sum p. The difference between the largest elements of M and N is 9. Then p is
(a) 17 (b) 36 (c) 9 (d) 27 (e) 21
(a) 17 (b) 36 (c) 9 (d) 27 (e) 21
@nick_baba said:The set M consists of p consecutive integers with sum 2p. The set N consists of 2p consecutive integers with sum p. The difference between the largest elements of M and N is 9. Then p is(a) 17 (b) 36 (c) 9 (d) 27 (e) 21
21
@nick_baba said:yep.. koi logical tareeka batana dost..don say hit n trial..
I'm afraid to say waise hi kiya 
..ab @nick_baba said:The set M consists of p consecutive integers with sum 2p. The set N consists of 2p consecutive integers with sum p. The difference between the largest elements of M and N is 9. Then p is(a) 17 (b) 36 (c) 9 (d) 27 (e) 21
21
@nick_baba said:The set M consists of p consecutive integers with sum 2p. The set N consists of 2p consecutive integers with sum p. The difference between the largest elements of M and N is 9. Then p is(a) 17 (b) 36 (c) 9 (d) 27 (e) 21
21
@deedeedudu said:21
@ScareCrow28 said:21
....logic kyu chupa ke rkha hai..wo bhi batao na bhai logo..
1 Like
@nick_baba said:....logic kyu chupa ke rkha hai..wo bhi batao na bhai logo..
Eqn bana lo sum of AP
with common difference 1 and different 1st term
with common difference 1 and different 1st term
@nick_baba said:The set M consists of p consecutive integers with sum 2p. The set N consists of 2p consecutive integers with sum p. The difference between the largest elements of M and N is 9. Then p is(a) 17 (b) 36 (c) 9 (d) 27 (e) 21
M={2-(p-1)/2,.............,1,2,3,,,,,,,,,,,,,2+(p-1)/2},Largest element=p
N={.5-(p-1)/2,..............,.5,1.5,........,.5+(2p-1)/2},Largest element=(p+3)/2
P-(P+3)/2=9
P=21