@grkkrg said:He can reach in 120 minutes exact!
Take a rest before starting the journey.
he he 😛 Then he'll take 40 rests ;)
@SarayuSheshadri said:he he Then he'll take 40 rests
@grkkrg said:He can reach in 120 minutes exact!Take a rest before starting the journey.
It's 40 
@grkkrg said:arre haan..1 + (40 - 1) = 40 @19rsb vvvvvv It's 40
Amar climbs at 16 m/min and rests for 2 minutes or 20 m in 2 min and rest for 1 minute.. Doesn't this means that he climbs first and then rests..In other questions like this it means this only..
So we shouldn't take the possibility of resting before climbing..
@19rsb said:eureka ! eureka ! eureka !
Thought of that first... But later thought it couldnt be that ways... But neways... Ultimately only correct answer is what matters...
@ScareCrow28 said:Amar climbs at 16 m/min and rests for 2 minutes or 20 m in 2 min and rest for 1 minute.. Doesn't this means that he climbs first and then rests..In other questions like this it means this only..So we shouldn't take the possibility of resting before climbing..
We can always assume that he can rest for any length of time as long as he covers 800 meters in 120 minutes sharp.
It's not "resting before climbing". It's just "resting".
I could've placed this rest period anywhere.
Placing it in the end violates the time condition.
Placing it in the middle gives 39 rests.
Placing it in the beginning gives 40 rests.
Hope it makes sense. :)
It's not "resting before climbing". It's just "resting".
I could've placed this rest period anywhere.
Placing it in the end violates the time condition.
Placing it in the middle gives 39 rests.
Placing it in the beginning gives 40 rests.
Hope it makes sense. :)
A wooden unit cube rests on a horizontal surface. A point light source a distance x above an upper vertex casts a shadow of the cube on the surface. The area of the shadow (excluding the part under the cube) is 35. Then x is
(1) 1/5 (2) 2/7 (3) 1/4 (4) 1/6
(1) 1/5 (2) 2/7 (3) 1/4 (4) 1/6
P.S: was jus fed up of that "rest" question
...thought of giving it a rest..
...thought of giving it a rest.. @grkkrg said:We can always assume that he can rest for any length of time as long as he covers 800 meters in 120 minutes sharp. It's not "resting before climbing". It's just "resting".I could've placed this rest period anywhere.Placing it in the end violates the time condition.Placing it in the middle gives 39 rests.Placing it in the beginning gives 40 rests.Hope it makes sense.
It makes sense because answer is 40 😛
But i am just wondering because i have seen questions like this where it means he walks for 20m/2min and then rests for 1 min..
Anyways..
and the answer says "40"
and the answer says "40"@nick_baba said:A wooden unit cube rests on a horizontal surface. A point light source a distance x above an upper vertex casts a shadow of the cube on the surface. The area of the shadow (excluding the part under the cube) is 35. Then x is (1) 1/5 (2) 2/7 (3) 1/4 (4) 1/6 P.S: was jus fed up of that "rest" question...thought of giving it a rest..
(1) 1/5
Another "rest" quesition. :P
35 = y^2 - 1^2
y = 6
1/(6 - 1) = x/1
x = 1/5
Another "rest" quesition. :P
35 = y^2 - 1^2
y = 6
1/(6 - 1) = x/1
x = 1/5
@ScareCrow28 said:Amar climbs at 16 m/min and rests for 2 minutes or 20 m in 2 min and rest for 1 minute.. Doesn't this means that he climbs first and then rests..In other questions like this it means this only..So we shouldn't take the possibility of resting before climbing..
I think discussion is endless......2 of d following cases prevails here
1)either,there is a problem within d given problem
2)or v r unable to extract d real problem out of d given problem
but what is important here ........is that........at least v hav given our bit of try.....so njoy
1)either,there is a problem within d given problem
2)or v r unable to extract d real problem out of d given problem
but what is important here ........is that........at least v hav given our bit of try.....so njoy
Number y is defined as the sum of the digit of the number x, and z as the sum of the digits of the number y. How many natural numbers x satisfy the equation x+y+z = 60?
(1) 1 (2) 3 (3) 4 (4) 2 (5) more than 4
(1) 1 (2) 3 (3) 4 (4) 2 (5) more than 4
@grkkrg said:(1) 1/5Another "rest" quesition. 35 = y^2 - 1^2y = 61/(6 - 1) = x/1x = 1/5
budyy..luks all latin....diagram k saath thoda explain karo ise...
@nick_baba said:Number y is defined as the sum of the digit of the number x, and z as the sum of the digits of the number y. How many natural numbers x satisfy the equation x+y+z = 60?(1) 1 (2) 3 (3) 4 (4) 2 (5) more than 4
2) 3 ??
@nick_baba said:Number y is defined as the sum of the digit of the number x, and z as the sum of the digits of the number y. How many natural numbers x satisfy the equation x+y+z = 60?(1) 1 (2) 3 (3) 4 (4) 2 (5) more than 4
(2) 3?
@nick_baba said:Number y is defined as the sum of the digit of the number x, and z as the sum of the digits of the number y. How many natural numbers x satisfy the equation x+y+z = 60?(1) 1 (2) 3 (3) 4 (4) 2 (5) more than 4
2) 3?
y can be a maximum of 14 (5 + 9)
z can be a maximum of 9
So x can be a minimum of 37
44 + 8 + 8 = 60
47 + 11 + 2 = 60
50 + 5 + 5 = 60
y can be a maximum of 14 (5 + 9)
z can be a maximum of 9
So x can be a minimum of 37
44 + 8 + 8 = 60
47 + 11 + 2 = 60
50 + 5 + 5 = 60
Yipeee!!! 5000th post was mine!! 
P.S. With a hopefully correct answer!!
@grkkrg said:2) 3?y can be a maximum of 14 (5 + 9)z can be a maximum of 9So x can be a minimum of 3744 + 8 + 8 = 6047 + 11 + 2 = 6050 + 5 + 5 = 60
u r right ..but did u got this condition for y using sum
@nick_baba said:budyy..luks all latin....diagram k saath thoda explain karo ise...
@grkkrg said:(1) 1/5Another "rest" quesition. 35 = y^2 - 1^2y = 61/(6 - 1) = x/1x = 1/5
Take the light source to be at origin.
The base of the cube rests on (0,0) (0,1) (1,1) (1,0)
The shadow of the cube will also be a square (0,0) (0,y) (y,y) (y,0)
The second part is based on similar triangles:
Let the light source be at point P, x meters above point A of the cube
Now x/(horizontal side of cube) = (vertical side of cube + x) / 6
x/1 = (1 + x) / 6
6x = 1 + x
x = 1/5
Diagram nahi daal sakta :(
The base of the cube rests on (0,0) (0,1) (1,1) (1,0)
The shadow of the cube will also be a square (0,0) (0,y) (y,y) (y,0)
The second part is based on similar triangles:
Let the light source be at point P, x meters above point A of the cube
Now x/(horizontal side of cube) = (vertical side of cube + x) / 6
x/1 = (1 + x) / 6
6x = 1 + x
x = 1/5
Diagram nahi daal sakta :(