Official Quant thread for CAT 2013

MBA CAT 2024
4381
@rubikmath said:
@sujamaitdistinct digits !! den 1,1,8 combo is not possible .ryt ?
oh haan. damn!! i should have got the clue..33 aa rhe the..8,1,1 gives 3..something was fishy still..gadbad ki.
4382
@Brooklyn said:
explain kardo yar


729=27*27
so, bhai just take an example of 4*4 saplings..and try to build logic..waise hee ho jayega..

4383
In how many ways can four letters of the word SERIES be arranged ?
24
42
84
102
4384
@sujamait said:
8 is not possible. and 7 is also not possible as perimeter of circle is 88.out of 4,6 I will go with 4
why cant it be 7?...
4385
@sujamait said:
In how many ways can four letters of the word SERIES be arranged ?244284102
4 diff= 4!

2 same 2 diff= 2c1*4!/2! = 4!
2 same 2 same other=1

total 49 :banghead:
4386
@sujamait said:
In how many ways can four letters of the word SERIES be arranged ?244284102
24 ? didnt get the question though ..
4387
@sujamait said:
In how many ways can four letters of the word SERIES be arranged ?244284102
102
4!+3C2*4!+4!/2!2!
4388
@sonamaries7 said:
why cant it be 7?...
7 se 87 aa rha tha perimeer of hexa..seemed v close to be ..so...hone ko toh 4,6,7 mein se ho sakta hai..but exam mein itna time nhn hua toh yeh wali approach ka risk lene ki koshish..
4389
@sujamait said:
In how many ways can four letters of the word SERIES be arranged ?244284102
is it 102??????
4390
@sujamait said:
7 se 87 aa rha tha perimeer of hexa..seemed v close to be ..so...hone ko toh 4,6,7 mein se ho sakta hai..but exam mein itna time nhn hua toh yeh wali approach ka risk lene ki koshish..
but otherwise kaise solve karoge?...
4391
@Brooklyn said:
4 diff= 4!2 same 2 diff= 2c1*4!/2! = 4!2 same 2 same other=1 total 49
IIFT ka Q hai..iski bajah se us saal cutoff rah gayi thi
4392
@sujamait said:
In how many ways can four letters of the word SERIES be arranged ?244284102
102
4393
@deedeedudu said:
1024!+3C2*4!+4!/2!2!
kaise aaye ye value..plz explain a bit
4394
@sujamait said:
IIFT ka Q hai..iski bajah se us saal cutoff rah gayi thi
102
4395
@sonamaries7 said:
102
approach??
4396



@sujamait said:
In how many ways can four letters of the word SERIES be arranged ?244284102

102 =

all different = 4!
2 same 2 diff = 2c1 * 3c1*4!/2!
2same pairs = 4!/2!2!
4397
Domain of f(x) =1/loga(b)

a = base = 5-|x|
b = root(x^3-7x^2+14x-8)

a> (0,∞)
b> ( -5, -4) U ( -4,4) U (4,5)
c> (1,2) U (4,5)
d> (1,2) U (4,∞)
4398
@19rsb said:
is it 102??????
@Brooklyn said:
102
@sonamaries7 said:
102
Yup Guys!!
@sonamaries7 said:
but otherwise kaise solve karoge?...
sochna padega..OA toh batado :/
4399
@mailtoankit said:
kaise aaye ye value..plz explain a bit
The word has 2S,2E,1R,1I
When all the words chosen r different total arrangements will be
4!
When Either 2S or 2E r chosen then
Total arrangements will be
4!/2! but either of 2S or 2E can be chosen hence 2 cases rest 2 alphabets can be selected in 3C2 ways
hence total
2*3C2*4!/2
Lastly when 2E nd 2S r selected
4!/2!2!
4400
@mailtoankit said:
kaise aaye ye value..plz explain a bit
there are 4 different letters S, E, R, I..
Arrangement with all different letters 4! = 24
with 2 same, the same letter can be E or S.. so total ways of selection 2*3(two of 3 other letters) arrangement in 4!/2!.. so total 2*3*4!/2! = 72
two same + two same - 4!/2!*2! = 6

total 24+72+6 = 102