Official Quant thread for CAT 2013

MBA CAT 2024
4401
@sonamaries7 said:
A hexagon is inscribed in a circle of r=14cm3 of its sides are 22 each and the other 3 sides are equal. Find the length of the other 3 sides4687
OA: 4
share the approach...
@sujamait ,@amresh_maverick ,@Brooklyn , @pankaj1988
4402
@amresh_maverick said:
Domain of f(x) =1/loga(b)a = base = 5-|x|b = root(x^3-7x^2+14x-8)a> (0, ˆž)b> ( -5, -4) U ( -4,4) U (4,5)c> (1,2) U (4,5)d> (1,2) U (4, ˆž)
c
4403
@amresh_maverick said:
Domain of f(x) =1/loga(b)a = base = 5-|x|b = root(x^3-7x^2+14x-8)a> (0, ˆž)b> ( -5, -4) U ( -4,4) U (4,5)c> (1,2) U (4,5)d> (1,2) U (4, ˆž)
c?
4404
@amresh_maverick said:
Domain of f(x) =1/loga(b)a = base = 5-|x|b = root(x^3-7x^2+14x-8)a> (0, ˆž)b> ( -5, -4) U ( -4,4) U (4,5)c> (1,2) U (4,5)d> (1,2) U (4, ˆž)
C lag rha hai..
o pe root wala -ve ho rha hai so..b is out..
5 se greater pe base -ve ho rha hai so..d,a is out..
4405
A sum was split into two equal parts. One of the parts was invested at SI for N1 years at R% p.a. The other part was invested at CI for N2 years at R% p.a. Both parts fetched the same interest. Which of the following can be concluded?
1)N1
2)N1>=N2
3)N1=N2
4)N1 not equal to N2
5)none
4406
@amresh_maverick said:
Domain of f(x) =1/loga(b)a = base = 5-|x|b = root(x^3-7x^2+14x-8)a> (0, ˆž)b> ( -5, -4) U ( -4,4) U (4,5)c> (1,2) U (4,5)d> (1,2) U (4, ˆž)
is it c????
4407
@Brooklyn said:
c
@sujamait said:
C lag rha hai..o pe root wala -ve ho rha hai so..b is out..5 se greater pe base -ve ho rha hai so..d,a is out..
@Brooklyn said:
c
OA = c and d are out as x cannot be 5

also taking x= 3 , the no comes out to be -negative which rules out option 2
4408
@pankaj1988 said:
A sum was split into two equal parts. One of the parts was invested at SI for N1 years at R% p.a. The other part was invested at CI for N2 years at R% p.a. Both parts fetched the same interest. Which of the following can be concluded?1)N12)N1>=N23)N1=N24)N1 not equal to N25)none
2
4409
@pankaj1988 said:
A sum was split into two equal parts. One of the parts was invested at SI for N1 years at R% p.a. The other part was invested at CI for N2 years at R% p.a. Both parts fetched the same interest. Which of the following can be concluded?1)N12)N1>=N23)N1=N24)N1 not equal to N25)none
N1>= N2
4410
@amresh_maverick said:
Domain of f(x) =1/loga(b)a = base = 5-|x|b = root(x^3-7x^2+14x-8)a> (0, ˆž)b> ( -5, -4) U ( -4,4) U (4,5)c> (1,2) U (4,5)d> (1,2) U (4, ˆž)


C ??
4411
@pankaj1988 said:
A sum was split into two equal parts. One of the parts was invested at SI for N1 years at R% p.a. The other part was invested at CI for N2 years at R% p.a. Both parts fetched the same interest. Which of the following can be concluded?1)N12)N1>=N23)N1=N24)N1 not equal to N25)none
none??????
4412
@pankaj1988 said:
A sum was split into two equal parts. One of the parts was invested at SI for N1 years at R% p.a. The other part was invested at CI for N2 years at R% p.a. Both parts fetched the same interest. Which of the following can be concluded?1)N12)N1>=N23)N1=N24)N1 not equal to N25)none
3?
4413
@pankaj1988 said:
A sum was split into two equal parts. One of the parts was invested at SI for N1 years at R% p.a. The other part was invested at CI for N2 years at R% p.a. Both parts fetched the same interest. Which of the following can be concluded?1)N12)N1>=N23)N1=N24)N1 not equal to N25)none
2 ?
4414
@Brooklyn said:
2
@SarayuSheshadri said:
N1>= N2
@mailtoankit said:
3?
@19rsb said:
none??????
OA is N1>=N2...Bhai zara isko batana kaise hoga?
4415
@pankaj1988 said:
A sum was split into two equal parts. One of the parts was invested at SI for N1 years at R% p.a. The other part was invested at CI for N2 years at R% p.a. Both parts fetched the same interest. Which of the following can be concluded?1)N12)N1>=N23)N1=N24)N1 not equal to N25)none


N1>=N2

.................................
4416
@pankaj1988 said:
OA is N1>=N2...Bhai zara isko batana kaise hoga?
logic:

either N1=N2=1 then only SI = CI

or for some year N1 > N2 SI= CI as CI increases faster than SI
4417
@pankaj1988 said:
OA is N1>=N2...Bhai zara isko batana kaise hoga?
if number of years is 1 then SI = CI.. So then N1 = N2

otherwise CI for x years is always greater than SI for x years.. So N1 has to be greater than N2.. :)
4418
@pankaj1988 said:
OA is N1>=N2...Bhai zara isko batana kaise hoga?
if you take 1 year then both will be same..so = ka sign..
now when n1 != n2 us case mein...
n1 ko greater hona hoga..kyunki..C.I har saal jayada hota jayega...SI same rahta hai.
4419
@pankaj1988 said:
A sum was split into two equal parts. One of the parts was invested at SI for N1 years at R% p.a. The other part was invested at CI for N2 years at R% p.a. Both parts fetched the same interest. Which of the following can be concluded?1)N12)N1>=N23)N1=N24)N1 not equal to N25)none
N1>=N2 : CI >SI EXcept for n1=n2 = 1
4420
@pankaj1988 said:
A sum was split into two equal parts. One of the parts was invested at SI for N1 years at R% p.a. The other part was invested at CI for N2 years at R% p.a. Both parts fetched the same interest. Which of the following can be concluded?1)N12)N1>=N23)N1=N24)N1 not equal to N25)none
SI = P*R*N1/100

CI = P(1+R/100)^N2 -P

SI=CI
P*R*N1/100 = P(1+R/100)^N2 -P
R*N1/100 = (1+R/100)^N2 -1
= 1 +N2*R/100 + N2*(N2+1)(R/100)^2 + ....... -1

 =N2*R/100 + N2*(N2+1)(R/100)^2 +...........

N1 =N2 + N2*(N2+1)R/100 +..........


Clearly N1>=N2