Official Quant thread for CAT 2013

@sujamait said:
How many three digit numbers with distinct digits can be formed such that product of the digits is the cube of a positive integer?a)21 b)24 c)36 d)30 We are required to form different words with the help of the word INTEGER.Let x be the number of words in which I and N are never together and y be the number of words which begin with I and end with R,then x/y is--a)42 b)30 c)6 d)50
1.24
2.30???????
@sujamait said:
y = 4^a-1 + 4^-a-1 .If 'a' is real then the least value of 'y' is a)2/3 b)1/2 c)1/3 d)1
1/2?
@sujamait said:
How many three digit numbers with distinct digits can be formed such that product of the digits is the cube of a positive integer?a)21 b)24 c)36 d)30 We are required to form different words with the help of the word INTEGER.Let x be the number of words in which I and N are never together and y be the number of words which begin with I and end with R,then x/y is--a)42 b)30 c)6 d)50
1.

1 - none
8 - 124 k 6 numbers
27 = 139 k 6 numbers
64 = 248 k 6 numbers
125 = none
216 = 496 k 6 numbers, 893 k 6 numbers
343 = none
512 = none
729 = none
30 numbers

2. x = 7!/2! - 6!/2! = 720/2*6 = 2160

y = 5!/2! = 60

x/y = 36
There are 3 APs with same common diff. A: a1,a2....B:b1,b2....C:c1,c2.....
bm=a1,am/bm=6/5,cn=b1 and an/bn=8/7..find a1/c1
5:1
6:1
7:2
CBD


@krum
@19rsb said:
1.242.30???????
I gt 36,30 for both..PC hang ho gaya tha..Q ki source gayab ho gayi ab :/
@sonamaries7 5:1
@sujamait said:
I gt 36,30 for both..PC hang ho gaya tha..Q ki source gayab ho gayi ab :/
bhai 1st ka 36 kaise aa rha hai......thoda prakash daliye......2nd ka toh mera bhi 30 aa rha hai......

@sonamaries7 said:
There are 3 APs with same common diff. A: a1,a2....B:b1,b2....C:c1,c2.....bm=a1,am/bm=6/5,cn=b1 and an/bn=8/7..find a1/c15:16:17:2CBD@krum:
5:1??
@sujamait 1.30
2.36
@mailtoankit ,@rubikmath
approach plz?
@sonamaries7 said:
There are 3 APs with same common diff. A: a1,a2....B:b1,b2....C:c1,c2.....bm=a1,am/bm=6/5,cn=b1 and an/bn=8/7..find a1/c15:16:17:2CBD@krum:
getting 5:1
@sujamait said:
getting 5:1
approach?
@sonamaries7
tried with a series . common diff.=1 (say)
a : 5,6,7,8,...
am/bm = 6/5 --> m=2 here --> b : 4,5,6,7,...
similarly n=4 here and c4=4
--> c1=1
A hexagon is inscribed in a circle of r=14cm
3 of its sides are 22 each and the other 3 sides are equal. Find the length of the other 3 sides
4
6
8
7
@19rsb said:
bhai 1st ka 36 kaise aa rha hai......thoda prakash daliye......2nd ka toh mera bhi 30 aa rha hai......
9 toh ho gye 1to 9 //
baaki
3,9,8 - 6
9,6,4
8,1,1
9,3,1
8,4,2
ke combos..


@sonamaries7 said:
approach?
approach is like..making eqns are solving them..
let d be commn diff
so,
b1+(m-1)d = a1

a1+(m-1)d * 5 = 6* b1+m-1 d

c1 + n-1d=b1

7*a1+ n-1 d = 8 . b1+ n-1 d

solveing these we will get the ration
@sujamait said:
A Gardner planted 729 saplings in such a way that every row had as many saplings as every column.He then decides to plant one new sapling between every two saplings .How many new saplings would he have to plant?1)2180 2)2080 3)1980 4)1880
explain kardo yar 😃
@sujamait
distinct digits !! den 1,1,8 combo is not possible .ryt ?
@sujamait said:
9 toh ho gye 1to 9 //baaki3,9,8 - 69,6,48,1,19,3,18,4,2ke combos.. approach is like..making eqns are solving them..let d be commn diffso,b1+(m-1)d = a1a1+(m-1)d * 5 = 6* b1+m-1 dc1 + n-1d=b17*a1+ n-1 d = 8 . b1+ n-1 dsolveing these we will get the ration
digit distinct he 1 ques me so hw can u take 811 and 1 to 9...check my sol em getting 30
@sujamait said:
9 toh ho gye 1to 9 //baaki3,9,8 - 69,6,48,1,19,3,18,4,2ke combos..


yaar 8,1,1,...possible nhin hai shayad ........distinct poocha hai....!!!!!!!!
@sonamaries7 said:
A hexagon is inscribed in a circle of r=14cm3 of its sides are 22 each and the other 3 sides are equal. Find the length of the other 3 sides4687
8 is not possible. and 7 is also not possible as perimeter of circle is 88.
out of 4,6 I will go with 4 😛