Official Quant thread for CAT 2013

@krum said:
376.75, ispe mehnat kia hai pehle X and Y belong to the set of positive integers. The probability that a randomly chosen value of Y satisfies the equation |3X-13Y|= 2 is:Options 1) 1/82) 2/33) 3/134) Cannot be determined
y=1,2,4,5,7,8 .. it will give some x (int)
so,2/3 !
y = 4^a-1 + 4^-a-1 .If 'a' is real then the least value of 'y' is
a)2/3 b)1/2 c)1/3 d)1
@sujamait said:
y = 4^a-1 + 4^-a-1 .If 'a' is real then the least value of 'y' is a)2/3 b)1/2 c)1/3 d)1
b) 1/2
I applied AM>=GM.
@sujamait said:
y = 4^a-1 + 4^-a-1 .If 'a' is real then the least value of 'y' is a)2/3 b)1/2 c)1/3 d)1
is it b???????
@sujamait said:
y = 4^a-1 + 4^-a-1 .If 'a' is real then the least value of 'y' is a)2/3 b)1/2 c)1/3 d)1
d ??
A Gardner planted 729 saplings in such a way that every row had as many saplings as every column.He then decides to plant one new sapling between every two saplings .How many new saplings would he have to plant?
1)2180 2)2080 3)1980 4)1880
@19rsb said:
is it b???????
yeah i tthink.
@sujamait said:
A Gardner planted 729 saplings in such a way that every row had as many saplings as every column.He then decides to plant one new sapling between every two saplings .How many new saplings would he have to plant?
26*26*2 ?
@sujamait said:
y = 4^a-1 + 4^-a-1 .If 'a' is real then the least value of 'y' is a)2/3 b)1/2 c)1/3 d)1
1/2?
@sujamait said:
yeah i tthink.
can u put brackets in d q plz?? is it: 4^(a-1) + 4^(-a-1) ??
@sujamait said:
A Gardner planted 729 saplings in such a way that every row had as many saplings as every column.He then decides to plant one new sapling between every two saplings .How many new saplings would he have to plant?
26*27 = 702 ?
@sujamait said:
A Gardner planted 729 saplings in such a way that every row had as many saplings as every column.He then decides to plant one new sapling between every two saplings .How many new saplings would he have to plant?
26*27*2=1404????
@19rsb said:
26*27*2=1404????
i thot but options are diff .. i guess seems like diagnal wale bhi le rhe hein..
1404 + 676
@Brooklyn said:
can u put brackets in d q plz?? is it: 4^(a-1) + 4^(-a-1) ??
yup! sry for no bracs.
@rachit_28 said:
26*27 = 702 ?
it should be 1404.
@sujamait said:
i thot but options are diff .. i guess seems like diagnal wale bhi le rhe hein..1404 + 676 yup! sry for no bracs.
satya vachan.......
@sujamait said:
i thot but options are diff .. i guess seems like diagnal wale bhi le rhe hein..1404 + 676 yup! sry for no bracs.
then none of options matcht:

http://www.wolframalpha.com/input/?i=4%5E%28a-1%29+%2B+4%5E%28-a-1%29
@19rsb said:
satya vachan.......
@sujamait samajh nhi aa raha diagaolanl walo ki jagah kaha se bachegi, i took 3 by 3 and then tried :(
@Brooklyn said:
then none of options matcht:www.wolframalpha.com/input/?i=...
global minimum dekho usmein ...1/2 at a=0 ..de rakha hai
@rachit_28
matlab 4 ke beech mein 1 ..
How many three digit numbers with distinct digits can be formed such that product of the digits is the cube of a positive integer?
a)21 b)24 c)36 d)30

We are required to form different words with the help of the word INTEGER.Let x be the number of words in which I and N are never together and y be the number of words which begin with I and end with R,then x/y is--
a)42 b)30 c)6 d)50

@sujamait said:
How many three digit numbers with distinct digits can be formed such that product of the digits is the cube of a positive integer?a)21 b)24 c)36 d)30 We are required to form different words with the help of the word INTEGER.Let x be the number of words in which I and N are never together and y be the number of words which begin with I and end with R,then x/y is--a)42 b)30 c)6 d)50
1. 24
2. 36