@bullseyes said:A gold merchant has 9 coins.. wd one coin in them have an extra weight.. rest all of them weigh the same.. find minimum no. of weighing required to identify the extra weight coin?
2?
@amresh_maverick said:@gs4890 I am in .If ABCD is a quadrilateral and AB is parallel to CD , then cos B + cos A = ??sin C + sin Dcos C + cos D-(cos C + cos D)sin C - sin D
cos c + cos d ?
@bullseyes said:sure?? no less minimum weighing then 2??
Isse kam nahi ho paega agar aap antaryami na ho to :)
@amresh_maverick said:@gs4890 I am in .If ABCD is a quadrilateral and AB is parallel to CD , then cos B + cos A = ??sin C + sin Dcos C + cos D-(cos C + cos D)sin C - sin D
cos C + cos D
someone here asked for an IIFT kind of qs. here is one
Sarita comes from the city to visit her relatives living in a small town. She arrives in their home in the morning at seven o'clock. She has a very interesting piece of news from the
city which she conveys to the family with whom she is staying. There are 4 members in the family and it takes Sarita exactly 10 minutes to tell them the gossip. Now can you guess
how long it would take for this news to spread around all the 87,300 inhabitants of the town, if each person took just 10 minutes to tell it to another 4 people?
city which she conveys to the family with whom she is staying. There are 4 members in the family and it takes Sarita exactly 10 minutes to tell them the gossip. Now can you guess
how long it would take for this news to spread around all the 87,300 inhabitants of the town, if each person took just 10 minutes to tell it to another 4 people?
@amresh_maverick said:@gs4890 I am in .If ABCD is a quadrilateral and AB is parallel to CD , then cos B + cos A = ??sin C + sin Dcos C + cos D-(cos C + cos D)sin C - sin D
Aate hi dhamaka kar diya .. :P
@amresh_maverick said:@gs4890 I am in .If ABCD is a quadrilateral and AB is parallel to CD , then cos B + cos A = ??sin C + sin Dcos C + cos D-(cos C + cos D)sin C - sin D
c
sab koi neend mein hai kya ?
OA is -(cos C + cos D)
as AB is || to CD then A + D = 180 and B + C = 180 applying cos both sides
cos A = cos (180-D)
= - cos D
cos B = cos (180-C)
= - cos C
So cos A + cos B = -(cos C + cos D)
@amresh_maverick said:@gs4890 I am in .If ABCD is a quadrilateral and AB is parallel to CD , then cos B + cos A = ??sin C + sin Dcos C + cos D-(cos C + cos D)sin C - sin D
Cos C + Cos D ?
Pehle square banaya, fir trapezium se confirm kiya.
galat hua :banghead:
@bullseyes said:someone here asked for an IIFT kind of qs. here is oneSarita comes from the city to visit her relatives living in a small town. She arrives in their home in the morning at seven o'clock. She has a very interesting piece of news from thecity which she conveys to the family with whom she is staying. There are 4 members in the family and it takes Sarita exactly 10 minutes to tell them the gossip. Now can you guesshow long it would take for this news to spread around all the 87,300 inhabitants of the town, if each person took just 10 minutes to tell it to another 4 people?
90 mins
@bullseyes said:someone here asked for an IIFT kind of qs. here is oneSarita comes from the city to visit her relatives living in a small town. She arrives in their home in the morning at seven o'clock. She has a very interesting piece of news from thecity which she conveys to the family with whom she is staying. There are 4 members in the family and it takes Sarita exactly 10 minutes to tell them the gossip. Now can you guesshow long it would take for this news to spread around all the 87,300 inhabitants of the town, if each person took just 10 minutes to tell it to another 4 people?
90 MINS?
Minimum value of 2^sinx + 2^cosx
2^(2^1/2) - 2
2^1/2 -1
(_/2)^(2-_/2)
(_/2)^(1-1/_/2)
@amresh_maverick said:Minimum value of 2^sinx + 2^cosx2^(2^1/2) - 22^1/2 -1 (_/2)^(2-_/2)(_/2)^(1-1/_/2)
neend ka medicine de diya bhai 
@bullseyes said:someone here asked for an IIFT kind of qs. here is oneSarita comes from the city to visit her relatives living in a small town. She arrives in their home in the morning at seven o'clock. She has a very interesting piece of news from thecity which she conveys to the family with whom she is staying. There are 4 members in the family and it takes Sarita exactly 10 minutes to tell them the gossip. Now can you guesshow long it would take for this news to spread around all the 87,300 inhabitants of the town, if each person took just 10 minutes to tell it to another 4 people?
4 + 4^2 + 4^3 + ... 4^n >= 87300
=> 4/3*(4^n - 1) >= 87300 = > n = 8 approx
Ans = 10*n = 80 minutes ?
@amresh_maverick said:Minimum value of 2^sinx + 2^cosx2^(2^1/2) - 22^1/2 -1 (_/2)^(2-_/2)(_/2)^(1-1/_/2)
OPTION 2
@amresh_maverick said:Minimum value of 2^sinx + 2^cosx2^(2^1/2) - 22^1/2 -1 (_/2)^(2-_/2)(_/2)^(1-1/_/2)
d..at 5pi/4
@amresh_maverick said:Minimum value of 2^sinx + 2^cosx2^(2^1/2) - 22^1/2 -1 (_/2)^(2-_/2)(_/2)^(1-1/_/2)
c?