Official Quant thread for CAT 2013

MBA CAT 2024
3401
@maddy2807 said:
AGAIN...A contract is to be completed in 56 days and 104 men are set to work, each working 8 hours a day. After 30 days, 2/5th of the work in finished. How many additional men may be employed so that work may be completed on time, each man now working 9 hours per day? A. 56 men B. 65 men C. 46 men D. None of the abovemy last one for the day...over to u @gs4890 , @pankaj1988
56 ?
3402
@amresh_maverick - would you like to volunteer sir ?

Just to inform , IIFT quantitative event going on ;)
3403
@maddy2807 said:
AGAIN...A contract is to be completed in 56 days and 104 men are set to work, each working 8 hours a day. After 30 days, 2/5th of the work in finished. How many additional men may be employed so that work may be completed on time, each man now working 9 hours per day? A. 56 men B. 65 men C. 46 men D. None of the abovemy last one for the day...over to u @gs4890 , @pankaj1988
56 men
3404
@maddy2807 said:
AGAIN...A contract is to be completed in 56 days and 104 men are set to work, each working 8 hours a day. After 30 days, 2/5th of the work in finished. How many additional men may be employed so that work may be completed on time, each man now working 9 hours per day? A. 56 men B. 65 men C. 46 men D. None of the abovemy last one for the day...over to u @gs4890 , @pankaj1988
56
3405
@maddy2807 said:
AGAIN...A contract is to be completed in 56 days and 104 men are set to work, each working 8 hours a day. After 30 days, 2/5th of the work in finished. How many additional men may be employed so that work may be completed on time, each man now working 9 hours per day? A. 56 men B. 65 men C. 46 men D. None of the abovemy last one for the day...over to u @gs4890 , @pankaj1988
56
3406
@maddy2807 said:
AGAIN...A contract is to be completed in 56 days and 104 men are set to work, each working 8 hours a day. After 30 days, 2/5th of the work in finished. How many additional men may be employed so that work may be completed on time, each man now working 9 hours per day? A. 56 men B. 65 men C. 46 men D. None of the abovemy last one for the day...over to u @gs4890 , @pankaj1988
56?
3407
@gs4890 thanks for that. thoda detail mein samjhao . kis cheeez ka volunteer ?

main aapka sir nahi hoon
3408

OA is 56

3409
@amresh_maverick said:
@gs4890 thanks for that. thoda detail mein samjhao . kis cheeez ka volunteer ?main aapka sir nahi hoon
Each person volunteering will have to post 5 IIFT kinda Q's...thatz it 😃 event will continue till 3-4am fortunately :P

3410
@maddy2807 said:
AGAIN...A contract is to be completed in 56 days and 104 men are set to work, each working 8 hours a day. After 30 days, 2/5th of the work in finished. How many additional men may be employed so that work may be completed on time, each man now working 9 hours per day? A. 56 men B. 65 men C. 46 men D. None of the abovemy last one for the day...over to u @gs4890 , @pankaj1988
56.
3411
@amresh_maverick said:
@gs4890 thanks for that. thoda detail mein samjhao . kis cheeez ka volunteer ?main aapka sir nahi hoon
maddy,me & pankaj done with volunteering ; finding our next bakra now :P
3412
@maddy2807 said:
AGAIN...A contract is to be completed in 56 days and 104 men are set to work, each working 8 hours a day. After 30 days, 2/5th of the work in finished. How many additional men may be employed so that work may be completed on time, each man now working 9 hours per day? A. 56 men B. 65 men C. 46 men D. None of the abovemy last one for the day...over to u @gs4890 , @pankaj1988
30 * 8 * 104 = 2/5 * W -- (1)
26 * 9 * (104+x) = 3/5* W -- (2)

Above two equations yields x = 56
3413

A gold merchant has 9 coins.. wd one coin in them have an extra weight.. rest all of them weigh the same.. find minimum no. of weighing required to identify the extra weight coin?

3414
@gs4890 I am in .

If ABCD is a quadrilateral and AB is parallel to CD , then cos B + cos A = ??

sin C + sin D
cos C + cos D
-(cos C + cos D)
sin C - sin D
3415
@bullseyes said:
A gold merchant has 9 coins.. wd one coin in them have an extra weight.. rest all of them weigh the same.. find minimum no. of weighing required to identify the extra weight coin?
2
3416
@bullseyes said:
A gold merchant has 9 coins.. wd one coin in them have an extra weight.. rest all of them weigh the same.. find minimum no. of weighing required to identify the extra weight coin?
2?
3417
@amresh_maverick said:
@gs4890 I am in .If ABCD is a quadrilateral and AB is parallel to CD , then cos B + cos A = ??sin C + sin Dcos C + cos D-(cos C + cos D)sin C - sin D
cos C + cos D
3418
@bullseyes said:
A gold merchant has 9 coins.. wd one coin in them have an extra weight.. rest all of them weigh the same.. find minimum no. of weighing required to identify the extra weight coin?
2 ?

3 3 3
1 1 1
3419
@bullseyes said:
A gold merchant has 9 coins.. wd one coin in them have an extra weight.. rest all of them weigh the same.. find minimum no. of weighing required to identify the extra weight coin?
2?
3420
@maddy2807 said:
2?
@deedeedudu said:
2
sure?? no less minimum weighing then 2??