120 - 144 -->25 numbersBox 1-25, 26-50, 51-75, 76-100, 101-125, 126, 127 and 128So total of 6 boxes, isn't it?? ( With same numbers )
Ahaan! I interpreted the question in a different way.
Raju has to put atleast 120 Oranges in one box and maximum he has 144 Oranges which can be put all together too.
So, taking 120 Oranges in Box 1, we are left with 144 - 120 = 24 Oranges. Now he can put one orange each in next 24 boxes leaving behind 128 - 1 - 24 = 103 Boxes having no oranges which is the least number of boxes having same number of Oranges.
Ahaan! I interpreted the question in a different way.Raju has to put atleast 120 Oranges in one box and maximum he has 144 Oranges which can be put all together too.So, taking 120 Oranges in Box 1, we are left with 144 - 120 = 24 Oranges. Now he can put one orange each in next 24 boxes leaving behind 128 - 1 - 24 = 103 Boxes having no oranges which is the least number of boxes having same number of Oranges.This is how I solved this question! I too missed the thread a lot. Aaj raha nahin gaya and so aa gaya kaam karte karte!
But each box can hold 120 to 144 oranges,but the by your method,the tota# of l oranges itself
But each box can hold 120 to 144 oranges,but the by your method,the tota# of l oranges itself 144,right?
Yeah I took total oranges as 144 as it said ''144 at the most''. Either that was for upper limit of the capacity of box or else the number of oranges. If capacity taken, then the number of oranges won't have any fixed limit. So, I took it the other way. Might be wrong. Dunno! :|
