@zuloo If you plot the graph for the given equation of circle ...center @ (1,-2) with radius as 2sqrt6, and you need to get the largest value for y/x
Any point on the circle on the 2nd and 4th quadrant will give you a negative value (y/x wont be max plus maximum you can get if y is having the max value) Possible case rests in 1st quadrant only where y is at its max ...ie
let d run rate before bea therefore total runs = 30a , now wenais increased by 33.33%a becomes 4/3a now20*4/3a = 30 * a=>8=9 kya galat kar raha hoon sir @ScareCrow28
@ScareCrow28 sir ji i just noticed that i mentioned the question wrongly. Its actually 20% less overs instead of 20 overs absolute value . So that means its 40 overs right?. But the answer as per the book is CBD. But i was wondering if we solve through options we arrive at 250 as the answer. Correct me if am wrong. Pardon me for the mistake everyone.
@ScareCrow28 sir ji i just noticed that i mentioned the question wrongly. Its actually 20% less overs instead of 20 overs absolute value . So that means its 40 overs right?. But the answer as per the book is CBD. But i was wondering if we solve through options we arrive at 250 as the answer. Correct me if am wrong. Pardon me for the mistake everyone.
Bhaiya jee.. sir mat bolo
See, the options also have a CBD in it, that's why the answer should be CBD
If the question would have been choose from the options below and there were no CBD then you could have marked 250. Hope you get the point
no sir not possible hogi dekho iske liye aur info ki zaroorat nahi dekho main bhale kitni bhi runrate se khel raha hoon par agar 30 over ka score 20 over mein banvana hai to hume RR 50% se badhani padegi30*a = 20*3a/2=>6=6???watsay?
sir how can u b so sure? dat d difference of 6,12,18,24,30 with d first will all result in a prime number .......kuch samajh ni aaya sir
bhai han wohi....it actually would be of 6k form (that we can be sure of) but since the options weren't available so i said 6.....but 6k hoga.......baaki samajh nahi aa raha kaise hoga..
From 40 litres of 2:3 Milk Water Solution , 8 litres are withdrawn and replaced by 8 litres of milk. What is the minimum number of times the operation has to be carried out of withdrawing and replacing so that the milk concentration is atleast 60 %.
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From 40 litres of 2:3 Milk Water Solution , 8 litres are withdrawn and replaced by 8 litres of milk. What is the minimum number of times the operation has to be carried out of withdrawing and replacing so that the milk concentration is atleast 60 %.