@RRD2 said:What is the least number which when divided by 42,72, and 84 leaves the remainders 24, 56 and 68 respectively?
I think it should be 26.
Then answer is 588
Then answer is 588
@RRD2 said:What is the least number which when divided by 42,72, and 84 leaves the remainders 24, 56 and 68 respectively?
72->-16
84->-16
12*42 -16
see this no will give remainder -16(or 26) with 42
hence such no is not possible
@RRD2 said:@dushyantagarwal@Subhashdec2 None of these ( Not such any no. possible) !
right 
.. I thought it was not meant for "None of these". So inferred to be a typo.
My Bad
.. I thought it was not meant for "None of these". So inferred to be a typo. My Bad
There are 50 coins on the table. A & B play a game. They can pick 1 - 5 coins. How many coins should A pick inorder to win the game.?
i) If the one who picks last one loses the game
ii) If the one who picks the last one wins the game
Plz explain.. (Forgot the trick) :(
@psk.becks said:In a chess tounament everybody plays everybody else.Everyone scored the same number of points, except four players whose total score were 17.5.Which of the following can be the number of players participating in the tourmanent. Assume that for each win a player scores 1 point , for draw 1/2 point and zero for losing.
a. 27b. 29c. 31d. 42
27 ??
@sbharadwaj said:There are 50 coins on the table. A & B play a game. They can pick 1 - 5 coins. How many coins should A pick inorder to win the game.? i) If the one who picks last one loses the gameii) If the one who picks the last one wins the gamePlz explain.. (Forgot the trick)
1)controlling factor=1+5=6
so u should make sure 6k+1 coins are left always
k=8
pick 1
2)in the second game i think you should make sure 6k coins are left
so pick 2
@sbharadwaj said:There are 50 coins on the table. A & B play a game. They can pick 1 - 5 coins. How many coins should A pick inorder to win the game.? i) If the one who picks last one loses the gameii) If the one who picks the last one wins the gamePlz explain.. (Forgot the trick)
For the 1st case A has to ensure that the no of coins remaining on the table should be of the form 6K (1+5)+1
For the second case, the no of coins should be of the form 6K
Puys please help with the following :-
Q. Australia scored a total of x runs in 50 overs . India tied the scores in 20 overs less. If India's average run rate ad been 33.33% higher the scores would have been tied10 overs earlier.
Find how many runs were scored by Australia?
(a) 250 (b) 240 (c) 200 (c) can not be determined
(a) 250 (b) 240 (c) 200 (c) can not be determined
Thanks in adv
What is the smallest positive common difference of a 6-term arithmetic progression consisting entirely of (positive) prime numbers?
@sbharadwaj of course assuming that both know how to whip the opponent.
1. he who picks the last coin/s loses. Which means A should leave 1 coin, or 7 coins(then B can pick 5 at max and then A will pick 1 and B has to pick the last one), or 13(B picks 5, A picks 1 leaving B with 7 and hence the previous case).
1. he who picks the last coin/s loses. Which means A should leave 1 coin, or 7 coins(then B can pick 5 at max and then A will pick 1 and B has to pick the last one), or 13(B picks 5, A picks 1 leaving B with 7 and hence the previous case).
So the logic is =[Maximum coins opponent can pick+Minimum coins subject can pick+Last coin]=5n+n+1=6n+1
nearest number with 6n+1=49 so he should pick 1 coin
2. he who picks the last wins. Similar to above case, just that now he will aim at leaving one coin for himself. So A should leave 6 coins(B picks 5 and A makes the winning pick) OR 12(Then B would attempt to leave 6 coins which he cannot. He can only pick 5. A picks 1 leaving 6.). Once again the logic is (Max of opponent +Minimum )=6n... hence he picks 2 coins
@psk.becks said:In a chess tounament everybody plays everybody else.Everyone scored the same number of points, except four players whose total score were 17.5.Which of the following can be the number of players participating in the tourmanent. Assume that for each win a player scores 1 point , for draw 1/2 point and zero for losing.a. 27 b. 29c. 31d. 42
Let N be total number of palyers
Total points be N(N-1)/2*3/2=(N-4)*x+17.5
Check with options
27
Total points be N(N-1)/2*3/2=(N-4)*x+17.5
Check with options
27
@gnehagarg said:Let N be total number of palyersTotal points be N(N-1)/2*3/2=(N-4)*x+17.5Check with options27
y the total no of points is n(n-1)/2 *3/2?
there is just 1 point to be won at max in a game
shouldnt it be n(n-1)/2
@Subhashdec2 said:y the total no of points is n(n-1)/2 *3/2?there is just 1 point to be won at max in a gameshouldnt it be n(n-1)/2
Ya,Your are right.Sorry,for my mistake
@DreamBikerzz said:Puys please help with the following :-Q. Australia scored a total of x runs in 50 overs . India tied the scores in 20 overs less. If India's average run rate ad been 33.33% higher the scores would have been tied10 overs earlier.Find how many runs were scored by Australia?(a) 250 (b) 240 (c) 200 (c) can not be determinedThanks in adv
CBD ?
can anyone tell me the shortcut to the following Q: x^2+y^2-2x+4y-19=0 find the largest value of y/x.
@DreamBikerzz said:Puys please help with the following :-Q. Australia scored a total of x runs in 50 overs . India tied the scores in 20 overs less. If India's average run rate ad been 33.33% higher the scores would have been tied10 overs earlier.Find how many runs were scored by Australia?(a) 250 (b) 240 (c) 200 (c) can not be determinedThanks in adv
cbd ?
@DreamBikerzz said:@ScareCrow28 Yup CBD. But approach please . And cannot we solve this using options?
Just can't find any solution with the given info. I can tell you how I proceeded.
Run rate = x/30
33.33% higher means, now it becomes = 4x/90
So, 4x/90 * 20 = x
We can't find "x"
