@The_Loser said:34^2020.last two digit.
2^2020 *17^2020
(2^10)^202 = 76
17^2020=89^1010
11^1010=01
76*01=76??
@The_Loser said:34^2020.last two digit.
@Logrhythm said:smallest 4 digit number in base 4 = 64largest 4 digit number in base 4 = 255smallest 4 digit number in base 3 = 27largest 4 digit number in base 3 = 80we need from 62 to 80 and only 72 out of these leave a remainder of 0 with 12, hence only 1 solution...
@vbhvgupta said:a reduction of 10% in the price of sugar enablesa person to buy 6.2kg more for rs 279. find the reduced price per Kg.
@vbhvgupta said:a reduction of 10% in the price of sugar enablesa person to buy 6.2kg more for rs 279. find the reduced price per Kg.
@KhannaiiM said:A 4 digit number X in base 4 when converted to base 3 gives a 4 digit number.When X is expressed in base 12 ,it has a zero in its unit digit.Find total number of such numbers?
@vbhvgupta said:a reduction of 10% in the price of sugar enablesa person to buy 6.2kg more for rs 279. find the reduced price per Kg.
@2013IsMine said:let price be Pquantity=279/pnew price =0.9Pquantity=279/0.9p=310/Pdiffernce =6.2310/p-279/p=6.21/p(31)=6.2P=5reduced price=4.5
@scrabbler said:76?4k and 25m+1regardsscrabbler
2^2020 * 17^2020
@vbhvgupta said:a reduction of 10% in the price of sugar enablesa person to buy 6.2kg more for rs 279. find the reduced price per Kg.