Abbe kamina.....Ye sawal bachche logo ke liye hai....Tere jaise experienced logo ke liye nahi........!!!!!!!!!Tu ye solve kar1)A stick is randomly broken into 3 pieces. What is the probability that the pieces will form a triangle?
Abbe kamina.....Ye sawal bachche logo ke liye hai....Tere jaise experienced logo ke liye nahi........!!!!!!!!!Tu ye solve kar1)A stick is randomly broken into 3 pieces. What is the probability that the pieces will form a triangle?
Suppose a stick is broken in 3 parts (x1, x2, x3).
the only way that these can form a triangle if max(x1,x2,x3)
and x1+x2+x3=1
Prob ( max(X1, X2, 1- X1-X2)
{Consider the X1, X2 as X-Y axis and draw the diagram with 1-X1-X2 as a line}
Suppose a stick is broken in 3 parts (x1, x2, x3). the only way that these can form a triangle if max(x1,x2,x3) and x1+x2+x3=1 Prob ( max(X1, X2, 1- X1-X2) {Consider the X1, X2 as X-Y axis and draw the diagram with 1-X1-X2 as a line}
could you elaborate with the XY axis diagram? i am not able to visualize it.. Kindly help me understand your approach
1> What is the no of three digit perfect squares that exist in base 5 system ?2> Two 1 X 1 squares are selected on a 8X8 chessboard. Prob that the selected squares have a common side ?PS: Dinner time
bhai yeh dono sawalo ka approach post karo.. i am not comfortable with this base system conversion.. koi short-cut hai kya?
Not really a short cut. I just thought - to be a 3-digit number in a base x, the number (in base 10) should lie in the range [x^2, x^3) in this case, [25, 125) so squares from 5 till 11 = 7 values.
Chessboard, looked at the squares as ordered pairs. Total 64 * 63 ways of selecting. But in the numerator, 1st square could be a corner (having 2 squares sharing a border) or a side (3 ditto) or an interior square (4 ditto). So 4 * 2 + 24 * 3 + 36 * 4 = 224 out of 64 * 63 which gave me 1/18. regards scrabbler
Suppose a stick is broken in 3 parts (x1, x2, x3). the only way that these can form a triangle if max(x1,x2,x3) and x1+x2+x3=1 Prob ( max(X1, X2, 1- X1-X2) {Consider the X1, X2 as X-Y axis and draw the diagram with 1-X1-X2 as a line}
Suppose a stick is broken in 3 parts (x1, x2, x3). the only way that these can form a triangle if max(x1,x2,x3) and x1+x2+x3=1 Prob ( max(X1, X2, 1- X1-X2) {Consider the X1, X2 as X-Y axis and draw the diagram with 1-X1-X2 as a line}
Don't forget that your sample space is a triangle bounded by x+y = 1 with area 1/2. So P will be (1/8 / 1/2) = 1/4. regards scrabbler
1> What is the no of three digit perfect squares that exist in base 5 system ?2> Two 1 X 1 squares are selected on a 8X8 chessboard. Prob that the selected squares have a common side ?PS: Dinner time
1. 7 2. 1/14 (divide in columns of 2 each, We have 4X2 = 8 columns. Consider each sections of 2 conseutive columns, Horizontally we can select 8 pairs, Vertically 8 pairs and diagonally 7X2= 14 pairs. Total 8+8+14 = 30 pairs.
We have 7 such grids of 2 consecutive columns each, so total pairs = 30X7 = 210.
bhai yeh dono sawalo ka approach post karo.. i am not comfortable with this base system conversion.. koi short-cut hai kya?
in base system 10 no of three digit nos.is 10^2 till 10^3-1 similarly in every base system d same pattern is followed so in base 5 is 5^2 to 5^3-1..hope it helps!!
...see.. this is what i fear in Pnc... story mein bin baat k twist.