Official Quant thread for CAT 2013

@bs0409 said:
@ChirpiBirdOA-465......Find the value of k such that sum of square of the roots of the quadartic equation x^2-8x+k=0 is 40a)12b)2c)5d)8
12..

(a+b)^2 - 2ab=40
64-2k=40
k=12
@ChirpiBird said:
i hate Pnc ....(also Probability). thanks anyway.
It's easy....once you sit down and understand (prove everything to yourself) ek baar. Otherwise it can be a nightmare I agree....

regards
scrabbler

@Logrhythm said:
12??did it with options...
bro this is a^2+b^2 = (a+b)^2-2ab
a+b = -8
a^2+b^2 = 40
bas itna hi karna hai.. if i am not wrong
@bs0409 said:
OA-12Two cards are drawn together from a pack of 52 cards. The probability that one is a spade and one is a heart, is: A)3/20B)29/34C)47/100D)13/102
D)13/102

13C1*13C1/52C2
@bs0409 said:
OA-12Two cards are drawn together from a pack of 52 cards. The probability that one is a spade and one is a heart, is: A)3/20B)29/34C)47/100D)13/102
d? 13/102
@bs0409 said:
OA-12Two cards are drawn together from a pack of 52 cards. The probability that one is a spade and one is a heart, is: A)3/20B)29/34C)47/100D)13/102
sample space = 52c2
favourable event = 13c1*13c1
p(e) = option d...
@bs0409 said:
OA-12Two cards are drawn together from a pack of 52 cards. The probability that one is a spade and one is a heart, is: A)3/20B)29/34C)47/100D)13/102
13c1*13c1/52c2 = 13/102 ?
@bs0409 said:
OA-12Two cards are drawn together from a pack of 52 cards. The probability that one is a spade and one is a heart, is: A)3/20B)29/34C)47/100D)13/102
( 13c1 * 13c1 )/52c2
d?

@iLoveTorres said:
bro this is a^2+b^2 = (a+b)^2-2aba+b = -8a^2+b^2 = 40 bas itna hi karna hai.. if i am not wrong
bhai i knw...but in case of algebra (or variable based questions) i am more comfortable using options.... :)
@bs0409 said:
@ChirpiBirdOA-465......Find the value of k such that sum of square of the roots of the quadartic equation x^2-8x+k=0 is 40a)12b)2c)5d)8
12.
@Logrhythm said:
bhai i knw...but in case of algebra (or variable based questions) i am more comfortable using options....
same here.. also in questions on AP GP options based approach is time saver :)
@joyjitpal said:
D)13/10213C1*13C1/52C2
@iLoveTorres said:
d? 13/102
@Logrhythm said:
sample space = 52c2favourable event = 13c1*13c1 p(e) = option d...
@mailtoankit said:
13c1*13c1/52c2 = 13/102 ?
@ChirpiBird said:
( 13c1 * 13c1 )/52c2 d?

ANS -D)13/102

Two cards are drawn together from a pack of 52 cards. The probability that one is a spade and one is a king, is??

@scrabbler said:
It's easy....once you sit down and understand (prove everything to yourself) ek baar. Otherwise it can be a nightmare I agree....regardsscrabbler
i just know to solve some trademark questions. lol.. that's it ..rest is nightmare.
Although i do get when someone explains it to me.
yep, u r right, i need to get to the basics. :)
@karl said:
12.

Abbe kamina.....
Ye sawal bachche logo ke liye hai....
Tere jaise experienced logo ke liye nahi........!!!!!!!!!

Tu ye solve kar

1)A stick is randomly broken into 3 pieces. What is the probability that the pieces will form a triangle?

1> What is the no of three digit perfect squares that exist in base 5 system ?

2> Two 1 X 1 squares are selected on a 8X8 chessboard. Prob that the selected squares have a common side ?

PS: Dinner time

@bs0409 said:
ANS -D)13/102Two cards are drawn together from a pack of 52 cards. The probability that one is a spade and one is a king, is??
8/221?
@bs0409 said:
ANS -D)13/102Two cards are drawn together from a pack of 52 cards. The probability that one is a spade and one is a king, is??
8/221?
@amresh_maverick said:
1> What is the no of three digit perfect squares that exist in base 5 system ?

7?

25
@amresh_maverick said:
2> Two 1 X 1 squares are selected on a 8X8 chessboard. Prob that the selected squares have a common side ?

1/18?

regards
scrabbler

@amresh_maverick said:
1> What is the no of three digit perfect squares that exist in base 5 system ?2> Two 1 X 1 squares are selected on a 8X8 chessboard. Prob that the selected squares have a common side ?PS: Dinner time
1) 7??
25 to 121 (both included)

2) 112/64c2 = 1/36?? (not sure, weak in chess :p)
@amresh_maverick said:
2> Two 1 X 1 squares are selected on a 8X8 chessboard. Prob that the selected squares have a common side ?PS: Dinner time

Shld be (36*4+24*3+4*2)/64P2=1/18