What annual payment will discharge a debt of Rs.580 in 5 years, the rate being 8% p.a??
How many pairs of integers are there such that twice the sum of the integers is equal to their product?
Find the Remainder when 39! is divided by 41.
How do I solve this problem ?
The sum of 60 positive integers is 1201.What is the minimum possible value of the L.C.M of these numbers?
a)24 b)21 c)40 d)22
The given answer is 22
In how many ways can place one black and one white king on chess board so that they do not attack each other?
Explain approach
A person has twenty friends.He wants to organize a party in which he wants to invite same number of friends.
1)Max party he can organize?
2)Each friend will be invited in how many party?
Explain approach
There are 6 dancers which may perform in any order.In how many ways one dancer named a can perform before dancer b.....approach
?
A regular polygon has even number of sides. if the product of the length of its side & distance between two opposite sides is 0.25 of its area, find the number of sides it has.
if there are 1000 people sitting in a circle and starting from 1st person every second person is killed for ex(1,3,5...and so on) are killed... which position number person will remain alive?
Josephus problem.
A group of n people are standing in a circle, numbered consecutively clockwise from 1 to n. Starting with person no. 2, we remove every other person, proceeding clockwise. For example, if n = 6, the people are removed in the order 2, 4, 6, 3, 1, and the last person remaining is no. 5. Let j(n) denote the last person remaining. Find some simple way to compute j(n) for any positive integer n > 1.
Solution.
The answer also can be expressed as j(n) = 2m + 1, where m = n − 2k, 2k = maximum power of 2 not exceeding n, i.e., 2k(less than ) n (less than) 1. (2) Finally, if n = 2k + m, where 0 m n, we start by removing the m people numbered 2, 4, 6, . . . , 2m. Now we have a circle with 2k people, and the "first one" (which will remain at the end) at that point is no. 2m + 1.
2013! + P + 2013 should be a prime number. How many such P-s are there such that P is between 1 and 2013!
options: 0, 1, 1998, 2099, 2000
how to do?
A vessel is filled with liquid,3 parts of which are water & 5 parts are syrup.How much of the mixture must be drawn off & replaced with water so that the mixture maybe half water and half syrup?
a.1/3
b.1/4
c.1/5
d.1/7
e.None
A horse race is to be conducted between 25 horses. Each race can only be competed between 5 horses. What is the minimum number of races to be conducted so as to find the fastest 3 horses among the 25?
Hey folks !
CAT-15 is ON, so which test series you planning to join ?
GoodNight
How many numbers less than 720 have their sum of digits a prime number?
CONDITION FOR TWO YEARS HAVING THE SAME CALENDER.
**Two years will have the same calender if the period(no. of days between the two years) between them is divisible by 7 or the sum of all the odd days in the period is divisible by 7.
Note: Odd days in a normal (non leap year) consisting of 365 days is 1 as 365 = 7*52 + 1
Similarly, in a leap year consisting of 366 days, number of odd days = 2 as 366= 7*52 + 2
Non Leap year Leap year
Odd days 2 1
For e.g
Ques. The calendar for the year 2007 will be the same for the year: [A]. 2014 [B]. 2016 [C]. 2017 [D]. 2018
Sol: Calculate the number of odd days between the year given in question to the year preceding the one given in each option.
Case [A], 2014 Calculate odd days for the years 2007 - 2013 (i.e beginning from 2007 till the complete year 2013)
Year: 2007 2008 2009 2010 2011 2012 2013 Sum
Odd days: 1 2 1 1 1 2 1 9
Case [B], 2016 Calculate odd days for the years 2007 - 2015 (i.e beginning from 2007 till the complete year 2015)
Year: 2007 2008 2009 2010 2011 2012 2013 2014 2015
Odd days: 1 2 1 1 1 2 1 1 1
Sum of odd days = 11
Case [C], 2017 Calculate odd days for the years 2007 - 2016 (i.e beginning from 2007 till the complete year 2016)
Year: 2007 2008 2009 2010 2011 2012 2013 2014 2015 2016
Odd days: 1 2 1 1 1 2 1 1 1 2
Sum of odd days = 13
Case [D], 2018 Calculate odd days for the years 2007 - 2017 (i.e beginning from 2007 till the complete year 2017)
Year: 2007 2008 2009 2010 2011 2012 2013 2014 2015 2016 2017
Odd days: 1 2 1 1 1 2 1 1 1 2 1
Sum of odd days = 14
Now in only case [D] , the sum of odd days in the given period is divisible by 7. So the calender of 2007 is same as of 2018.
Find the number of solutions : x* 3^x = 1
32!+33!+34!+......90!, find the highest power of 2.
Three varieties of rice A,B and C costing Rs6 /kg ,Rs 9/kg and Rs 12 / kg are mixed together in a certain ratio.The mixture is sold at 200/3 % profit for Rs 15/ kg .Of the total of 100 kg of the. Mixture ,50 kg is variety B.
Find the quantity of variety A in kgs
Plz elaborate the steps
Two typists undertake to do a job. The second typist begins working one hour after the first. Three hours after the first typist has begun working, there is still 9/20 of the work to be done. When the assignment is completed, it turns out that each typist has done half the work. How many hours would it take each one to do the whole job individually ?
Provide the solution, please!