@pavi.k said: @Vineeth555remainder is 1...((26-1)^2)/26=(-1)^2= 1...
bro, i thought the exponent was 25 ( an odd number).. thats why I posted 25..
@pavi.k said:
i have read an impenetrable fort and impregnable fortress.. and the former sounded better 
thats why.. thanks anyways
thats why.. thanks anyways
@sampras
@sampras said:Bhai it should be... -1 as (26-1)25 / 26 .... will give remainder (-1)^25Remember when (a-1)^n is divided by a... then the remainder is (-1)^n
Just logically think how can we have negative remainder ..
@abhi_1234 said: @samprasJust logically think how can we have negative remainder ..
if n is odd then (-1)^n = -1 In the qn its 25^25 and not 25*25 is it???
A clock is showing right time at 12 pm. After this, it started gaining 15 minutes per hour. SO, when the clock shows 5 pm, what is the actual time?
a. 4.30 pm b. 5 pm c. 4.00 pm d. 3.30 pm
@sampras said:if n is odd then (-1)^n = -1 In the qn its 25^25 and not 25*25 is it???
acha bhai going by your own method
as you said (a-1)^n when divided by a remainder is (-1)^n
now you put a= 4 n= 3(odd)
AND NOW YOU TELL ME WHAT IS THE REMAINDER
as you said (a-1)^n when divided by a remainder is (-1)^n
now you put a= 4 n= 3(odd)
AND NOW YOU TELL ME WHAT IS THE REMAINDER
@Vineeth555 said: A clock is showing right time at 12 pm. After this, it started gaining 15 minutes per hour. SO, when the clock shows 5 pm, what is the actual time? a. 4.30 pm b. 5 pm c. 4.00 pm d. 3.30 pm
4 pm ??
@abhi_1234 said:acha bhai going by your own method as you said (a-1)^n when divided by a remainder is (-1)^nnow you put a= 4 n= 3(odd) AND NOW YOU TELL ME WHAT IS THE REMAINDER
obviously .... its 3.... you r correct...thanx
@abhi_1234
Q. when (67^67 +67) is divided by 68 the remainder is ...
please explain the logic and method involved .... as confused in Binomial expansion...
@sampras said: @abhi_1234Q. when (67^67 +67) is divided by 68 the remainder is ...please explain the logic and method involved .... as confused in Binomial expansion...
66????gud mng
@sampras said: @abhi_1234Q. when (67^67 +67) is divided by 68 the remainder is ...please explain the logic and method involved .... as confused in Binomial expansion...
by bifurcating it........
67^67/68 = -1
Now -1+67 = 66, which z less than 68; Hence d reminder...
@sampras bhai and all the bhai log
yaar actually
there is an question which is been regularly asked in SSC
like they would have given some value of x and will say us to find the value of the equation with x....
for ex=x=2-rt3
then find something like x^5+something
is there any trick to do that...if yes then thoda prakash daliye...+if possible aise thode questions ki practice karva dijiye
@JS-M said:by bifurcating it........67^67/68 = -1Now -1+67 = 66, which z less than 68; Hence d reminder...
hmmmm I too had the same result... what about the Qn by @sandy73 this morning...
1) when 25^25 is divisible by 26, the remainder is ___________
got confused on discussion on this qn with ... @abhi_1234
@sampras said:hmmmm I too had the same result... what about the Qn by @sandy73 this morning...1) when 25^25 is divisible by 26, the remainder is ___________got confused on discussion on this qn with ... @abhi_1234
25 hoga yr.......same logic, don't need any binomial for such questions where there z nly single term...
@gudda1122 said: @sampras bhai and all the bhai logyaar actuallythere is an question which is been regularly asked in SSClike they would have given some value of x and will say us to find the value of the equation with x....for ex=x=2-rt3then find something like x^5+somethingis there any trick to do that...if yes then thoda prakash daliye...+if possible aise thode questions ki practice karva dijiye
yeah in these type of qns take the rt part on one side... develop the expn... then use it as divisor and divide the given expn by it in traditional way... will get the remainder or the quotient as required.... I used to do like this.... its kachha method for me and is working till now... donno any authenticated one... anyone ... if knows please do provide...
waise mera admit card aa gaya hai
for the 1st Time my center is near my home
Uttam nagar -holy convent school and my home is in Janakpuri west
@sampras said:yeah in these type of qns take the rt part on one side... develop the expn... then use it as divisor and divide the given expn by it in traditional way... will get the remainder or the quotient as required.... I used to do like this.... its kachha method for me and is working till now... donno any authenticated one... anyone ... if knows please do provide...
and @JS-M bhai iske thode questions hai toh post karna :)