what is your paper attempting strategy???????
@sampras and @JS-M and all the other people who are right now Online on this thread
@Vineeth555 said: A clock is showing right time at 12 pm. After this, it started gaining 15 minutes per hour. SO, when the clock shows 5 pm, what is the actual time? a. 4.30 pm b. 5 pm c. 4.00 pm d. 3.30 pm
4 pm??
@gudda1122 said:and @JS-M bhai iske thode questions hai toh post karna
Q. if x = (root3 + 1)/2
then
4x^3+2x^2 - 8x + 7 is....
then
4x^3+2x^2 - 8x + 7 is....
@sampras said: @abhi_1234Q. when (67^67 +67) is divided by 68 the remainder is ...please explain the logic and method involved .... as confused in Binomial expansion...
-^67 + -1 = -2 = 66
@gudda1122 : sirji maine to tier1 bina prep ke diya tha....i came back on fri after being rejected by Air Force in SSB
sat rest kiya sun to de ke aagya.... jo aate the attempt kiye rest left
same dis tym :)
@gudda1122 said:and @JS-M bhai iske thode questions hai toh post karna
If iota = rt(-1) , then {cos(pie/3) + iota* sin(pie/3)}^3 = ??
@gudda1122 said: waise mera admit card aa gaya haifor the 1st Time my center is near my homeUttam nagar -holy convent school and my home is in Janakpuri west
sexy hai yar!! mera Rohini !!! n i live in south delhi laga di meri again
@gudda1122 said: @sampras bhai and all the bhai log
yaar actuallythere is an question which is been regularly asked in SSClike they would have given some value of x and will say us to find the value of the equation with x....for ex=x=2-rt3then find something like x^5+somethingis there any trick to do that...if yes then thoda prakash daliye...+if possible aise thode questions ki practice karva dijiye
yar dekho coz odd power soo here first find x^2
den x^3= x^2 * x n so on simple method hai i knw
@Brooklyn said:yar dekho coz odd power soo here first find x^2den x^3= x^2 * x n so on simple method hai i knw@gudda1122 : mere doubts nhi solve kiye dose i had tagged u in mrng
bhai just abhi so kar utha hu chai pee rha hu....
abhi solve karta hu pakka se :)
some important formulas...as this time paper will be flooded with trigno
sine 15= (rt3-1) /2rt2
sine 18= (rt5-1)/4
sine 36=( 10-2rt5)/4
sine 22.5= (rt(2-rt2))/2
all dese values are actually asked indirectly.so byheart
prism
VOLUME= area of base x height
LSA= perimeter of base x height
TSA= LSA +2 x Area
pyramid
VOLUME = (1/3) x area of base x height
LSA= (1/2) X perimeter of base x height
TSA = LSA + area
imp questions:
* cow tethered at corner of squares; cost of painting room ; digging of well ; circumference & speed ; radian to degree ; all trigno/algrebra questions from kiran ; DCT TCT; train meeting*
@Brooklyn said:-^67 + -1 = -2 = 66
got it bhai .... as the days are nearing getting confused in small- small concepts even...donn know god will only save
@gudda1122 bhai my strategy is to cover the whole Qn in one go ... if any qn i feel will take more than 1.2 mnts... will skip n move forward... which is the most difficult part... as the temptation can't be overcome...going thru the whole qn paper (maths) once solving the easy ones and less time consuming ones... then will come back to the lengthier ones..
though first I start from stats part .... good 20 marks ... easy takeaway... donn exhausts your brain ... just the calculations...then number system... algebra.... easy trigo n geo qns... then time work, time dist... followed by CP SP problems... which are weak points...
And in worst case if unable to even 50% will go for do or die... bubbling either option C or D...
as acc to my research on this ... 29/100 C options were there in CGL 11 and 24/100 D options were there.... and even in other recent exams the pattern is same... ha ha ha ... just going by luck if at all required...will not advise others following here...
@Brooklyn said: @gudda1122 : sirji maine to tier1 bina prep ke diya tha....i came back on fri after being rejected by Air Force in SSBsat rest kiya sun to de ke aagya.... jo aate the attempt kiye rest leftsame dis tym
bhai I was rejected 7 times ...3 times AFSB mysore ... 2 times dehradun... and 2 times varanasi...
@sampras @sampras : mera to 1 tym hoke hi "bas hogya....nt intrested in goin again walla" mood ban gya hai
@Brooklyn said: @gudda1122 :A circular wire of radius 15 cm is cut and bent so as to lie along the circumference of aloop of radius 120 cm. what is the measure of the angle subtended by it at the centre of theloop?yar how to do dis??
bhai it is just saying that a wire of 15cm was placed on a circumfrence of a circle with radius 120
now as we know it won't cover full circumfrence
hence it will only cover some part now we just need to find that angle
ab bhai length of wire with 15 cum radius will be
2*pi*15
and we know theta(angle) is arc/radius =15*pi*2/120
