ShoutBox (Part 1)

@YouMadFellow said:
Did anyone answer this ? Anyways
Speed of escalator be u..(both elevators are moving at the same speed)
Number of steps in escalator = 30 + (30/2)*u = 20 + (20/1)*u
=> u = 2 steps/sec
Total steps = 60
In case of Ram and Tarun, relative speed = 6 steps/sec
So, they meet at 60/6 = 10 secs
=> Tarun moved = 4*10 = 40 steps..
Question mai sameer aur tarun ka likha hai wahi prob hai :p
@nits2811 said:
answer toh batao...32*24*16...aise karke hoga na kuch??
Thik direction mai ho, par wrong ans. 6912 hai ans.
@YouMadFellow said:
Did anyone answer this ? Anyways
Speed of escalator be u..(both elevators are moving at the same speed)
Number of steps in escalator = 30 + (30/2)*u = 20 + (20/1)*u
=> u = 2 steps/sec
Total steps = 60
In case of Ram and Tarun, relative speed = 6 steps/sec
So, they meet at 60/6 = 10 secs
=> Tarun moved = 4*10 = 40 steps..
Ye (30/2)*u and (20/1)*u kahan se aaya??? :(
@ankita14 said:
Thik direction mai ho, par wrong ans. 6912 hai ans.
kaise bhala...thodi si explanation milega..
@paridhi11890 Time = Steps taken / Speed
@paridhi11890 said:
Ye (30/2)*u and (20/1)*u kahan se aaya???
That's the distance covered by the escalator. Assume ram Shyam speed 2 and 1 resp. So ram takes 15 sec to cover 30 steps, elevator covers 15u steps in that time. Similarly for Shyam. Then equate the two distances.
@wovfactorAPS Yah... printing mistake.. If sameer is also moving down, then meeting time = (60/5) = 12 secs => 12*4 = 48 steps damn it is also there in the options.. Not fair .. First time my delusional approach to a question helped me get the right answer πŸ˜› ! :mg:
@nits2811 said:
kaise bhala...thodi si explanation milega..
Select black square first..32 ways then 24 white left and then 18 white left. The two whites are interchangeable so divide by 2. 32*24*18/2
@ankita14 said:
Select black square first..32 ways then 24 white left and then 18 white left. The two whites are interchangeable so divide by 2. 32*24*18/2
two whites are interchangeable kuch samajh nhi aaya...baaki toh thk hain...par it doesn't specify that u have to choose black first...??
@ankita14 Ye be Tarun or Ram ko hi mila re.....
@YouMadFellow said:
Did anyone answer this ? Anyways
Speed of escalator be u..(both elevators are moving at the same speed)
Number of steps in escalator = 30 + (30/2)*u = 20 + (20/1)*u
=> u = 2 steps/sec
Total steps = 60
In case of Ram and Tarun, relative speed = 6 steps/sec
So, they meet at 60/6 = 10 secs
=> Tarun moved = 4*10 = 40 steps..
how many terms,at the minimum of sequence 1+1/2+1/3+....must be together so that sum will not be less than 3.
a) 16
b) 17
c) 18
d) 20

i do not have OA
@nits2811 said:
two whites are interchangeable kuch samajh nhi aaya...baaki toh thk hain...par it doesn't specify that u have to choose black first...??
Matlab double counting ho raha hai if you're not dividing by 2 kyu ki the order in which you select the white squares does not matter. Specified nai hai but it's better to start with b. wwb wala case mai locha hota hai. Multiple cases aate hai.
@RoadKill said:
@nits2811 No of ways of selecting 2 white squares and 1 black from a chess board such that no two lie on the same row or column.
selection of black squares = 32 ways
selection of white square = 24 ways
selection of another white square = 18 ways

number of ways = 32*24*18

but here order doesn't matter of white squares

so , 32*24*18/2
@tequierocr7 said:
There were two escalators (moving stairways) in a mall, with the same number of steps, the first one moving up and the second moving down at the same speed. Ram and Sameer walk up the first escalator at their respective uniform speeds. Ram took 2 steps in the time that Sameer took one. Ram and Sameer reached the top of the escalator after taking 30 steps and 20 steps respectively. Ram then started to walk down the second escalator. At the same time, Tarun started to walk up the second escalator at twice Ram's speed. How many steps would Tarun take before meeting Sameer?
a) 20
b) 24
c) 40
d) 48Please iska solution explain kr do detail me... OA is 40..
let say speed of ram = 2 m/s
speed of sameer = 1 m/s
speed of escalator = x m/s

30 + 15x = 20 + 20x
=> number of steps = 60 and x = 2

if it is RAM and TARUN in question

60*2/6 = 20 steps

if it is SAMEER and TARUN

60*2/5 = 24 steps

40 toh kisise bhi nahi ata
@hedonistajay said:
how many terms,at the minimum of sequence 1+1/2+1/3+....must be together so that sum will not be less than 3.
a) 16
b) 17
c) 18
d) 20i do not have OA
1+1/2+1/3+1/4+1/5
we know that 1/4
1+1/2+1/4+1/4+1/8+1/8+1/8+1/8+1/12+1/12+1/12+1/12+1/16+1/16+1/16+1/16
=1+1/2+1/2+1/2+1/3+1/4
=(12+6+6+6+4+3)/12
=37/12
37/12 >3

16
@YouMadFellow said:
@wovfactorAPS Yah... printing mistake.. If sameer is also moving down, then meeting time = (60/5) = 12 secs => 12*4 = 48 steps damn it is also there in the options.. Not fair .. First time my delusional approach to a question helped me get the right answer !
how did you get 48

number of steps
relative speed of tarun = 4 - 2 = 2
relative speed of sameer = 1 + 2 = 3

60*2/5 = 24 ???

@jain4444 said:
let say speed of ram = 2 m/s
speed of sameer = 1 m/s
speed of escalator = x m/s
30 + 15x = 20 + 20x
=> number of steps = 60 and x = 2
if it is RAM and TARUN in question
60*2/6 = 20 steps
if it is SAMEER and TARUN
60*2/5 = 24 steps
40 toh kisise bhi nahi ata
But the one who posted this question said k OA 40 hi h..!!!
Vaise you are saying to 24 hi hoga....
@jain4444 said:
how did you get 48
number of steps
relative speed of tarun = 4 - 2 = 2
relative speed of sameer = 1 + 2 = 3
60*2/5 = 24 ???
Meets at a distance of 24 steps but his actual speed is 4 and not 2 , so he has travelled 48 steps on the process, the elevator has pushed him down by 24 steps, so left with net 24 steps again.
@ankita14 said:
Meets at a distance of 24 steps but his actual speed is 4 and not 2 , so he has travelled 48 steps on the process, the elevator has pushed him down by 24 steps, so left with net 24 steps again.
Messed up the relative speed values, but you get the gist :rolleyes:
@jain4444
@jain4444 said:
how did you get 48
number of steps
relative speed of tarun = 4 - 2 = 2
relative speed of sameer = 1 + 2 = 3
60*2/5 = 24 ???
Tarun's raw speed = 4 , Sameer's raw speed = 1

(60)/(4 +1) = 12 secs to meet .. The speed of escalator will not play part in relative speed
Tarun moves = 12*(Tarun's speed) = 48 steps 😐

By that time, escalator throws out = 2*12 = 24 steps

-> With respect to escalator, he moved a resultant of 24 steps, but Tarun stepped on 48 steps, so he moved 48 steps, not his fault that the escalator pulled him down by 24 steps..