ShoutBox (Part 1)

Jobs & Careers
20091
@Estallar12 1001 waala? What is the rule exactly, yaad nahi...
20092
@ad18 said:
@Estallar12
@YouMadFellow
@Ibanez
Sir thoda confusion hai,
1144= 11 x 13 x 8
But, 777777 is divisible by 7 x 11 x 13 = 1001, agar 777777 ko 1144 se divide karte hain to remainder aata hai.
Haan, 1001 remainder aaega na obviously Bro.
20093
@RoadKill Haan 6 numbers ka group is divisible by 13.. jaise 777777, 111111 etc..
20094
The products of digits of all three digit even numbers are added. What are the last three digits of this sum.
20095
@Estallar12 Bhai, tune aisa kyun bola ki 426 digits tak ka remainder = 0 hoga ? uska to 1 hoga naa .. 13k, 11m, 8k + 1 .. Lagta hai "unlike" karna padega us post ko :sneaky: :P
20096
@YouMadFellow said:
@RoadKill Haan 6 numbers ka group is divisible by 13.. jaise 777777, 111111 etc..
Divisible by 7 and 11 also. ( 6 repetited digits ka group).
20097
@Estallar12 Haan wo to theek hai, 1001 se divisible hai basically any sequence of 6 nos.
20098
@YouMadFellow said:
@Estallar12 Bhai, tune aisa kyun bola ki 426 digits tak ka remainder = 0 hoga ? uska to 1 hoga naa .. 13k, 11m, 8k + 1 .. Lagta hai "unlike" karna padega us post ko
1 kyun hoga ? :banghead:
20099
@Estallar12 said:
1 kyun hoga ?
Oh teri haan! My bad :splat:
20100
@YouMadFellow 426 multiple of 6. Any sequence of 6 digits is div by 13, hence 0 bola usne. Par ye 1144 se mod 0 kaise bola wo nahi pata. :P
20101
@Estallar12 said:
1144 = 11 x 13 x 8
And 77777 written 6 times will be divisible by 1144 then.
So, 777 written 426 times mod 1144 = 0
Thus, 777 ...... 429 times mod 1144 = 777.
Sir 777777 (7 written six times) will not be divisible by 1144, 777777 odd no. hai, 1144 even no.
20102
@RoadKill Haan divisible by 13 to thik hai, but divisible by 1144 kyu ? !
20103
@YouMadFellow Wahaan pe goof up. :D
20104
@Estallar12 said:
The products of digits of all three digit even numbers are added. What are the last three digits of this sum.
Aise questions me dimaag kharab hota hai :banghead: .. Shayad CAT me aise hi questions aaye hai is baar :splat:
20105
If the HM between two positive numbers is to their GM is 12:13, then the number could be in ratio :

12:13,
1/12:1/13,
4:9,
2:3
20106
@Estallar12 said:
The products of digits of all three digit even numbers are added. What are the last three digits of this sum.
500?
20107
Range of fucntion f(x)= x/(x+1) ?
20108
@Estallar12

Sum yeh hai kya ?

[2 + 4+ 6 + 8] * ( 1 + 2+ ....9) * ( 1+2+ ...9) = 45^2 * 20 = 2025 * 20 = 40500 ?

Last three digits = 500 ?
20109
@Estallar12 said:
If the HM between two positive numbers is to their GM is 12:13, then the number could be in ratio :
12:13,
1/12:1/13,
4:9,
2:3
4:9
20110
@Estallar12 said:
If the HM between two positive numbers is to their GM is 12:13, then the number could be in ratio :
12:13,
1/12:1/13,
4:9,
2:3
4:9 ...