ShoutBox (Part 1)

Jobs & Careers
20111
@Estallar12 said:
Range of fucntion f(x)= x/(x+1) ?
{R} - [1] ?
20112
@Estallar12 said:
If the HM between two positive numbers is to their GM is 12:13, then the number could be in ratio :
12:13,
1/12:1/13,
4:9,
2:3
4:9
6(a+b)=13(ab)^1/2
20113
@YouMadFellow said:
{R} - [1] ?
you just stated independent in terms of dependent right?

I'd forgotten we could use that to calculate range!~
20114
@Estallar12 said:
Range of fucntion f(x)= x/(x+1) ?
R - {1}
20115
@ashishpai2001 said:
you just stated independent in terms of dependent
What are independent and dependent :splat: ?

I made the graph. OR ( 1 - (1/(1+x)) => except 1 , everything ...
20116
A regular pentagon is drawn on a piece of paper. In how many ways can five identical Re.1 coins be placed on the five vertices of the pentagon if exactly one coin is to be placed on each vertex?
(a) 6 (b) 32 (c) 16 (d) 8
20117
@ad18 said:
A regular pentagon is drawn on a piece of paper. In how many ways can five identical Re.1 coins be placed on the five vertices of the pentagon if exactly one coin is to be placed on each vertex?
(a) 6 (b) 32 (c) 16 (d) 8
d) 8 ?

0 coins = 1
1 coin = 1
2 coins = 2
3 coins = 2
4 coins = 1
5 coins = 1
20118
@YouMadFellow said:
What are independent and dependent ?
I made the graph. OR ( 1 - (1/(1+x)) => except 1 , everything ...
y = x/x+1
yx + y = x
y = x - xy
y = x(1-y)
x = y/(1-y)

So every value is possible except at y=1 ie 1 is not in the range
20119
@ad18 said:
A regular pentagon is drawn on a piece of paper. In how many ways can five identical Re.1 coins be placed on the five vertices of the pentagon if exactly one coin is to be placed on each vertex?
(a) 6 (b) 32 (c) 16 (d) 8
8??
20120
The number of natural numbers less than 1000 whose sum of digits is 12?
20121
@YouMadFellow said:
d) 8 ?
Are the vertices numbered or something ?
0 coins = 1
1 coin = 1
2 coins = 2
3 coins = 2
4 coins = 1
5 coins = 1
No, you need to take heads and tails into account. 5H/0T, 4H/1T, 3H/2T, 2H/3T, 1H/4T, 0H/5T. And also the order in which they appear on the pentagon
20122
@YouMadFellow said:
{R} - [1] ?
R-{-1} I believe. x can be 1
20123
@Estallar12 said:
The number of natural numbers less than 1000 whose sum of digits is 12?
(x + y + z) = 12

=> 14C2 - 3*(4C2) = 73 ?
20124
@Ibanez said:
R-{-1} I believe. x can be 1
Range is asked, not domain 😃
20125
@ad18 Damn ! :banghead: .. Sholay wala sikka hota to ?? :splat:
20126
@Estallar12 said:
The number of natural numbers less than 1000 whose sum of digits is 12?
35?
20127
@YouMadFellow wudnt it be always less than 1
f(x)= x/(x+1) = 1-1/(x+1) as x-->infin fx---1 x--->0 fx=0
it shud be (-1,1)
20128
@YouMadFellow said:
Range is asked, not domain
O yes.
20129
@YouMadFellow said:
(x + y + z) = 12
=> 14C2 - 3*(4C2) = 73 ?
Hey can you give me the formula for this.. i know the 14C2 part.. why 3*4C2..?
20130
@tekkenlord_king said:
@YouMadFellow wudnt it be always less than 1
f(x)= x/(x+1) = 1-1/(x+1) as x-->infin fx---1 x--->0 fx=0
it shud be (-1,1)
Refer this: