Quant by Arun Sharma

Find the 28383rd term of the series: 123456789101112..........

a) 3 b) 4 c) 9 d) 7

Answer should be a) 3.

We need to count the no. of digits:
1-9 = 9
10-99 = 90*2 = 180
100-999 = 900*3 = 2700
1000-9999 = 9000*4 = 36000

Thus, the number would be a 4 digit no. No. of digits till 999 is 2889. We need the 28383rd digit, i.e. we need to find the 25494th digit starting from 1000 (28383-2889 = 25494).

Since, we know it'll be a 4 digit number, we can find the last number by dividing 25492/4 (not 25494, as we're trying to find the number now. Once we find the number, we can find the next two digits to get to the 25494th digit).

25492/4 = 6373rd number starting from 1000. It means the number is 1000+6373-1 = 7372. Till 7372, we have got 25492+2889 = 28381 digits. Next number will be 7373, we're interested in only the 2nd number as then we'll reach the 28383rd digit, and this number is 3.

Hope you understood 😃
Find the 28383rd term of the series: 123456789101112..........

a) 3 b) 4 c) 9 d) 7


Count of numbers with 1 digit = 9
Numbers with 2 digits = 90
Numbers with 3 digits = 900
Numbers with 4 digits = 9000

So total number of digits if we count all 1 digit, 2 digit and 3 digit numbers is = 9 * 10 + 90 * 2 + 900 * 3 = 2889.

Since 28383rd term is asked, 28383 - 2889 = 25494.

The next series will be all 4 digit numbers, so 25494 mod 4 = 6373 with a remainder of 2.

There will be 6373 4 digit numbers till we reach 25492 digits. The first 4 digit number is 1000. Add 6373 + 1000 = 7373.

Remainder of 2, so it will like ....7373 7374 7375

The reqd digit is 3.

Hope this is understandable. ....

Please explain with detailed explanation :

Q11, Q12 (LOD2) - Number Systems Pg14

Thanks

Please explain with detailed explanation :

Q11, Q12 (LOD2) - Number Systems Pg14

Thanks

Please take the pains of posting the questions as well, as not every puy who wishes to contribute on this thread, has the book. Besides, others don't have to flip through the pages and can check the problem here itself.

Hi frnz,

I am a newbie and have started pretty late for the xm. But I hope to give my best still!

Though, some of the answers by Arun Sharma puzzle me , I still feel it has good questions.

Need your help with the following questions :

LOD I

55. If 2a) 6 b) 7 c) 8 d) 4 e) None of these

74. Three mangoes, four guavas and five watermelons cost Rs 750. Ten watermelons, six mangoes and 9 guavas cost Rs 1580. What is the cost of six mangoes, ten watermelons and 4 guavas?
a) 1280 b) 1180 c) 1080 d) cannot be determined

76. The cost of four mangoes, six guavas and sixteen watermelons is Rs 500, while the cost of seven mangoes, nine guavas and nineteen watermelons is Rs 620. What is the cost of one mango, one guava and one watermelon?
a) 120 b) 40 c) 150 d) cannot be determined

77. For the question above, what is the cost of mango?
a) 20 b) 14 c) 15 d) cannot be determined

78. The following is known about three real numbers x,y and z.
-4a) -16
Thanks

Hi frnz,

I am a newbie and have started pretty late for the xm. But I hope to give my best still!

Though, some of the answers by Arun Sharma puzzle me , I still feel it has good questions.

Need your help with the following questions :

LOD I

55. If 2a) 6 b) 7 c) 8 d) 4 e) None of these

74. Three mangoes, four guavas and five watermelons cost Rs 750. Ten watermelons, six mangoes and 9 guavas cost Rs 1580. What is the cost of six mangoes, ten watermelons and 4 guavas?
a) 1280 b) 1180 c) 1080 d) cannot be determined

76. The cost of four mangoes, six guavas and sixteen watermelons is Rs 500, while the cost of seven mangoes, nine guavas and nineteen watermelons is Rs 620. What is the cost of one mango, one guava and one watermelon?
a) 120 b) 40 c) 150 d) cannot be determined

77. For the question above, what is the cost of mango?
a) 20 b) 14 c) 15 d) cannot be determined

Thanks


q1. i think answer should be none of these....

q2. answer is 1180....

q3. answer is 40...

q4. answer is CBD

q1. i think answer should be none of these....

q2. answer is 1180....

q3. answer is 40...

q4. answer is CBD


Thanks, divishth. How did you reach the answers?

I completely agree with you...but its not that i m lazy in posting the questions, its the syntax of the questions for which i avoided...anyways,
here are the questions:

Q11)a number xy is multiplied by another no ab and the result comes as pqr, where r=2y, q=2(x+y) and p=2x where x,y11
13
31
22

Q12) denotes the greatest integer value just below x and {x} its fractional value. The sum of ^3 and{x}^2 is -7.91. find x.
-2.03
-1.97
-2.97
-1.7

Thanks.

Hi frnz,

I am a newbie and have started pretty late for the xm. But I hope to give my best still!

Though, some of the answers by Arun Sharma puzzle me , I still feel it has good questions.

Need your help with the following questions :

LOD I

55. If 2a) 6 b) 7 c) 8 d) 4 e) None of these

Thanks


though i am not sure about this one...but.....lets c
x can have value = 3
y can have = 2
so (x+y)/(x-Y) = 5/1 = 5
therefore none of these
Hi frnz,

I am a newbie and have started pretty late for the xm. But I hope to give my best still!

Though, some of the answers by Arun Sharma puzzle me , I still feel it has good questions.

Need your help with the following questions :

LOD I

74. Three mangoes, four guavas and five watermelons cost Rs 750. Ten watermelons, six mangoes and 9 guavas cost Rs 1580. What is the cost of six mangoes, ten watermelons and 4 guavas?
a) 1280 b) 1180 c) 1080 d) cannot be determined



Thanks


here in this question....
3M + 4G + 5M = 750 ...(1)
6M + 9G + 10M = 1580...(2)
multiply (1) with 2 we have
6M + 8G + 10M = 1500...(3)
subtract (3) from (2)
we have G = 80
now 6M + 9G + 10M = 1580
6M + 4G + 10M = 1580 - 5G
therefore 6M + 4G + 10M = 1580 - 5*80
6M + 4G + 10M = 1180..
Hi frnz,

I am a newbie and have started pretty late for the xm. But I hope to give my best still!

Though, some of the answers by Arun Sharma puzzle me , I still feel it has good questions.

Need your help with the following questions :

LOD I

76. The cost of four mangoes, six guavas and sixteen watermelons is Rs 500, while the cost of seven mangoes, nine guavas and nineteen watermelons is Rs 620. What is the cost of one mango, one guava and one watermelon?
a) 120 b) 40 c) 150 d) cannot be determined

77. For the question above, what is the cost of mango?
a) 20 b) 14 c) 15 d) cannot be determined

Thanks

here we have
4M + 6G + 16W = 500..(1) * 7
7M + 9G + 19W = 620..(2) * 4

28M + 42G + 112W = 3500..(3)
28M + 36G + 76W = 2480..(4)

subtracting 4 from 3
6G + 36W = 1020..(5)
G + 6W = 170..(6)
put 5 in 1 we have
4M + (1020-36W) + 16W = 500
4M - 20W = -520
M-5W = -130...(7)
Add (6) and (7)
M+W+G = 40

but uniquely we can't determine value of one mango....hence for next question CBD
here we have
4M + 6G + 16W = 500..(1) * 7
7M + 9G + 19W = 620..(2) * 4

28M + 42G + 112W = 3500..(3)
28M + 36G + 76W = 2480..(4)

subtracting 4 from 3
6G + 36W = 1020..(5)
G + 6W = 170..(6)
put 5 in 1 we have
4M + (1020-36W) + 16W = 500
4M - 20W = -520
M-5W = -130...(7)
Add (6) and (7)
M+W+G = 40

but uniquely we can't determine value of one mango....hence for next question CBD

here in this question....
3M + 4G + 5M = 750 ...(1)
6M + 9G + 10M = 1580...(2)
multiply (1) with 2 we have
6M + 8G + 10M = 1500...(3)
subtract (3) from (2)
we have G = 80
now 6M + 9G + 10M = 1580
6M + 4G + 10M = 1580 - 5G
therefore 6M + 4G + 10M = 1580 - 5*80
6M + 4G + 10M = 1180..

though i am not sure about this one...but.....lets c
x can have value = 3
y can have = 2
so (x+y)/(x-Y) = 5/1 = 5
therefore none of these


Thanks divishth...

As I said, answers in the book had me confused slightly! But now I am sure to not trust book's answers :D

btw...you missed this one

78. The following is known about three real numbers x,y and z.
-4a) -16

Hi all

This is my first post in PG.. but i have been a regular visitor to this site.. I came across some qns in the quant book by Arun sharma which i cudnt solve.. so help me out with these qns

1. Find the maximum value of n such that 50! is perfectly divisible by 2520^n
2. Find the maximum value of n such that 50! is perfectly divisible by 12600^n
3. find the number of divisors 0f 1080 excluding the through out divisors which are perfect squares

Hi Puys,

I have some unsolved problems:

Review Test of Block 2

6) 2 oranges, 3 bananas and 4 apples cost Rs. 15. 3 oranges, 2 bananas and 1 apple cost Rs. 10. I bought 3 oranges, 3 bananas and 3 apples. How much did I pay?

1) Rs. 10
2) Rs. 8
3) Rs. 15
4) Cant be determined


7) John bought 5 mangoes and 10 oranges together for Rs. 40. Subsequently, he returned 1 mango and got 2 oranges in exchange. The price of an orange would be:

1) Rs. 1
2) Rs. 2
3) Rs. 3
4) Rs. 4


16) The total expenses of a boarding house are partly fixed and partly varying linearly with the number of boarders. The average expense per boarder is Rs. 700 when there are 25 boarders and Rs. 600 when there are 50 boarders. What is the average expense per boarder when there are 100 boarders.

1) 550
2) 580
3) 540
4) 570

hi mohitgem
1.2o+3b+4a = 15
3o+2b+1a = 10
adding these 2, we get 5o+5b+5a = 25
so 3o+3b+3a = 5x3 =15

2. 5m+10o = 40
1m = 2o
sub 1m = 2o in eqn1 10m = 40
m = 4 and o =2

3. F - fixed cost , V- variable cost

F+25V = 700x25
F+50V = 600x50
we get V = 500 , F = 5000
so avg cost for 100 borders = (F+100V)/100
= 550

I have posted some doubts look thru those and help me out

Hi Puys,

I have some unsolved problems:

Review Test of Block 2

6) 2 oranges, 3 bananas and 4 apples cost Rs. 15. 3 oranges, 2 bananas and 1 apple cost Rs. 10. I bought 3 oranges, 3 bananas and 3 apples. How much did I pay?

1) Rs. 10
2) Rs. 8
3) Rs. 15
4) Cant be determined


7) John bought 5 mangoes and 10 oranges together for Rs. 40. Subsequently, he returned 1 mango and got 2 oranges in exchange. The price of an orange would be:

1) Rs. 1
2) Rs. 2
3) Rs. 3
4) Rs. 4


16) The total expenses of a boarding house are partly fixed and partly varying linearly with the number of boarders. The average expense per boarder is Rs. 700 when there are 25 boarders and Rs. 600 when there are 50 boarders. What is the average expense per boarder when there are 100 boarders.

1) 550
2) 580
3) 540
4) 570

Answers:

1) 15 Rs.
2) Rs. 2
3) 550
hi mohitgem
1.2o+3b+4a = 15
3o+2b+1a = 10
adding these 2, we get 5o+5b+5a = 25
so 3o+3b+3a = 5x3 =15

2. 5m+10o = 40
1m = 2o
sub 1m = 2o in eqn1 10m = 40
m = 4 and o =2

3. F - fixed cost , V- variable cost

F+25V = 700x25
F+50V = 600x50
we get V = 500 , F = 5000
so avg cost for 100 borders = (F+100V)/100
= 550

I have posted some doubts look thru those and help me out


where are your doubts ??

help me out with these qns

1. Find the maximum value of n such that 50! is perfectly divisible by 2520^n
2. Find the maximum value of n such that 50! is perfectly divisible by 12600^n
3. find the number of divisors 0f 1080 excluding the through out divisors which are perfect squares

This one is from arun sharma..

A train travels nonstop at an average speed of 75 km/h. While the same train travels at an average speed of 60 km/h when it stops at intermediate stations. find the time in minutes per hour for which the train stops.

1) 10 min 2) 12 min 3) 14 min 4) 18 min

This one is from arun sharma..

A train travels nonstop at an average speed of 75 km/h. While the same train travels at an average speed of 60 km/h when it stops at intermediate stations. find the time in minutes per hour for which the train stops.

1) 10 min 2) 12 min 3) 14 min 4) 18 min


Train takes 60/75 of an hour = 48 minutes to travel 60 kms.

So, it stops for 60-48 = 12 minutes per hour