its on page 100 ques-36-39 of arun sharma
Q-- if it is known that mr magoo estimates his savings at 10 moolhas and actual expenditure is 288 moohlas in a year . then what will happen to his estimated savings if he suddenly calculates on thebasis of 12 month calender year??
ans- -will increase by 5
-will increase by 15
-will increase by 10
-will triple
a can do a piece of work in 18days and B in 9 days and C in 6days.A and B start working together and after 2 days c join them.in how many days will the job be completed??
plz give the proper solution
A's 1 day work=1/18
B's 1 day work=1/9
C's 1 day work=1/6
(A+b) 2 days work =2(1/18+1/9)
=2*1/6=1/3
remaining work= 1-1/3=2/3
left for A+B+C
A+B+C 1 day work =1/18+1/9+1/6
=6/18=1/3
1/3rd work is done in 1 day
2/3rd work is done in 2/3*3/1=2 days
hence total days to complete work = 2 of a+b+c and 2 of a+b+c=4 days
=4 days
These two questions are from the chapter "Alligations"
Q. 17
A dishonest grocer professes to sell pure butter at cost price, but he mixes it with adulterated fat and thereby gains 25%. Find the percentage of adulterated fat in the mixture assuming that adulterated fat is freely available.
a. 20%
b. 25%
c. 33.33%
d. 40%
Q. 25
Two vessels contain spirit and water mixed respectively in the ratio of 1:3 and 3:5. Find the ratio in which these are to be mixed to get a new mixture in which the ratio of spirit to water is 1:2
a. 2:1
b. 3:1
c. 1:2
d. 1:3
Please help!
These two questions are from the chapter "Alligations"
Q. 17
A dishonest grocer professes to sell pure butter at cost price, but he mixes it with adulterated fat and thereby gains 25%. Find the percentage of adulterated fat in the mixture assuming that adulterated fat is freely available.
a. 20%
b. 25%
c. 33.33%
d. 40%
Q. 25
Two vessels contain spirit and water mixed respectively in the ratio of 1:3 and 3:5. Find the ratio in which these are to be mixed to get a new mixture in which the ratio of spirit to water is 1:2
a. 2:1
b. 3:1
c. 1:2
d. 1:3
Please help!
Q 17. Assume that he buys 100 gms of butter for Rs. 12.5 and sells it at Rs. 12.5 as well (selling at cost price). Given, that he gains 25% by adding adulterated fat. Thus, his actual cost becomes Rs. 10 and he gains 2.5 on 10 -> 25%.
Thus, %age of pure butter = 10/12.5 = 80%
And %age of adulterated fat = 100-80 = 20%
Q 25. Either this question is wrong, or the options are. Because if the two vessels contain spirit and water in the ratio of 1:3 and 3:5, and we add them in the ratio of 1:1, we will get a ratio of 4:8 (1+3:3+5) or 1:2
Q 17. Assume that he buys 100 gms of butter for Rs. 12.5 and sells it at Rs. 12.5 as well (selling at cost price). Given, that he gains 25% by adding adulterated fat. Thus, his actual cost becomes Rs. 10 and he gains 2.5 on 10 -> 25%.
Thus, %age of pure butter = 10/12.5 = 80%
And %age of adulterated fat = 100-80 = 20%
Q 25. Either this question is wrong, or the options are. Because if the two vessels contain spirit and water in the ratio of 1:3 and 3:5, and we add them in the ratio of 1:1, we will get a ratio of 4:8 (1+3:3+5) or 1:2
Thanks a lot..Are you sure about the second one being incorrect??
Q- in what ratio should water be mixed with soda costing rs12 per litre so as to make a profit of 25% by selling the diluted liquid at rs 13.75 per litre?
1- 10:1
2- 12:1
3- 11:1
4- 1:12
5- 1:11
Q- in what ratio should water be mixed with soda costing rs12 per litre so as to make a profit of 25% by selling the diluted liquid at rs 13.75 per litre?
1- 10:1
2- 12:1
3- 11:1
4- 1:12
5- 1:11
The answer to this one is 1:11
Here's the sol:
The profit is 25%.
Thus,
125% of x = 13.75
x = 11 (This the effective cost price of the mixture)
Cost of soda is Rs.12
Cost of water is Rs.0
And the average (effective) cost price is Rs.11
Now, use the cross rule of alligation or the equation to derive the ratio.
Using the equation,
n1/n2 = n2-A/A-n1
i.e n1/n2 = 12-11/11-0
n1/n2 = 1/11
the ratio is 1:11
pway SaysThanks a lot..Are you sure about the second one being incorrect??
Yes. Did you get any other answer?? Btw, I had checked earlier and you had mentioned that you were getting the same result, so don't know how you got another result so quickly :-P
avinav2712 SaysYes. Did you get any other answer?? Btw, I had checked earlier and you had mentioned that you were getting the same result, so don't know how you got another result so quickly :-P
Well actually I too did the same and got the same answer but there is another very similar question in the same chapter and this approach did not give any of the options as the answer. So, it thought that it is quite strange that the book has the wrong options for both the questions of the type.
pway SaysWell actually I too did the same and got the same answer but there is another very similar question in the same chapter and this approach did not give any of the options as the answer. So, it thought that it is quite strange that the book has the wrong options for both the questions of the type. :lookround:
If you have the concepts right, you can prove both the questions as wrong 😃 Of course, provided you have confidence in your concepts
The residents of town X participated in a survey to determine the number of hours per week each residents spent watching television. The distribution of the results of the survey had a mean of 21 hours and a standard deviation of 6 hours. The number of hours that John, a resident of town X watch television last week was between 1 and 2 standard deviations below the mean. Which of the following would be the number of hours that John watched the television last week ?
30
20
18
12
6
Can someone please explain ?
The residents of town X participated in a survey to determine the number of hours per week each residents spent watching television. The distribution of the results of the survey had a mean of 21 hours and a standard deviation of 6 hours. The number of hours that John, a resident of town X watch television last week was between 1 and 2 standard deviations below the mean. Which of the following would be the number of hours that John watched the television last week ?
30
20
18
12
6
Can someone please explain ?
Should be 12. As Mean - SD = 21 - 6 = 15 and Mean - 2*SD = 21-12 = 9. Thus, 12 is the only option between 9 and 15
Q - two vessels contain spirit and water mixed in ratio 1:3 and 3:5.
Find the ratio in which these are to be mixed to get a new mixture in which the ratio of spirit to water is 1:2 ??
Ans 1:3
a. 2:1
b. 3:1
c. 1:2
Q - two vessels contain spirit and water mixed in ratio 1:3 and 3:5.
Find the ratio in which these are to be mixed to get a new mixture in which the ratio of spirit to water is 1:2 ??
Ans- 1-- 149:247
2-- 247:149
3-- 143:241
4-- 241:143
Atleast check the last couple of pages before posting your question. This question was discussed recently.
Two vessels contain spirit and water mixed respectively in the ratio of 1:3 and 3:5. Find the ratio in which these are to be mixed to get a new mixture in which the ratio of spirit to water is 1:2
a. 2:1
b. 3:1
c. 1:2
Spirit is in the ratio 1/4 in vessel 1
spirit is in the ratio 3/8 in vessel 2
in the mixture ratio of spirit is 1/3
1/4 3/8
1/3
x/3/8-1/3 y/1/4-1/3
x/y=1/2
so ans is 1:2
This is from Percentages Q. 36-38
In a recent youth fete organised by AMS Careers, the entry tickets were sold according to the following scheme:
Tickets bought in one lot 6 12 18
Percentage Discount 10% 20% 25%
Original price of ticket is Rs.40
This offer could have been availed only when tickets were bought in a fixed lot according to the scheme and any additional ticket was available at its original price.
Q. 36. If a person has to buy 25 tickets, then what will be the minimum price per ticket?
a. Equal to Rs. 32
b. 32.32
c. 31.84
d. Cannot be determined
(I got the answer as Rs. 31.84..not sure about it though)
38. On the day of the fete, with the objective of maximising participation, the number of tickets sold in a lot was halved with the same discount offer. Mr. X is in a fix regarding the number of tickets he can buy with Rs. 532. The maximum number of tickets he can purchase with the money is
a. 14
b. 15
c. 16
d. 17
This is from Percentages Q. 36-38
In a recent youth fete organised by AMS Careers, the entry tickets were sold according to the following scheme:
Tickets bought in one lot 6 12 18
Percentage Discount 10% 20% 25%
Original price of ticket is Rs.40
This offer could have been availed only when tickets were bought in a fixed lot according to the scheme and any additional ticket was available at its original price.
Q. 36. If a person has to buy 25 tickets, then what will be the minimum price per ticket?
a. Equal to Rs. 32
b. 32.32
c. 31.84
d. Cannot be determined
(I got the answer as Rs. 31.84..not sure about it though)
38. On the day of the fete, with the objective of maximising participation, the number of tickets sold in a lot was halved with the same discount offer. Mr. X is in a fix regarding the number of tickets he can buy with Rs. 532. The maximum number of tickets he can purchase with the money is
a. 14
b. 15
c. 16
d. 17
Q 36 has to be 31.84. 18 tickets at Rs. 30 each (25% discount), 6 tickets at Rs 36 each (10% discount) and one ticket at Rs. 40 (normal price) = 25 tickets for Rs. 796 = Rs. 31.84/ticket.
Q 38 should have the answer as 16. According to the question, the discount system would work as, 3 tickets = 10%, 6 = 20%, 9 = 25%. Thus, we can buy 9 tickets at Rs. 30 each, 6 tickets at Rs. 32 each. This totals to be Rs. 462. So only Rs. 70 left, with which we can buy just one ticket of Rs. 40. Thus, 9+6+1 = 16 tickets.
Hello Friends,
This is from a series of questions given in LOD 3 in the Number System chapter.
The question number is from 54 till 58... One of them is listed below... rest are all of the same type. I am basically not good at these types of questions, so need your help.
54) What is the remainder when 50^51^52 is divided by 11.
a) 6
b) 4
c) 7
d) 3
I really feel confused when a 2 power system (like in this case) is present.
Could you please help me out with a possible way of approaching such types of questions?
Thanks,
Mohit.
Hello Friends,
This is from a series of questions given in LOD 3 in the Number System chapter.
The question number is from 54 till 58... One of them is listed below... rest are all of the same type. I am basically not good at these types of questions, so need your help.
54) What is the remainder when 50^51^52 is divided by 11.
a) 6
b) 4
c) 7
d) 3
I really feel confused when a 2 power system (like in this case) is present.
Could you please help me out with a possible way of approaching such types of questions?
Thanks,
Mohit.
answer is 6
50^10k = 1mod11
So 51^52 is to be written in the form of 10k + a.
Now unit digit of 51^52 = 1 => 51^52 = 10k + 1.
=> 50^51^52 = 50^(10k + 1) = 50mod11 = 6mod11
answer is 6
50^10k = 1mod11
So 51^52 is to be written in the form of 10k + a.
Now unit digit of 51^52 = 1 => 51^52 = 10k + 1.
=> 50^51^52 = 50^(10k + 1) = 50mod11 = 6mod11
Hello Mani,
Thanks for the valuable response. However, if you would have read my question carefully, I have expressed my discomfort with these types of problems containing 2 powers. Could you please let me know how to approach such problems, and if possible, by remainder theorem. I am not well versed in the "mod" way of solving the remainder questions.
Your response and help would be highly appreciated.
Thanks,
Mohit.