@gudda1122 :one thing i just wanted to know,why u assumed 60 units,any specific reason...i mean when ur assuming,u could have assumed some other value as well.....
@UnCharismatic said: @gudda1122 : ne thing i just wanted to know,why u assumed 60 units,any specific reason...i mean when ur assuming,u could have assumed some other value as well.....
i assumed to make calculation simple :)
completed one LOD1 of Time nd Work with 5 which i wasn't able to do...but 45 is indeed a gud no. of questions ....,now its tym for LOD2
@gudda1122 :okey..got it,nyc way to make a question simple...:)
@prati086 said: The sum of the series is represented as1/(1*5)+1/(5*9)+...................+1/(221*225)is ................
1/4 [ 1-1/5 +1/5 -1/9 + 1/9 -......+1/221 - 1/225]
= 224/225 * 1/4
= 56/225 :)
@prati086 said: The sum of the series is represented as1/(1*5)+1/(5*9)+...................+1/(221*225)is ................
Is it 56/225 ?
@prati086 said: The sum of the series 1/(sqrt(2) + sqrt(1)) + 1/(sqrt(2) + sqrt(3)) + ........ + 1/(sqrt(120) + sqrt(121)) ..............How to solve ths
Rationalizing Denominator:
you will get _/(n+1) - _/n
S = (rt2 -rt1) + (rt3-rt2) + (rt4-rt3)+....(rt121 -rt120)
S = rt 121 -rt 1 = 11-1 = 10 😃
@prati086 said: The sum of the series 1/(sqrt(2) + sqrt(1)) + 1/(sqrt(2) + sqrt(3)) + ........ + 1/(sqrt(120) + sqrt(121)) ..............How to solve ths
Rationalizing Denominator:
you will get _/(n+1) - _/n
S = (rt2 -rt1) + (rt3-rt2) + (rt4-rt3)+....(rt121 -rt120)
S = rt 121 -rt 1 = 11-1 = 10 😃
There are some Extra Practice Questions on Pg 393, in the Geometry and Mensuration Chp.
Q.5-A lateral side of an isosceles triangle is 15 cm. and the altitude is 8 cm. What is the radius of the circumscribed circle.
The answer is 9.375. But using abc/4R=1/2*base*ht (Equating areas), the answer comes out to be 14.xx.
The answer is 9.375. But using abc/4R=1/2*base*ht (Equating areas), the answer comes out to be 14.xx.
Please help me solve this.
@prati086 Draw a rectangle then u ll come to noe that distance of shorter side from the center of rectangle i.e. intersection of two diagonal is 13 not 9
@Bababhokali said:1/4 [ 1-1/5 +1/5 -1/9 + 1/9 -......+1/221 - 1/225]= 224/225 * 1/4= 56/225
why u took 1/4 outside???
@challenger90 said:why u took 1/4 outside???
Original series is
1/5 + 1/45 + 117..etc
So I doesn't have any 4 in Numerator....Hence divide modified series by 4 to get reqd answer :)
@Bababhokali said:Original series is1/5 + 1/45 + 117..etcSo I doesn't have any 4 in Numerator....Hence divide modified series by 4 to get reqd answer
but why there was a need to divide it by 4..in simple terms answer cud be 224/225..so why there was a need to do that..i m not getting it
@challenger90 said:but why there was a need to divide it by 4..in simple terms answer cud be 224/225..so why there was a need to do that..i m not getting it
Bheyya
1-1/5 is not equal to 1/(1*5). Paper pencil se check karo :P
A set S consists of 12 distinct elements a1,a2,a3...a12.How many subsets can be made of S with the restriction
that
the subscripts of elements in any subset starting from
the second element
is an integral multiple of the subscript of the first
element.
eg: if the 1st element is a1, we could have the set as
{a1, a2 , a3..}
if the 1st element is a2, we could have the set as {a4
, a6..}pl help wid approach too...
in a trepezium ABCD.the diagonals AC n BD intersect each other at O such that OB:CD = 3:1 then ratio of areas of AOB:COD
in a trapezium ABCD, AB || CD. BD perpendicular to AD. AC is perpen to BC. IF AD=BC=15 and AB=25. area of trapezium