@jeetuachtani said:OA 192.5 buddy
am getting 192 as answer!
remainder when 50! is divided by 16^15 ??
PLS guys post the approach for such remainder type ques
@jai91 said: remainder when 50! is divided by 16^15 ?? PLS guys post the approach for such remainder type ques
Bro, just find out the powers of 2 in 50!. And now, as 16 = 2^4 => 16^15 = (2^4)^15 = 2^60.
And Powers of 2 in 50! = 25+12+6+3+1 = 47.
Phuck. This will turn out to be a big number now :O
@Estallar12 said:Bro, just find out the powers of 2 in 50!. And now, as 16 = 2^4 => 16^15 = (2^4)^15 = 2^60.And Powers of 2 in 50! = 25+12+6+3+1 = 47.Phuck. This will turn out to be a big number now
I also tried to do the same 
Now struck
trying to solve it since last 15 minutes :O
@vijay_chandola said:I also tried to do the sameNow strucktrying to solve it since last 15 minutes
Mera Remainder is coming something in 16-17 digits. :banghead:
Queschen galat daala hai kya ?? @jai91
@Estallar12 same here...
I thought some trick should work
its a 17digit number wolfram-alpha se confirm kiya
@vijay_chandola said: @Estallar12 same here...I thought some trick should workits a 17digit number wolfram-alpha se confirm kiya
Oh Darn! And we were trying to solve it :P
sqrt(1+2sqrt(1+3sqrt(1+4sqrt(1+5sqrt1+........ find the value !
@Estallar12 : bhai question toh sahi hai bt options nai he 
aise type k questions ka method samjha do yaar
aise type k questions ka method samjha do yaar
@jai91 said: @Estallar12 : bhai question toh sahi hai bt options nai he aise type k questions ka method samjha do yaar
@chandrakant.k said: @Estallar12 : sir, even i am stuck at that step.. please tag me if you get to know the solution
Skip it :mg:
@jai91 said: @Estallar12skip dis one bt remainder type ques ka method kya he
You can use Remainder Theorem, Euler's Theorem or Chinese Remainder.
