there is a group of 200 students , where each student studies one or more of the three subjects among A, B and C. The number of students studying C > num of students A > num of students studying B. which in turn is more than no of students who study exactly 2 subjects, which in turn , is more than no of students who study all the 3 subjects. it is known that at least one student studies all the three subjects.
q1.) what is the max no of students who study B.
148/149/150/147/none
Plz help me with this....
After receiving two successive raises,Hursh's salary became equal to 15/8 times of his initial salary.By how much percent was the salary raised the first time if the second raise was twice as high(in percent) as the first?
a. 15%
b. 20%
c. 25%
d. 30%
e. 33.33%
The ratio of Jim's salary for October to his salary for November was 1.5:1.333 and the ratio of the salary for November to that of December was 2:2.6666.The worker got 40 rupees more for december than for october and received a bonus constituting 40 percent of the salary for 3 months.Find the bonus
a. 368.888
b. 152.5555
c. 222.22
d. 265.6
e. None of these
@rk90 said: Plz help me with this....After receiving two successive raises,Hursh's salary became equal to 15/8 times of his initial salary.By how much percent was the salary raised the first time if the second raise was twice as high(in percent) as the first?a. 15%b. 20%c. 25%d. 30%e. 33.33%
25 %
Hello!!!!Approach Plz!!!!!
@mbajamesbond said: which is the least number that must b subtracted from 1856 so that remainder when divided by 7,12,16 will same remainder four. pls do rply me with the answersHow you get there?IMO it should be 6
176
@[520788:LeoN88]:I need the approach.Plz provide the same!
@rk90 said: Plz help me with this....After receiving two successive raises,Hursh's salary became equal to 15/8 times of his initial salary.By how much percent was the salary raised the first time if the second raise was twice as high(in percent) as the first?a. 15%b. 20%c. 25%d. 30%e. 33.33%
best possible way to solve these kinds of question is by using option
start with the option which is in the middle
@rk90 said: @LeoN88:I need the approach.Plz provide the same!
Sorry,
% increase in sal . = ((15/8) - 1)/1 =7/8 approx 84.xx %
Apply x + 2x + (2x.x)/100 =approx 84 formula
x=25 satisfies....from options
% increase in sal . = ((15/8) - 1)/1 =7/8 approx 84.xx %
Apply x + 2x + (2x.x)/100 =approx 84 formula
x=25 satisfies....from options
the answer to salary problem is d
oct=a
nov=b
dec=c
a/b=1.5/1.333
or a/b=9/8
b/c=2/2.666
or b/c=3/4
a=9/8 * b
b=3/4 *c
or a=27/32 * c
c=40+a
or c=40+27/32 *c
or 5/32 * c=40
or c=256
a=216
b=192
a+b+c=664
bonus=40% of 664
or bonus=265.6
A batsman's runs before the last match of the season, add up to 750. In his last two innings, he scores only 6 runs, and his average drops by 2. His final average of the season is
(1) 25 runs
(2) 30 runs
(3) 28 runs
(4) 24 runs
if p , q ,r are roots of equation x^3-3^x+11=0 then the equation whose roots are (p+q),(q+r),(r+s) is:
since it's a cubic equation..finding roots become very tough..is there any solution??
value of 'a' for which quadratic equation (1-2a)x^2-6ax-1=0 and ax^2-x+1=0 have atleast one root in common???
@challenger90 said: value of 'a' for which quadratic equation (1-2a)x^2-6ax-1=0 and ax^2-x+1=0 have atleast one root in common???
I think a = 1/2 ll do that;) ll share the approach if it's right
@challenger90 said: if p , q ,r are roots of equation x^3-3^x+11=0 then the equation whose roots are (p+q),(q+r),(r+s) is: since it's a cubic equation..finding roots become very tough..is there any solution??
Is it 3^x or 3*x ?
Such questions are better done by using options.
if x-y = 12 * (x+y)
100(denominator of 12* (x+y)
den dey have written x/y= 14/11
anyone elaborate pls
100(denominator of 12* (x+y)
den dey have written x/y= 14/11
anyone elaborate pls
A salseman gets commision on total sales at 9%. If the sale is exceeded by Rs 10,000 he gets additional comm as bonus of 3% on the excess of sales over 10,000. If he gets total comm of Rs 1380, then bonus recived is
soln
comm upto 10k =10,000 * 9/100 = 900
after 10k
comm bonus
9 : 3
soln
comm upto 10k =10,000 * 9/100 = 900
after 10k
comm bonus
9 : 3
3x: x
bonus = (1380-900)* 1/4= 120(ans)
how come 1/4 divided...??????
bonus = (1380-900)* 1/4= 120(ans)
how come 1/4 divided...??????
hey guys
m a total newbie here
got a question
Q- 1! x 2! x .........X 50! find the number of consecutive zeroes
ans options given are 235,12,262,105
but m gettin ans as 62
m i right??? r the options incorrect????
if not kindly provide the right ans along with the logic used
Thanks.....
@[596070:niranjan031286]
Yes it is 62 & your approach is correct !
@[563226:mbajamesbond]
the answer should be 28
so before the last match his avg was 30
only this option satisfies nothing else