@[520788:LeoN88] thanks a ton leon
ABC sells watch to wholesaler and making profit of 10%. The wholeseller sells to retailer n making profit of 10%. A custo purchases at 990.Profit of retailer is 2 3/11 %. cost inc by ABC to produce it..
solution is::::
[(x * 1.1) * 1.1) * 1125/1100] = 990
i understood everything is just when we calcluate 2 3/11 it will come 25/11...so how come 1125/1100...generally we do 1.2 if 20 % profit is der....
responses will be highly appreciated
solution is::::
[(x * 1.1) * 1.1) * 1125/1100] = 990
i understood everything is just when we calcluate 2 3/11 it will come 25/11...so how come 1125/1100...generally we do 1.2 if 20 % profit is der....
responses will be highly appreciated
a shopkeeper calc his profit percent on s.p which comes out to be 30%. If it had been calcluated as usual on c.p wht is the required percentage profit
a)42 6/7% b) 41 2/3%
SOln is:::
cp sp
70 100
---------3/7 increase----->
1st decrease 30% i got
next increase 3/10-3=3/7...i got but
ans is 42 6/7%....HOW
response will be appreciated
---------3/7 increase----->
1st decrease 30% i got
next increase 3/10-3=3/7...i got but
ans is 42 6/7%....HOW
response will be appreciated
Guys Please reply its urgent...
http://www.pagalguy.com/forums/cat-and-related-bschools/sinhgad-vadgao-imdr-pune-t-84031/p-3594277
@jeetuachtani said: a shopkeeper calc his profit percent on s.p which comes out to be 30%. If it had been calcluated as usual on c.p wht is the required percentage profita)42 6/7% b) 41 2/3%SOln is:::1st decrease 30% i gotnext increase 3/10-3=3/7...i got butans is 42 6/7%....HOWresponse will be appreciated
---------------------------------
1st time He calculated on base as SP So SP=100 then CP=70 as loss is 30
Now req. (100-70)/70
1st time He calculated on base as SP So SP=100 then CP=70 as loss is 30
Now req. (100-70)/70
3/7 approx. 14.x * 3 so ans. 42.xx
Hello,
I'm CAT'12 aspirant. For practice of variety of questions, I intend to go beyond the Institute course material.
Need suggestion on the following:-
1. Quant or the set of books-IS THE SET OF BOOKS- HOW TO PREPARE FOR CAT BY ARUN SHARMA AND MEENAKSHI UPADHAY IS WORTH BUY OR SHOULD I BUY THE QUANT BOOK ONLY.
2. IF NOT THE SET- IF U DONT RECOMMEND THE SET, THEN WHICH BOOKS HSUD BE BOUGHT FOR PRACTISE OF OTHER HEADS VIS-A-VIS THE DI/VA/LR
THANKS
Find the domain
1) [0,4]
y = [log(5x-x^2)/4)]^1/2
2) [0,5]
3) [-4,-1]
4) [-1,5]
:)
hey hie everyone...
i m solvng Quantum cat......so is dis book as gud as arun sharma....is it sufficient???
or should i study arun sharma also.............
PS: can i ask qus frm QC here in dis thread
@GuptaSukriti said: hey hie everyone... i m solvng Quantum cat......so is dis book as gud as arun sharma....is it sufficient???or should i study arun sharma also............. PS: can i ask qus frm QC here in dis thread
Quantum CAT is a Good Book. No Doubt in that. Both Quantum and Arun Sh have their own good chapters. Anyways, doing Quantum is equal as in doing Arun, so you need not worry on that.
And yeah, you can post questions from that book here or else on the Quant Thread without giving a second thought.
@AbhiCAT2012 said: Find the domain y = [log(5x-x^2)/4)]^1/2 1) [0,4]2) [0,5]3) [-4,-1]4) [-1,5]
Tools to solve this Qn :
1) Log of a negative no. is not defined.
2) Log of 0 is not defined.
Now check the answer choices.
- (3) and (4) will involve negative nos. and hence can make the argument of log function negative. So none of these two can be the answer
- For choice (2), if we take x=5 the argument of Log is 0 which is not defined.
Also for x=0, y is again not defined.
This eliminates choice (1) also because it contains the element 0.
Hence ideally the correct answer choice is (5)None of These, which you might have forgotten to add.
Or
the first choice is actually a half open interval (0,4]
@AbhiCAT2012 said: Find the domain y = [log(5x-x^2)/4)]^1/2 1) [0,4]2) [0,5]3) [-4,-1]4) [-1,5]
To find the range,equate y = 0
=>(1/2)* log[(5x - x^2)/4] = 0
=>(5x - x^2)/4 = 10^0
=> 5x - x^2 = 4
Solving quadratic equation x^2 -5x + 4,we get x = 1 or 4
So the range would be (0,5) and not [0,5]
@[568667:Psychamour]
well these are the options available in Arun Sharma
I had a doubt that's y i posted here
Thanks for the quick response
Also for x=5 this will be 0 ,, so answer could be (0,5)
@[550618:mani0303]
Right
😃
Please answer:
Two poles of height a and b units are c units apart from each other. The height h of the point of intersection of lines joining the top of each pole to the foot of opposite pole is_____ of the height of two poles.
1. AM
2. GM
3. HM/2
@davidvilla7 said: Please answer: Two poles of height a and b units are c units apart from each other. The height h of the point of intersection of lines joining the top of each pole to the foot of opposite pole is_____ of the height of two poles. 1. AM 2. GM 3. HM/2
hm/2
@[550618:mani0303] the least value of n for which the sum series 5+8+11+.....n terms is not less than 670 wats the answer this is frm progression
and one more qstn a man recieves Rs 60 for the first week and Rs 3 more each week than the preceding week. how much does he earn by 20th week.
@sahib_sheetu said: @mani0303 the least value of n for which the sum series 5+8+11+.....n terms is not less than 670 wats the answer this is frm progression and one more qstn a man recieves Rs 60 for the first week and Rs 3 more each week than the preceding week. how much does he earn by 20th week.
1)nth term in the series is 3n + 2
Summation of n terms would be [3*n*(n+1)]/2 + 2n >= 670
Check for easier terms like 10,15,or 20
At n = 20,[3*n*(n+1)]/2 + 2n = 670
2)For the 2nd,he gets 3 more than 1st,
for 3rd week,he gets 6 more than 1st
so,for the 20th week,he gets 19*3(=57) more than 1st
So,the amount earned on 20th week is 60 + 3*19 = 117