In a town consisting of three localities A, B and C, the population of the three localities A, B and C are in the ratio 9:8:3. In locality A, 80% of the people are literate, in locality B, 30% of the people are illiterate. If 90% people in locality C are literate, find the percentage literacy in that town. (a) 61.5% (b) 78% (c) 75% (d) None of these
i worked in this way: let the population be x 9x+8x+3x=100 x=5 A=45,B=40,C=15 then A=80/100*45=36 B=30/100*40=12 C=90/100*15=13.5 approx 13 39/100*100=39%
can u please tell me whether i am right??coz the question paper doesnt contain the answer..thanx in advance
i think there is some mistake in your solution my answer is coming out as 61.xx% literacy rate....
To pass an exam ,40% marks are essential.A obtains 10% marks less than the pass marks and B obtains 11.11% marks less than A.what percent less than the sum of A's and B's marks should c obtain to pass the exam? 1)40% 2)41(3/17)% 3)28% 4)Any of these pls explain the answer in detail with steps
To pass an exam ,40% marks are essential.A obtains 10% marks less than the pass marks and B obtains 11.11% marks less than A.what percent less than the sum of A's and B's marks should c obtain to pass the exam? 1)40% 2)41(3/17)% 3)28% 4)Any of these pls explain the answer in detail with steps
my take is option 3...what is the correct answer....plz share that...then i will xplain my approach
To pass an exam ,40% marks are essential.A obtains 10% marks less than the pass marks and B obtains 11.11% marks less than A.what percent less than the sum of A's and B's marks should c obtain to pass the exam? 1)40% 2)41(3/17)% 3)28% 4)Any of these pls explain the answer in detail with steps
Let the Total marks be 100 => To pass 40 marks is required => A obtains 36 marks => B obtains 32 marks Sum of A and B's marks = 36+32 = 68 Therefore to pass the exam C needs 68-40 = 28 marks less than the sum of A and B => % = 28/68 * 100 => 700/17 => 41(3/17)
To pass an exam ,40% marks are essential.A obtains 10% marks less than the pass marks and B obtains 11.11% marks less than A.what percent less than the sum of A's and B's marks should c obtain to pass the exam? 1)40% 2)41(3/17)% 3)28% 4)Any of these pls explain the answer in detail with steps
total marks:::100 pass :: 40 a scores:::36 b score ::::32 a+b::68 Now 40=68(1 - x/100) find x x= (28/6100 Ans::option 2 :::41(3/17) Regards, Never Back Down
In a town consisting of three localities A, B and C, the population of the three localities A, B and C are in the ratio 9:8:3. In locality A, 80% of the people are literate, in locality B, 30% of the people are illiterate. If 90% people in locality C are literate, find the percentage literacy in that town. (a) 61.5% (b) 78% (c) 75% (d) None of these
i worked in this way: let the population be x 9x+8x+3x=100 x=5 A=45,B=40,C=15 then A=80/100*45=36 B=30/100*40=12 C=90/100*15=13.5 approx 13 39/100*100=39%
can u please tell me whether i am right??coz the question paper doesnt contain the answer..thanx in advance
No need for assuming total population to be 100 in this problem. Just take them as 9,8 and 3 Literate in A = 9 *0.8 = 7.2 Literate in B = 8 *0.7 = 5.6 Literate in C = 3 * 0.9 = 2.7 Total Literate in A,B,C = 7.2+5.6+2.7 = 15.5 Total population = 20 Percentage literate = 15.5/20 = 77.5%
The hourly wages of a female labour are increased by 12.5%, whereas the weekly working hours are reduced by 8%. Find the percentage change in the weekly wages if she was getting 1200 per week for 50 hours..pls explain with steps
The hourly wages of a female labour are increased by 12.5%, whereas the weekly working hours are reduced by 8%. Find the percentage change in the weekly wages if she was getting 1200 per week for 50 hours..pls explain with steps
It should be 42.
She gets 12.5% more => She gets (9/8 )th of orginal price. Initially she used to get (1200/50) = Rs. 24 per hour Now she gets 24*9/8 = Rs. 27 per hour
The weight of an iron bucket increases by 33.33% when filled with water to 50% of its capacity. Which of these may be 50% of the weight of the bucket when it is filled with water( assume the weight of bucket and its capacity in kg to be integers?.. pls explain in detail with steps
The weight of an iron bucket increases by 33.33% when filled with water to 50% of its capacity. Which of these may be 50% of the weight of the bucket when it is filled with water( assume the weight of bucket and its capacity in kg to be integers?.. pls explain in detail with steps
'Which of these' is missing here.. Anyway, let weight of empty bucket be 3x. => 3x is integer
When half filled; it increases by 33.33% => It becomes 4x. => Capacity of bucket = 2x => 2x is also integer
As 3x and 2x are integers; x must be integer.
Now, weight of half filled bucket = 4x => Multiple of 4 => Choose multiple of 4 from option
The weight of an iron bucket increases by 33.33% when filled with water to 50% of its capacity. Which of these may be 50% of the weight of the bucket when it is filled with water( assume the weight of bucket and its capacity in kg to be integers?.. pls explain in detail with steps
'Which of these' is missing here.. Anyway, let weight of empty bucket be 3x. => 3x is integer
When half filled; it increases by 33.33% => It becomes 4x. => Capacity of bucket = 2x => 2x is also integer
As 3x and 2x are integers; x must be integer.
Now, weight of half filled bucket = 4x => Multiple of 4 => Choose multiple of 4 from option
Here weight bucket=x and water when filled 50% its weight=y Given => x + y =1.33 x => x=3y now in second case u need to find x + 2y because it says when filled with water. y was 50% so 2y for full water => so we are looking for 3y+2y = 5y => A multiple of 5 in the answer.
Here weight bucket=x and water when filled 50% its weight=y Given => x + y =1.33 x => x=3y now in second case u need to find x + 2y because it says when filled with water. y was 50% so 2y for full water => so we are looking for 3y+2y = 5y => A multiple of 5 in the answer.
Aah.. I though we have to find the weight of half filled water.. Yes, if it is weight of completely filled bucket, it will be a multiple of 5.
Here weight bucket=x and water when filled 50% its weight=y Given => x + y =1.33 x => x=3y now in second case u need to find x + 2y because it says when filled with water. y was 50% so 2y for full water => so we are looking for 3y+2y = 5y => A multiple of 5 in the answer.
hi dude could u explain this step x=3y more clearly coz if x+y=1.33x then y=0.33x
a salesman is appointed on the basic salary of ts. 1200 per month and the condition that for everty sales of Rs. 10000 above Rs. 10000 he will get 50% of the basic salary and 10% of the sales as a reward. htis incentive scheem does not operate for the first Rs 10000 of sales. what should be the vaslude of sales if he wants to earn Rs. 7600 in a month a) 60000 b)50000 c)40000 d)none of these
Two numbers are in ratio P:Q. When 1 is added to both the numerator and denominator,the ratio gets changed to R/S. Again when 1 is added to both the numerator and denominator, it becomes 1/2. Find the sum of P and Q.
a salesman is appointed on the basic salary of ts. 1200 per month and the condition that for everty sales of Rs. 10000 above Rs. 10000 he will get 50% of the basic salary and 10% of the sales as a reward. htis incentive scheem does not operate for the first Rs 10000 of sales. what should be the vaslude of sales if he wants to earn Rs. 7600 in a month a) 60000 b)50000 c)40000 d)none of these
Two numbers are in ratio P:Q. When 1 is added to both the numerator and denominator,the ratio gets changed to R/S. Again when 1 is added to both the numerator and denominator, it becomes 1/2. Find the sum of P and Q.
explain with steps
(1) My take is 50000
He earns 1200 as basic salary. And for first 10000; he will not get bonus. => He needs to earn (7600-1200) = 6400 for sale of 10000 onwards.
He earns 50% of bonus of basic salary => 50% of 1200 => Rs. 600 And 10% on sales => 10% of 10000 => Rs. 1000
=> Total 1600 => He needs to make 6400/1600 = 4 more sales of rs. 10000 each => Total sales = 10000 + 4*10000 = 50000
(2) It cannot be determined
P/Q = (k-2)/(2k-2) If k = 3; P/Q = 1/4 If k = 4; P/Q = 2/6 = 1/3
A and B are two alloys of argentum and brass prepared by mixing metals in proportions 7 : 2 and 7:11 respectively. If equal quantities of the two alloys are melted to form a third alloy C, the proportion of argentum and brass in C will be (a) 5 : 9 b)5:7 c)7:5 d)9:5 e)7:9 the given answer is 7:5 pls explain with proceedings thanks in advance
A and B are two alloys of argentum and brass prepared by mixing metals in proportions 7 : 2 and 7:11 respectively. If equal quantities of the two alloys are melted to form a third alloy C, the proportion of argentum and brass in C will be (a) 5 : 9 b)5:7 c)7:5 d)9:5 e)7:9 the given answer is 7:5 pls explain with proceedings thanks in advance
answer is correct...and let me tell you a trick for these kinds of question...always for saveing time and escpaeing from calculation...take lcm of 2 values given...for ex..here A=7:2=7+2=9 B=7:11=7+11=18 take lcm of both...will shorten calculation...here it will be 18...now take 18 as the amount of both alloy(A,B) and then just add them you will find the answer... hope it will help...
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