answer is correct...and let me tell you a trick for these kinds of question...always for saveing time and escpaeing from calculation...take lcm of 2 values given...for ex..here A=7:2=7+2=9 B=7:11=7+11=18 take lcm of both...will shorten calculation...here it will be 18...now take 18 as the amount of both alloy(A,B) and then just add them you will find the answer... hope it will help...
i got 14 kg of 1st and 7 kg of 2nd i was unable to proceed further i too used the same technique..can u explain more clearly
i got 14 kg of 1st and 7 kg of 2nd i was unable to proceed further i too used the same technique..can u explain more clearly
Hello, for A a=7/9 b=2/9 for B a=7/18 b =11/18 irrespective of any wt. for c let take equal quantity of both say X total a in c= 7X/9 + 7X/18--------------------(1) total b in c= 2X/9 + 11X/18--------------------(2) req.= (1)/(2) it's coming 21/15 , for simplicity take X to be 18 ie LCM(9,1 Regards, Never Back Down.
The sum of the numerator and denominater of a +ve fraction is 11,if 2 is added to both num..and den..,,the fraction is increased by 1/24.the difference of numerator and denominater of the fraction is A) 5 B) 3 C) 1 D) 9 what is the detail solution.
The sum of the numerator and denominater of a +ve fraction is 11,if 2 is added to both num..and den..,,the fraction is increased by 1/24.the difference of numerator and denominater of the fraction is A) 5 B) 3 C) 1 D) 9 what is the detail solution.
Let the fraction be x/y
x+y=11 => x=11-y......(1)
x+2/y+2=x/y + 1/24 Solving this and putting the value of x we will get a quadratic in y
The sum of the numerator and denominater of a +ve fraction is 11,if 2 is added to both num..and den..,,the fraction is increased by 1/24.the difference of numerator and denominater of the fraction is- A) 5 B) 3 C) 1 D) 9 what is the detail solution.
x+y =11 x+2 / y+2 =x/y +1/24 x+2/y+2 =24x+y / 24y Cross multiply and u will get y^2 +2y+48x-48y Replace the value of x with x=11-y and by solving u will get y^2-94y+528=0 solve this quadratic equation and y=6 will come x+y=11 then x=5 differ. =1
In triangle ABC,O IS THE CENTROID AND AD ,BE,CF ARE THREE MEDIANS ABD THE AREA OF TRIANGLE AOE= 15 CM^2 THEN THE AREA OF QUADRILATERAL BDOF IS A)20 CM^2 B)30 cm^2 C)40 cm^2 D)25 cm^2
In triangle ABC,O IS THE CENTROID AND AD ,BE,CF ARE THREE MEDIANS ABD THE AREA OF TRIANGLE AOE= 15 CM^2 THEN THE AREA OF QUADRILATERAL BDOF IS A)20 CM^2 B)30 cm^2 C)40 cm^2 D)25 cm^2
thanks in advance guys
Given Area of Triangle AOE = 15 => 1/2 * OE * OA = 15 => 1/2 * x * 2x = 15 => x^2 = 15 Now for area of quadrilateral BDOF => Area of triangle OBD + OBF => 1/2 * OD * OB + 1/2 * OF * FB => 1/2 * x * 2x + 1/2 * x * 2x => 2x^2 => 30cm^2
1) After an increment of 7 in both numerator and the dinominator,a fraction changes to 3/4.find the original fraction
1.)2/5....
solution of 1st question let the fraction be N/D now add 7 to both N+7/D+7=3/4 now solve the equation...you will get 4N=3D-7 it is an simple equation which gets satisfiesd on D=5 and N=2 kindly share solution of 3rd question..let me know where i am lacking....
solution of 1st question let the fraction be N/D now add 7 to both N+7/D+7=3/4 now solve the equation...you will get 4N=3D-7 it is an simple equation which gets satisfiesd on D=5 and N=2 kindly share solution of 3rd question..let me know where i am lacking....
I solved third one using Using chain rule: 30*6/7*2=18*1/7*x x=180*2/18=20 days
if a and b are positive integers then 2 always lies between a) (a+b)/(a-b) and ab b) a/b and (a+2b)/(a+b) c) a and b d)ab/(a+b) and (a-b)/ab e)a+b and ab
if a and b are positive integers then 2 always lies between a) (a+b)/(a-b) and ab b) a/b and (a+2b)/(a+b) c) a and b d)ab/(a+b) and (a-b)/ab e)a+b and ab
pls explain wit steps
my take is option (d) what is the correct answer... best possible way to do such kind of question is assume 2 values... a=10 and b=20...and try to take bigger value but easy one...or i would say the one's which end with zeros because they will make calculation easy........put them in different options and you will get your answer... correct me if i am wrong