In an examination,80% of students passed in english,85% in Maths and 75% in both English and maths.if 40students failed in both the subject find the total number of students in this n(a)=80 n(b)=85 n(AUB) should be 75% but they have given a(AB) as 75% hw cum its possible.. im really confused by such problems..can any one clearly explain the difference.thanks in advance
My take is 400.
See.. 75% passed in both. Now, 80% passed in English => Only english = (80-75)% = 5% And only Maths = (85-75)% = 10%
So, total passed = (Passed in both) + (Passed in only 1) = 75 + (5+10) = 90%
So, 10% failed in both the subjects. As 40 failed in both the subjects, total number of students = 400
1)A and B can do a piece of work in 18 days, B and C can do it in 24 days, A and C can do it in 36 days. In how many days will A,B and C finish it, working together and separately?
2)45 men can complete a work in 16 days. 6 days after they started working, 30 more joined them. How many days will they take now to complete the remaining work?
1)A and B can do a piece of work in 18 days, B and C can do it in 24 days, A and C can do it in 36 days. In how many days will A,B and C finish it, working together and separately?
2)45 men can complete a work in 16 days. 6 days after they started working, 30 more joined them. How many days will they take now to complete the remaining work?
(1) My take is 16
Days take are (18, 24, 36) => 6 * (3, 4, 6)
Now, let's consider (3, 4, 6) and in the end multiply by 6. => (A, B) do 24/3 = 8 units per day => (B, C) do 24/4 = 6 units per day => (C, A) do 24/6 = 4 units per day
=> (A, B) + (B, C) + (C, A) do 8+6+4 units per day => 2*(A+B+C) do 18 units per day => A+B+C do 9 units per day
=> A+B+C will take 24/9 days to complete work Multiplying by 6 now, A, B and C will together take 6*(24/9) = 16 days
(2) My take is 6
Total work units = 45*16 After 6 days, 45*6 are done and 45*10 are left.
Now, let's consider (3, 4, 6) and in the end multiply by 6. => (A, B) do 24/3 = 8 units per day => (B, C) do 24/4 = 6 units per day => (C, A) do 24/6 = 4 units per day
=> (A, B) + (B, C) + (C, A) do 8+6+4 units per day => 2*(A+B+C) do 18 units per day => A+B+C do 9 units per day
=> A+B+C will take 24/9 days to complete work Multiplying by 6 now, A, B and C will together take 6*(24/9) = 16 days
(2) My take is 6
Total work units = 45*16 After 6 days, 45*6 are done and 45*10 are left.
Now, 30 more men join => Total men = 75
=> Days needed = (45*10)/75 = 6
could you explain why 24 in the foll. step?? => (A, B) do 24/3 = 8 units per day => (B, C) do 24/4 = 6 units per day => (C, A) do 24/6 = 4 units per day
could you explain why 24 in the foll. step?? => (A, B) do 24/3 = 8 units per day => (B, C) do 24/4 = 6 units per day => (C, A) do 24/6 = 4 units per day
LCM of (3, 4, 6) being 24; we have assumed the total work amount = 24 units As (A, B) take 3 days together; they do 24/3 units = 8 units per day.. And so on..
LCM of (3, 4, 6) being 24; we have assumed the total work amount = 24 units As (A, B) take 3 days together; they do 24/3 units = 8 units per day.. And so on..
1)A and B can do a piece of work in 18 days, B and C can do it in 24 days, A and C can do it in 36 days. In how many days will A,B and C finish it, working together and separately?
2)45 men can complete a work in 16 days. 6 days after they started working, 30 more joined them. How many days will they take now to complete the remaining work?
1. 1/A+1/B =1/18 1/B+1/c = 1/24 1/A+1/C= 1/36 Adding all 2(1/A+1/B+1/C)= 1/18+1/24+1/26 Solving 1/A+1/B+1/C = 1/4 So total 4 days. 2. total man-hours days = 45*16 = 720 for 6 days = 45*6 = 270 720-270 = 450 Now 30 more joined so 45+30 = 75 so total days 450/75 = 6 My take
1.)find 28383rd term of the series...12345678910111213141516....?
2.)if you form a subset of integers chosen from between 1 to 3000,such that no two integers add up o a multiple of nine,what can be the maximum number of elements in the subset?
1)the cost manufacture of an article is made up of four components A,B,C,D which have a ratio 0f 3:4:5:6 respectively.if there are respective changes in the cost of +10%,-20%,-30% and +40% then wat would be the % change in cost.
2) Harsh receives an inheritance of a certain amount from his grandfather. Of this he loses 32.5% in his effort to produce a film. From the balance, a taxi driver stole the sum of 100000 that he used to keep in his pocket.of the rest he donated 20% to a charity.further he purchases a flat in Ganga APt for Rs.7.5 lakh.he then realises that he is left with only Rs.2.5 lakh cash of his inheritance.what was the value of his inheritance pls explain the steps in detail
1.)find 28383rd term of the series...12345678910111213141516....?
2.)if you form a subset of integers chosen from between 1 to 3000,such that no two integers add up o a multiple of nine,what can be the maximum number of elements in the subset?
kindly help in the both the questions
1. 9+90*2+900*3+4x = 28383 => x= 6373, rem = 2 6373 63. 28383rd digit is 3.
2. Remove all numbers which leaves remainder of 1,2,3,4 by dividing 9 => Number of numbers which leaves 1,2,3,4 as remainders is (3000/9) * 4 = 1332 + 1(One multiple of 9 can be thr) = 1333
1)the cost manufacture of an article is made up of four components A,B,C,D which have a ratio 0f 3:4:5:6 respectively.if there are respective changes in the cost of +10%,-20%,-30% and +40% then wat would be the % change in cost.
2) Harsh receives an inheritance of a certain amount from his grandfather. Of this he loses 32.5% in his effort to produce a film. From the balance, a taxi driver stole the sum of 100000 that he used to keep in his pocket.of the rest he donated 20% to a charity.further he purchases a flat in Ganga APt for Rs.7.5 lakh.he then realises that he is left with only Rs.2.5 lakh cash of his inheritance.what was the value of his inheritance pls explain the steps in detail
1. A=30, B=40, C=50, D=60 => Total cost = 180 Now, A=33, B=32, C=35, D=84 => Total new cost = 184 => Increase% = 4/180 * 100 => 2.22%
2. Inheritence left = x Money Left after producing a failed film = 67.5x/100 Money left after getting mugged = 67.5x/100 - 100000 Money left after donating to charity = 0.8*(0.675x - 100000) Money left after purchasing apt = 0.8*(0.675x - 100000) - 750000 => 0.8*(0.675x - 100000) - 750000 = 250000 => 0.8*(0.675x - 100000) = 1000000 => 0.54x - 80000 = 1000000 => x = 20 lakhs
the entrance ticket at the Minerva theatre in Mumbai is worth Rs.250. wen the price of the ticket was lowered, the sale of the tickets increased by 50% while the collections decreased by 17.5%. find the deduction in the ticket price? a) 150 b) 112.5 c) 105 d) 120 pls explain i detail with stepss
the entrance ticket at the Minerva theatre in Mumbai is worth Rs.250. wen the price of the ticket was lowered, the sale of the tickets increased by 50% while the collections decreased by 17.5%. find the deduction in the ticket price? a) 150 b) 112.5 c) 105 d) 120 pls explain i detail with stepss
Suppose 1 ticket was originally sold so total collection = 250 finally 1.5 tickets were sold for = 250*(82.5/100) Therefore,deduction in price,= 250 - 250*(82.5/100) = Rs.112.50
the entrance ticket at the Minerva theatre in Mumbai is worth Rs.250. wen the price of the ticket was lowered, the sale of the tickets increased by 50% while the collections decreased by 17.5%. find the deduction in the ticket price? a) 150 b) 112.5 c) 105 d) 120 pls explain i detail with stepss
Lets say that x people came to the theatre. Total money collected = 250*x Now the no of people increased to 1.5x => 1.5x * P = 0.825 * 250x => P = 137.5 Hence cost reduced = 250 - 137.5 = 112.5
the entrance ticket at the Minerva theatre in Mumbai is worth Rs.250. wen the price of the ticket was lowered, the sale of the tickets increased by 50% while the collections decreased by 17.5%. find the deduction in the ticket price? a) 150 b) 112.5 c) 105 d) 120 pls explain i detail with stepss
My take B 112.5
Let the initial sales be "x"
250 * x = 250x --> Total Sales-->EQ 1
After the change :
(250-y) * 1.5x = 82.5 * 250x --> EQ2
Dividing 1 by 2
250/1.5(250-y) = 1/82.5
82.5 * 250 = 375 - 1.5y
y = 112.5
This method is the conventional one. Any smart cuts?
P.S : Hehehe already 3 answers . Have to increase my typing speed!
in an examination 45% students failed in hindi and 32% failed in History,20% failed in both the subjects.if the number of students who passed the examination was 880,how many students appeared in the examination consisted only of these two subjects..
