Quant by Arun Sharma

Buddy sorry for late reply, I do like solving prob so lazyness gets negated :D

1)If Sardar Preetpal Singh's taxi is 14 years old and has a fuel efficiency of 12km/litre of fuel, find his profit in a run from Howrah Station to Park Street (a distance of 7 kms) if the stoppage time is 8 minutes. Assume he owns the taxi

Cost of petrol for 7km journey =>8.75 (price of petrol-rs 15/litre from prob statement)
now calculate the metre charege =>10+5x5+8=>43+8.6=>51.6

here 10 - charge for first 2 km
5x5=> charges for next 5 km as for every km he takes 5rs
8=>waiting charges
8.6=>20% pay over meter reading
profit=>51.6-8.75
=>42.85

2)the percentage profit is :

51.6-8.75/8.75
=>489.71%

3)with increase of 13 min in waiting time =>10+5x5+13=>48+9.6=>57.6
profit=>57.6-8.75=>48.85
=>48.85-42.85/42.85
=>14%

Thanks a lot buddy..:grin::grin:
Buddy sorry for late reply, I do like solving prob so lazyness gets negated :D

1)If Sardar Preetpal Singh's taxi is 14 years old and has a fuel efficiency of 12km/litre of fuel, find his profit in a run from Howrah Station to Park Street (a distance of 7 kms) if the stoppage time is 8 minutes. Assume he owns the taxi

Cost of petrol for 7km journey =>8.75 (price of petrol-rs 15/litre from prob statement)
now calculate the metre charege =>10+5x5+8=>43+8.6=>51.6

here 10 - charge for first 2 km
5x5=> charges for next 5 km as for every km he takes 5rs
8=>waiting charges
8.6=>20% pay over meter reading
profit=>51.6-8.75
=>42.85

2)the percentage profit is :

51.6-8.75/8.75
=>489.71%

3)with increase of 13 min in waiting time =>10+5x5+13=>48+9.6=>57.6
profit=>57.6-8.75=>48.85
=>48.85-42.85/42.85
=>14%

Thanks a lot buddy..:grin::grin:

can anyone please explain how to find the remainder of
50^51^52 divided by 11

A and B walk up the escalator (moving stairway) .The escalator moves at a constant speed ,A takes six steps for every four of B's steps .A gets to the top of the escalator after having taken 50 steps ,while B (because his slower pace lets the escalator do a little more of the work ) takes only 40 steps to reach the top,If the escalator were turned off, how many steps would they have to walk up ??
(a)80
(b)100
(c)120
(e) 160

plzz mention the logic behind this ......

can anyone please explain how to find the remainder of
50^51^52 divided by 11

50^51^52 is divided by 11
=>6^51^52 divided by 11
=>(3x2)^51^52 divided by 11
=>(3)^51^52 divided by 11 x (2)^51^52 divided by 11

now use format little theorem
from format little theorem wkt 3^10/11=1 and 2^10/11=1
51^52/10=1 so 51^52 can be put in the form 10k+1

so 3^(10k+1)/11 x 2^(10k+1)/11
3^10k=1 and 2^10k=1
so remainder is 3x2/11=>6

A and B walk up the escalator (moving stairway) .The escalator moves at a constant speed ,A takes six steps for every four of B's steps .A gets to the top of the escalator after having taken 50 steps ,while B (because his slower pace lets the escalator do a little more of the work ) takes only 40 steps to reach the top,If the escalator were turned off, how many steps would they have to walk up ??
(a)80
(b)100
(c)120
(e) 160

plzz mention the logic behind this ......

lets consider A speed as 6 steps/min and B speed as 4steps/min

here A has climed 50 steps in 8.33 min and B has climed 40 steps in 10 min.. Remember escalator speed is same for both..
solve through options from here
if no of steps is 80 escalator has covered 30 steps in 8.33 min => 3.6 steps/min
in case of B escalator has covered 40 steps in 10 mins=>4 steps/min

So there is disparity, u need to get same speed.

for 100 steps u get same speed
=>for A 50/8.33=>6 steps/min
=>for B 60/10=>6steps/min

thanks a lot

Hi! I have some questions to ask from Quadratic Equations LOD - I

1. For the equation, 2^a+3 = 4^a+2 - 48, the value of 'a' will be
a) -3/2 b) -3 c) -2 d) 1

2. If a=sqrt(7+4 sqrt(3)), what is the value of (a +1/a)?
a) 7 b)4 c) 3 d)2


3. For what values of c in the equation 2x^2 - (c^3 + 8c - 1)x + c^2 - 4c = 0, the roots of the equation will be opposite in signs?

a) (0,4) b) (-4,0) c) (0,3) d) (-4,4)


Please post solutions.. Thanks!

Hi! I have some questions to ask from Quadratic Equations LOD - I

1. For the equation, 2^a+3 = 4^a+2 - 48, the value of 'a' will be
a) -3/2 b) -3 c) -2 d) 1

2. If a=sqrt(7+4 sqrt(3)), what is the value of (a +1/a)?
a) 7 b)4 c) 3 d)2


3. For what values of c in the equation 2x^2 - (c^3 + 8c - 1)x + c^2 - 4c = 0, the roots of the equation will be opposite in signs?

a) (0,4) b) (-4,0) c) (0,3) d) (-4,4)

Please post solutions.. Thanks!


answers are in bold

1) 2^a+3 = 4^a+2 - 48
=>16*2^2a-8*2^a-48=0

Putting 2^a=x,we get 16x^2-8x-48=0
on solving,x=-3/2,2 but -3/2 is not possible so x=2^a=2.So,a=1

2)a=sqrt(7+4 sqrt(3))

a^2=7+4 sqrt(3), 1/a^2=1/(7+4 sqrt(3))=7-4 sqrt(3)

(a+1/a)^2=a^2+1/a^2+2=7+4 sqrt(3)+7-4 sqrt(3)+2
=16
So,a+1/a=4

3)For roots of eqn ax^2+bx+c to be of opposite sign, product of roots must be -ve ie (c/a)
So,(c^2-4c)/2 this gives c in the range (0,4)

Hope it helps

cheers

Pls explain.
Seven diff. objects must be divided among 3 ppl. in how many ways can this be done if one or two of them can get no object. ??

Puys Need ur help with these qsns
Profit and Loss

LOD 2 q16
A shopkeeper makes a profit of Q% by sellig an object for rs24.Had c.p and s.p be interchanged it would have led to a loss of 62.5Q%.With the latter c.p what should be the new s.p to make a profit of Q%?
34.4 32.5 25.6 38.8

Percentages
LOD 2 q40
Of the adult population in NAgpur, 45%of men and 25 % of women are married. What % of total population of adults is married?(assume no man marries more than one woman and vice versa)
33.33% 32.14% 31.1% None of these

1) in second case cost price is 24 and since he makes a lose of 62.5% selling price would be 15(got by 24/1.625).

so to make a profit of 9/24(15 is cp and 24 is sp in first case) u should sell it 32.5

2)Here 45M=25F because each man cant have two wife's and vice-verse
so M/F=9/5
so 45%M=450 then 25%F=450
total adult population=>1000+1800
=>900/1800
=>32.14%

herz my approach

LOD 2 q16
A shopkeeper makes a profit of Q% by sellig an object for rs24.Had c.p and s.p be interchanged it would have led to a loss of 62.5Q%.With the latter c.p what should be the new s.p to make a profit of Q%?
34.4 32.5 25.6 38.8

answer should be 38.8 . my approach is quite wierd



Both ur aswrs are correct,can u plz post the approach for the 1st qsn
Puys Need ur help with these qsns
Profit and Loss

LOD 2 q16
A shopkeeper makes a profit of Q% by sellig an object for rs24.Had c.p and s.p be interchanged it would have led to a loss of 62.5Q%.With the latter c.p what should be the new s.p to make a profit of Q%?
34.4 32.5 25.6 38.8

Percentages
LOD 2 q40
Of the adult population in NAgpur, 45%of men and 25 % of women are married. What % of total population of adults is married?(assume no man marries more than one woman and vice versa)
33.33% 32.14% 31.1% None of these

hey maybe i am wrong here..but i am kinda confused..
let,
cp = X rs
sp = 24 rs
Profit = (24-X)rs
Profit% = {/X}*100

since its a profitable deal, therefore X
now when cp and sp are interchanged, and its a loss situation,
Loss% = {/24}*100
since XProfit%
but it is given profit% = Q%
and loss% = 62.5Q%
i am confused here....
hey maybe i am wrong here..but i am kinda confused..
let,
cp = X rs
sp = 24 rs
Profit = (24-X)rs
Profit% = {/X}*100

since its a profitable deal, therefore X
now when cp and sp are interchanged, and its a loss situation,
Loss% = {/24}*100
since XProfit%
but it is given profit% = Q%
and loss% = 62.5Q%
i am confused here....


Buddy, i think you are going wrong with the bases on which you are calculating the percentages.

Profit/Loss is being calculated on the CP. Agreed. However the C.P. in the two cases isn't the same. For the first case its x and the next one its 24. So percentages are bound to differ.

Hope this solves your doubt:lookround: But my doubt still stands, how to solve this question??
Buddy, i think you are going wrong with the bases on which you are calculating the percentages.

Profit/Loss is being calculated on the CP. Agreed. However the C.P. in the two cases isn't the same. For the first case its x and the next one its 24. So percentages are bound to differ.

Hope this solves your doubt:lookround: But my doubt still stands, how to solve this question??

dude if u look at my explaination again u will find that i am nt at all confused with the bases on which the profit or loss percentage is calculated..profit percentage is calculated on the assumed cp i.e is rs X and loss percentage is calculated on rs 24..however since the first deal is profitable, therefore rs (cp)X.
this means the profit percentage should be more than the loss percentage..
but in the question stated above profit percentage is given as Q% and loss percentage is given as 62.5Q%..here is my doubt..please look into dis once again..and let me know where am i going wrong..
dude if u look at my explaination again u will find that i am nt at all confused with the bases on which the profit or loss percentage is calculated..profit percentage is calculated on the assumed cp i.e is rs X and loss percentage is calculated on rs 24..however since the first deal is profitable, therefore rs (cp)X.
this means the profit percentage should be more than the loss percentage..
but in the question stated above profit percentage is given as Q% and loss percentage is given as 62.5Q%..here is my doubt..please look into dis once again..and let me know where am i going wrong..


dude ur point taken. It makes sense, the only plausible way i c it happening though, is if loss% is 62.5%Q and not 62.5Q%. However, i double checked the qstn , it says 62.5Q%. Its gotta b a typo,but if anyone is to blame here its "ARUN SHARMA"!

And if its, 62.5%Q, then the question is a sitter, ans comes out to be 34.4 which is pretty close to the ans in book which is 38.8(probably another Typo!). It all makes sense:cheerio:

Thanks for bringing this up

please can any one suggest a good book for DI .......

Hi,

Please help me with this question with proper solution:


tuliram runs in a triathlon consisting of 3 phases in the following manner.running 12 km,cycling 24 kkm and swimming 5 km.his speeds in the 3 phases are in the ratio 2:6:1.he completes the race in n minutes.later he changes his stratgey so that the distances he covers in each phase are constant but his speeds are now in the ratio 3:8:1.the end result is that he completes the race taking 20 mins more than the earlier speed.it is also known that he has not changed his running speed when he changes his strategy.

if his speeds are in the ratio 1:3:1,with the running time remaining unchanged what is his finishing time?

Hi,

Please help me with this question in proper sol:

tuliram runs in a triathlon consisting of 3 phases in the following manner.running 12 km,cycling 24 kkm and swimming 5 km.his speeds in the 3 phases are in the ratio 2:6:1.he completes the race in n minutes.later he changes his stratgey so that the distances he covers in each phase are constant but his speeds are now in the ratio 3:8:1.the end result is that he completes the race taking 20 mins more than the earlier speed.it is also known that he has not changed his running speed when he changes his strategy.

if his speeds are in the ratio 1:3:1,with the running time remaining unchanged what is his finishing time?

Hi,

Please help me with this question in proper sol:

tuliram runs in a triathlon consisting of 3 phases in the following manner.running 12 km,cycling 24 kkm and swimming 5 km.his speeds in the 3 phases are in the ratio 2:6:1.he completes the race in n minutes.later he changes his stratgey so that the distances he covers in each phase are constant but his speeds are now in the ratio 3:8:1.the end result is that he completes the race taking 20 mins more than the earlier speed.it is also known that he has not changed his running speed when he changes his strategy.

if his speeds are in the ratio 1:3:1,with the running time remaining unchanged what is his finishing time?


It should be 2n/3 minutes. u havnt specified options, so i'm giving the ans in terms of n. Wats d oa?