There is a formula to find this
Each Instalment= Pxr/100
30000=px3/100
=>4.46
can u plz explain this formulae, how did u arrive at this formulae??
can u plz explain this formulae, how did u arrive at this formulae??
Help me here guys , i cant solve these:banghead: :
Find the missing terms :
1.)2,3,8,63.....
a.)3968
b.)3759
c.)4959
d.)3000
2.)1,7,25,61,121......
a.)216
b.)211
c.)210
d.)212
3.)1/2, 1/2, 2/4 , 6/12 , 24/48.....
a.)125/250
b.)132/264
c.)120/240
d.)150/300
ALso explain the relationship between terms......
Help me here guys , i cant solve these:banghead: :
ALso explain the relationship between terms......
Find the missing terms :
1.)2,3,8,63.....
a.)3968
b.)3759
c.)4959
d.)3000
2
2^2-1=3
3^2-1=8
8^2-1=63
63^2-1=3968
2.)1,7,25,61,121......
a.)216
b.)211
c.)210
d.)212
1^3-0=1
2^3-1=7
3^3-2=25
4^3-3=61
5^3-4=121
6^3-5=211
3.)1/2, 1/2, 2/4 , 6/12 , 24/48.....
a.)125/250
b.)132/264
c.)120/240
d.)150/300
1/2
1*1/2*1=1/2
1*2/2*2=2/4
2*3/4*3=6/12
6*4/4*12=24/48
24*5/48*5=120/240
way2imagination Sayscan u plz explain this formulae, how did u arrive at this formulae??
There is a big derivation for this in T.I.M.E materials. If u have one you can go through it...
Arun sharma-Number system-level one -problem no.28
can anyone explain..GCD is to be find..but not getting answer
Arun sharma-Number system-level one -problem no.28
can anyone explain..GCD is to be find..but not getting answer
Arun sharma-Number system-level one -problem no.28
can anyone explain..GCD is to be find..but not getting answer
Are you talking about the Milkman problem?
The GCD/HCF of each of the numbers (403, 465, 496) is 31.
403 = 31 * 13
465 = 31 * 15
496 = 31 * 16
The least number of bottles would therefore be 13 + 15 + 16 = 44 i.e. option (d)
Interestingly a problem testing this simple concept had appeared even in XAT last year.
Hope this helps.
one more problem no.34
which of the following is not a perfect square?
100856
325137
945729
all of these?
what is the funda here?
one more problem no.34
which of the following is not a perfect square?
100856
325137
945729
all of these?
what is the funda here?
I'm not sure whether you are aware of this concept, but a number is a perfect square if & only if all its prime factors have an even power.
eg: 3^7 * 5^4 won't be a perfect square since the power of 3 is odd.
Using this -
100856 = 2^3 * 12607
At this stage itself you can say this won't be a PS since the max power 2 can have is 3, an odd no.
Similarly, 325137 = 3 * 108379
Again, 108379 is not divisible by 3 (use divisiblity rule). So the power for 3 will be 1, an odd no.
Both 1 & 2 are not PS. The ans can therefore only be d.
Hope I've not made a calculation mistake here.
Problem no.62
which of these is greater?
54^4 or 21^12
(0.4)^4 or (0.8 )^3
what is funda here?
Problem no.62
which of these is greater?
54^4 or 21^12
(0.4)^4 or (0.8 )^3
what is funda here?
For the first -
(54^4)^(1/4) = 54
(21^12)^(1/4) = 21^3
21^12 is greater.
The second is too simple a calculation to try out the above. But still -
0.4^4 = (4 * 10^-1)^4 = 256 * 10^-4 = .0256
0.8^3 = (8 * 10^-1 )^3 = 64 * 10^-3 = .0640
Therefore, (0.8 )^3 is greater . In any case, this can be done orally since it can be seen that the power of 10 will be -4 & -3 resp.
Problem no.62
which of these is greater?
54^4 or 21^12
(0.4)^4 or (0.8 )^3
what is funda here?
Break down the numbers into their prime factors:
First question:
54^4 -> (2*3*3*3)^4 -> (2^4)*(3^12)
21^12 -> (3^12)*(7^12)
Since 3^12 is the common factor and 7^12 is obviously larger than 2^4, 21^12 is much larger
Second question:
(0.4)^4 -> (2*2/10)^4 -> (2/5)^4 -> 2^4 * 5^(-4)
(0.8 )^3 -> (2*2*2/10)^3 -> (2*2/5)^3 -> 2^6 * 5^(-3) -> 2^4 * 2^2 * 5^(-3)
Since 2^4 is common and 5^(-3) is larger than 5^(-4), then (0.8 )^3 is easily larger.
one more problem no.34
which of the following is not a perfect square?
100856
325137
945729
all of these?
what is the funda here?
Another easier method to chk is digit sum rule. Any perfect square will have a digit sum of 1,4,7,9
100856=>2
325137=>3
so both of these cant be perfect squares
Another easier method to chk is digit sum rule. Any perfect square will have a digit sum of 1,4,7,9
100856=>2
325137=>3
so both of these cant be perfect squares
This method is good to eliminate options but not good in confirming a number as a square, because two numbers can have a digit sum of 7 but one can be a square and other a non-square number.
someone please give the solution for question number 1 of LOD 3, on the chapter Profit and Loss...
piyushm807 Sayssomeone please give the solution for question number 1 of LOD 3, on the chapter Profit and Loss...
Take time to post the question. Not everyone has the book.. And there are people who are lazy to open the book as i am
All right Eagle.. Firstly it seems like the thread is on Arun Sharma's book probs so kinda got tempted to assume every one has a book. Secondly,I wonder how a person being lazy can be patient enough to read the following the question...Anyway if u say so, then....Here I go...i hope though lazy, u are keener..:P
The charges of a taxi journey are decided on the basis of the distance covered and the amount of the waiting time during a journey. Distance wise, for the first 2 kilometres (or any part thereof) of a journe, the metre reading is fixed as Rs 10(if there is no waiting). Also if a taxi is boarded and it does not move, then the metre reading is again fixed at Rs 10 for the first ten minutes of waiting. For every additional kilometre the metre reading changes by Rs 5 (with changes in the meter reading being in multiples of Re. 1 for every 200 metres travelled). For every additional minute of waiting, the metre reading changes by Re. 1 (no account is taken of a fraction of a minute waited for or of a distance less than 200 metres travelled). The net meter reading is a function of the amount of time waited for and the distance travelled.
The cost of running a taxi depends on the fuel efficiency (in terms of mileage/litre), depreciation (straight line over 10 years) and the driver's salary (not taken into account if the taxi is self owned).
Depreciation is Rs. 100 per day everyday of the first 10 years. This depreciation has to be added equally to the cost for every customer while calculating the profit for a particular trip. Similarly, the driver's salary is also apportioned equally across the customers of the particular day. Assume, for simplicity that there are 50 customers every day(unless otherwise mentioned). The cost of fuel is Rs 15 per litre(unless otherwise stated).
The customer has to pay 20% over the meter reading while settling his bill. Also assume that there is no fuel cost for waiting time (unless otherwise stated).
Based on the above facts , answer the following
1) If Sardar Preetpal Singh's taxi is 14 years old and has a fuel efficiency of 12km/litre of fuel, find his profit in a run from Howrah Station to Park Street (a distance of 7 kms) if the stoppage time is 8 minutes. Assume he owns the taxi
a) Rs 32.25 b) Rs. 40.85
c) Rs 34.25 d) Rs 42.85
e) Rs 44.85
Ans - Rs 42.85
2) the percentage profit is :
a) 391.42 % b) 380 %
c)489.71 % d) 438.23 %
e) 444.25 %
Ans - (c)
3) For the same journey as in question (1), if on another day, with heavier traffic, the waiting time increases to 13 minutes, find the percentage change in profit :
a) 12% b) 14%
c) 13% d) 16%
e) 17%
All right Eagle.. Firstly it seems like the thread is on Arun Sharma's book probs so kinda got tempted to assume every one has a book. Secondly,I wonder how a person being lazy can be patient enough to read the following the question...Anyway if u say so, then....Here I go...i hope though lazy, u are keener..:P
The charges of a taxi journey are decided on the basis of the distance covered and the amount of the waiting time during a journey. Distance wise, for the first 2 kilometres (or any part thereof) of a journe, the metre reading is fixed as Rs 10(if there is no waiting). Also if a taxi is boarded and it does not move, then the metre reading is again fixed at Rs 10 for the first ten minutes of waiting. For every additional kilometre the metre reading changes by Rs 5 (with changes in the meter reading being in multiples of Re. 1 for every 200 metres travelled). For every additional minute of waiting, the metre reading changes by Re. 1 (no account is taken of a fraction of a minute waited for or of a distance less than 200 metres travelled). The net meter reading is a function of the amount of time waited for and the distance travelled.
The cost of running a taxi depends on the fuel efficiency (in terms of mileage/litre), depreciation (straight line over 10 years) and the driver's salary (not taken into account if the taxi is self owned).
Depreciation is Rs. 100 per day everyday of the first 10 years. This depreciation has to be added equally to the cost for every customer while calculating the profit for a particular trip. Similarly, the driver's salary is also apportioned equally across the customers of the particular day. Assume, for simplicity that there are 50 customers every day(unless otherwise mentioned). The cost of fuel is Rs 15 per litre(unless otherwise stated).
The customer has to pay 20% over the meter reading while settling his bill. Also assume that there is no fuel cost for waiting time (unless otherwise stated).
Based on the above facts , answer the following
1) If Sardar Preetpal Singh's taxi is 14 years old and has a fuel efficiency of 12km/litre of fuel, find his profit in a run from Howrah Station to Park Street (a distance of 7 kms) if the stoppage time is 8 minutes. Assume he owns the taxi
a) Rs 32.25 b) Rs. 40.85
c) Rs 34.25 d) Rs 42.85
e) Rs 44.85
Ans - Rs 42.85
2) the percentage profit is :
a) 391.42 % b) 380 %
c)489.71 % d) 438.23 %
e) 444.25 %
Ans - (c)
3) For the same journey as in question (1), if on another day, with heavier traffic, the waiting time increases to 13 minutes, find the percentage change in profit :
a) 12% b) 14%
c) 13% d) 16%
e) 17%
ans -(b)
All right Eagle.. Firstly it seems like the thread is on Arun Sharma's book probs so kinda got tempted to assume every one has a book. Secondly,I wonder how a person being lazy can be patient enough to read the following the question...Anyway if u say so, then....Here I go...i hope though lazy, u are keener..:P
The charges of a taxi journey are decided on the basis of the distance covered and the amount of the waiting time during a journey. Distance wise, for the first 2 kilometres (or any part thereof) of a journe, the metre reading is fixed as Rs 10(if there is no waiting). Also if a taxi is boarded and it does not move, then the metre reading is again fixed at Rs 10 for the first ten minutes of waiting. For every additional kilometre the metre reading changes by Rs 5 (with changes in the meter reading being in multiples of Re. 1 for every 200 metres travelled). For every additional minute of waiting, the metre reading changes by Re. 1 (no account is taken of a fraction of a minute waited for or of a distance less than 200 metres travelled). The net meter reading is a function of the amount of time waited for and the distance travelled.
The cost of running a taxi depends on the fuel efficiency (in terms of mileage/litre), depreciation (straight line over 10 years) and the driver's salary (not taken into account if the taxi is self owned).
Depreciation is Rs. 100 per day everyday of the first 10 years. This depreciation has to be added equally to the cost for every customer while calculating the profit for a particular trip. Similarly, the driver's salary is also apportioned equally across the customers of the particular day. Assume, for simplicity that there are 50 customers every day(unless otherwise mentioned). The cost of fuel is Rs 15 per litre(unless otherwise stated).
The customer has to pay 20% over the meter reading while settling his bill. Also assume that there is no fuel cost for waiting time (unless otherwise stated).
Based on the above facts , answer the following
1) If Sardar Preetpal Singh's taxi is 14 years old and has a fuel efficiency of 12km/litre of fuel, find his profit in a run from Howrah Station to Park Street (a distance of 7 kms) if the stoppage time is 8 minutes. Assume he owns the taxi
a) Rs 32.25 b) Rs. 40.85
c) Rs 34.25 d) Rs 42.85
e) Rs 44.85
Ans - Rs 42.85
2) the percentage profit is :
a) 391.42 % b) 380 %
c)489.71 % d) 438.23 %
e) 444.25 %
Ans - (c)
3) For the same journey as in question (1), if on another day, with heavier traffic, the waiting time increases to 13 minutes, find the percentage change in profit :
a) 12% b) 14%
c) 13% d) 16%
e) 17%
ans -(b)
Someone please solve this.....
Buddy sorry for late reply, I do like solving prob so lazyness gets negated :D
1)If Sardar Preetpal Singh's taxi is 14 years old and has a fuel efficiency of 12km/litre of fuel, find his profit in a run from Howrah Station to Park Street (a distance of 7 kms) if the stoppage time is 8 minutes. Assume he owns the taxi
Cost of petrol for 7km journey =>8.75 (price of petrol-rs 15/litre from prob statement)
now calculate the metre charege =>10+5x5+8=>43+8.6=>51.6
here 10 - charge for first 2 km
5x5=> charges for next 5 km as for every km he takes 5rs
8=>waiting charges
8.6=>20% pay over meter reading
profit=>51.6-8.75
=>42.85
2)the percentage profit is :
51.6-8.75/8.75
=>489.71%
3)with increase of 13 min in waiting time =>10+5x5+13=>48+9.6=>57.6
profit=>57.6-8.75=>48.85
=>48.85-42.85/42.85
=>14%