@pakkapagal said:why not 1000/12?
...lol.. galti se mistake kar dia. applied time work, i think combined work will be 8+4 pages. Thank you for pointing my mistake. :)yes. 1000/12 should be right.
...lol.. galti se mistake kar dia. applied time work, i think combined work will be 8+4 pages. Thank you for pointing my mistake. :)yes. 1000/12 should be right.
@jashholmes said:A number P is increased by 30% and another number Q is decreased by 30% to make them equal. But what percentage is Q greater than P???
=> P" = Q"
=> 1.3 P = 0.7 Q
=> Q = P*(1.3/0.7) = 13P/7.
So, 6/7 = 600/7 = 85.7 %
@ChirpiBird said:...lol.. galti se mistake kar dia. applied time work, i think combined work will be 8+4 pages. Thank you for pointing my mistake. yes. 1000/12 should be right.
but OA nhi malum :P....itna saral hota to pg pe nhi hota :D
@jashholmes said:A certain type of amoeba is able to spilt itself up into 24 amoebae, each of these amoebae are further able to split themselves up into 24 amoebae and so on. However, only 25% of the amoebae are able to do so while the rest die. If the number of amoebae after the 4th such split are 3888. How many amoebae were there at the beginning???
I think it wil be 3...Its in powers of 6...
So it will be 6*6*6*6*a
Where a is initial number....
Unable to calculate...travelling....
@jashholmes said:A number P is increased by 30% and another number Q is decreased by 30% to make them equal. But what percentage is Q greater than P???
1.3P = .7Q
Q - P/P*100 = (Q - .7/1.3*Q)/(.7/1.3*Q)*100 = 85.71% ?
@jashholmes said:A number P is increased by 30% and another number Q is decreased by 30% to make them equal. But what percentage is Q greater than P???
85.7%?
(130/100)*P = (70/100)*Q
=> P/Q = 70/130
So,Q is 85.7% greater than P
@jashholmes said:A number P is increased by 30% and another number Q is decreased by 30% to make them equal. But what percentage is Q greater than P???
1.3P=.7Q
13/7=Q/P
(13-7)/7=(Q-P)/P
(6/7)*100... = 14.28*6=85.68%??
13/7=Q/P
(13-7)/7=(Q-P)/P
(6/7)*100... = 14.28*6=85.68%??
@jashholmes said:A number P is increased by 30% and another number Q is decreased by 30% to make them equal. But what percentage is Q greater than P???
13P = 7q...
Q = 13p/7
So 600/7%
@jashholmes said:A number P is increased by 30% and another number Q is decreased by 30% to make them equal. But what percentage is Q greater than P???
130P = 70Q
P/Q = 70/130
70*X% = 50
=> X = 85.xx
@Estallar12 said:=> P" = Q"=> 1.3 P = 0.7 Q=> Q = P*(1.3/0.7) = 13P/7.So, 6/7 = 600/7 = 85.7 %
p=70, q=130
60/130x100=60%
This answer is wrong.....WHY???
@jashholmes said:A number P is increased by 30% and another number Q is decreased by 30% to make them equal. But what percentage is Q greater than P???
1.3p = 0.7q
p/q = 7/13
(13-7)/7 = 6/7 = 1 - 1/7 = 1 - 0.1428 = 0.8572 or 85.72%
@jashholmes said:p=70, q=13060/130x100=60%This answer is wrong.....WHY???
P was increased and q was decreased...
@jain4444 said:130P = 70Q P/Q = 70/130 70*X% = 50 => X = 85.xx
P=130 Q=70Q.P So, 130-70/130x100=60%
This answer is wrong....WHY???
@saurav205 said:P was increased and q was decreased...
yeah...sry..
P=130 Q=70
Q>P So, 130-70/130x100=60%
This answer is wrong....WHY???
This answer is wrong....WHY???
@jashholmes said:In a town 25% of the population eat rice. Of the remaining 1/3rd eat clean wheat only. Of the remaining 20% eat jowar only in the remaining 112 persons eat bajra only. Find the total number of people in town.???
x/4+x/4+x/10+112=x,x=280?
A car travelling with 5/7 of its usual speed covers 42 km in 1 hr 40 min 48sec What is the usul speed of the car?
@jashholmes said:In a town 25% of the population eat rice. Of the remaining 1/3rd eat clean wheat only. Of the remaining 20% eat jowar only in the remaining 112 persons eat bajra only. Find the total number of people in town.???
x/4 = rice
(x-x/4)*1/3 = x/4 = clean wheat
20*x/200 = x/10 = jowar
x - (x/2+x/10) = 112
x - 3x/5 = 112
2x/5 = 112
x = 280...
@jain4444 said:A car travelling with 5/7 of its usual speed covers 42 km in 1 hr 40 min 48sec What is the usul speed of the car?
@jain4444 said:A car travelling with 5/7 of its usual speed covers 42 km in 1 hr 40 min 48sec What is the usul speed of the car?
1 hour 40 min 48 sec= 1 hour 40+4/5 min = 1 hour 204/5 min = 1+204/300 hour = 504/300 hour
5v/7 *504/300 =42
72v/60=42
6v/5=42
v=35??
@jashholmes said:p=70, q=13060/130x100=60%This answer is wrong.....WHY???
What percent of P is asked and not Q. :)
@jain4444 said:A car travelling with 5/7 of its usual speed covers 42 km in 1 hr 40 min 48sec What is the usul speed of the car?
35 KM/HR ?
42/5/7*x = 6048/3600
x = 35 km/hr