Official Quant thread for CAT 2013

MBA CAT 2024
19946
@mailtoankit said:
280 ?let total population be x.25x --> rice.75x*1/3 = .25x --> wheatof remaining .50x , .50x*.2 eat jowarremaining .4x = 112 eat bajraso x = 112/.4 = 280
Even I did this with the same method, but this is a very lengthy method.
Is there any other way to find the answer in a very short method???
19947
@Pradeep_Rss said:
A merchant claims 4 % loss on cofee but uses weight equal to 840 gm instead of kg .the merchant gains or losses what % ?
1000 gm = 1000 rs = cost price

claimed SP = 960 = money comes in
840 = comes goes out

840*x/100 = (960 - 840)
=> x = 14.28 % profit
19948
@Pradeep_Rss said:
A merchant claims 4 % loss on cofee but uses weight equal to 840 gm instead of kg .the merchant gains or losses what % ?
14.28% ?
let cp be 100
sp = .96*100 = 96
actual cp = 84
%gain = 96 - 84/84*100 = 14.28%
19949

Avg weight of 5 officers is 42 kg . an officer was replaced by a new one so the avg increased by 500 gms . weight of new officer?? and the weight of the replaced officer ??

19950
@Estallar12 said:
Thanks a ton man!
19951
A certain type of amoeba is able to spilt itself up into 24 amoebae, each of these amoebae are further able to split themselves up into 24 amoebae and so on. However, only 25% of the amoebae are able to do so while the rest die. If the number of amoebae after the 4th such split are 3888. How many amoebae were there at the beginning???
19952
@Pradeep_Rss said:
Avg weight of 5 officers is 42 kg . an officer was replaced by a new one so the avg increased by 500 gms . weight of new officer?? and the weight of the replaced officer ??
Total W = 42*5 = 210 kg.
New Total = 42.5 * 5 = 212.5 kg.

Increase in Weight = 2.5 kg.
19953
@Estallar12 said:
Total W = 42*5 = 210 kg.New Total = 42.5 * 5 = 212.5 kg.Increase in Weight = 2.5 kg.
can we find the weight of the person who is replaced ?
19954
@Pradeep_Rss said:
Avg weight of 5 officers is 42 kg . an officer was replaced by a new one so the avg increased by 500 gms . weight of new officer?? and the weight of the replaced officer ??
cannot be determined. ?
B(new off wt)-A(old off wt)=2.5 kgs
we need more info to find exact wts.

P.S : 100th post!!
19955
@jashholmes said:
A certain type of amoeba is able to spilt itself up into 24 amoebae, each of these amoebae are further able to split themselves up into 24 amoebae and so on. However, only 25% of the amoebae are able to do so while the rest die. If the number of amoebae after the 4th such split are 3888. How many amoebae were there at the beginning???
3?
19956
@jashholmes said:
A certain type of amoeba is able to spilt itself up into 24 amoebae, each of these amoebae are further able to split themselves up into 24 amoebae and so on. However, only 25% of the amoebae are able to do so while the rest die. If the number of amoebae after the 4th such split are 3888. How many amoebae were there at the beginning???
beginning =X
1st stage=24*X/4=6X
2nd Stage=24*6X/4=6^2X
4th split=6^4X
X=3?
19957
@jashholmes said:
A certain type of amoeba is able to spilt itself up into 24 amoebae, each of these amoebae are further able to split themselves up into 24 amoebae and so on. However, only 25% of the amoebae are able to do so while the rest die. If the number of amoebae after the 4th such split are 3888. How many amoebae were there at the beginning???
x

=> 24x/4 = 6x

=> 6x*24/4 = 36x

=> 36x*24/4 = 216x

=> 216x*24/4 => 1296x.

3888 = 1296*3

So, x = 3.
19958
@Pradeep_Rss said:
Avg weight of 5 officers is 42 kg . an officer was replaced by a new one so the avg increased by 500 gms . weight of new officer?? and the weight of the replaced officer ??
Cannot be determined...you can find out the difference in their weigjt...but not exact weigjt....
19959
@Pradeep_Rss said:
can we find the weight of the person who is replaced ?
We cannot !! :splat:
19960
@Pradeep_Rss said:
can we find the weight of the person who is replaced ?
We cannot !! :splat:
19961
@jashholmes said:
A certain type of amoeba is able to spilt itself up into 24 amoebae, each of these amoebae are further able to split themselves up into 24 amoebae and so on. However, only 25% of the amoebae are able to do so while the rest die. If the number of amoebae after the 4th such split are 3888. How many amoebae were there at the beginning???
start, a
1st split 24*a/4=6a
2nd.. 6^2*a
3rd... 6^3*a
4th 6^4*a=3888
or a=3.
19962
@jashholmes said:
A certain type of amoeba is able to spilt itself up into 24 amoebae, each of these amoebae are further able to split themselves up into 24 amoebae and so on. However, only 25% of the amoebae are able to do so while the rest die. If the number of amoebae after the 4th such split are 3888. How many amoebae were there at the beginning???
let initially x there

x*6*6*6*6 = 3888
=> x = 3
19963
@ani6 said:
ghosh can write twice as fast as basu.A poerson takes twicw as long to write with fountain pen compared to ball point pen.ghosh can write 8pages a day with a ball point pen.What is the least time taken to complete 1000 pages with both basu and ghosh working together???plz help
1000/12 ?
19964
@ChirpiBird said:
ghosh is writes 8pages using ball point penbasu will write 4 pages using ball point pen (twice as slow.)basu will write 2 pages using fountain pen .. (fountain pen is twice as slow)ghosh will write 4 pages using ball point pen(twice as fast as basu)1/8+1/4=3/8(3/8)*1000 = 375days.. ??
why not 1000/12?

19965
A number P is increased by 30% and another number Q is decreased by 30% to make them equal. But what percentage is Q greater than P???