Official Quant thread for CAT 2013

MBA CAT 2024
18546
@nole said:
@Logrhythm what if square of some other number ends in say 55 or 66 ? for eg i know square of any number can not end with 3 or 8.similary can i refute for other numbers also ?
that does not happen...xxx6^2 wld always hv an odd ten's digit..
and 55 does not appear together..

yar these are all observation based questions....it is better that u remember such things, coz it is very difficult to actually figure these out in the exam..
18547

let d work done be 300 units ..so a does 30 units/day,b -15 units/day n c -10 units/day..so d amt shud b in d ratio 30:15:10..so OA is 1800?

@vbhvgupta said:
A b and c cna do a piece of work in 10, 20 and 30 days. they begin a new job of similar type and each of them work on it for one third of the total period of work. If they get 6600 for the new job , how much shd B get, given that the amounts distributed are in proportion to the work done by them1800 2200 3300 2400
let d work done be 300 units ..so a does 30 units/day,b -15 units/day n c -10 units/day..so d amt shud b in d ratio 30:15:10..so OA is 1800?
18548

A pipe can fill a tank in 4 hrs while a leak which is at 1/4th of thr height of the tank can empty upto that part in 2 hrs. If both r operated simultaneously and initiallly the tank is fulll, then when it will be 1/4th full

A.2 B.2 1/3 c. 1 1/2 D. 6hrs
18549
@vbhvgupta said:
A pipe can fill a tank in 4 hrs while a leak which is at 1/4th of thr height of the tank can empty upto that part in 2 hrs. If both r operated simultaneously and initiallly the tank is fulll, then when it will be 1/4th full
A.2 B.2 1/3 c. 1 1/2 D. 6hrs
Work done by pipe in an hour W/4
work done by leak in an hour W/8
(W/4-W/8 )n=W/4
n/8=1/4
n=2 hours
18550
@vbhvgupta said:
A pipe can fill a tank in 4 hrs while a leak which is at 1/4th of thr height of the tank can empty upto that part in 2 hrs. If both r operated simultaneously and initiallly the tank is fulll, then when it will be 1/4th full
A.2 B.2 1/3 c. 1 1/2 D. 6hrs
plus i think initially the tank should be empty
since if the leak can empty 1/4th part in 2hours
it will take 8 hours to empty the whole tank
while the pipe can fill in 4 hours
so the rate of water is more coming from the pipe than going out of the leak
so a full tank will never get empty
18551
@vbhvgupta said:
A b and c cna do a piece of work in 10, 20 and 30 days. they begin a new job of similar type and each of them work on it for one third of the total period of work. If they get 6600 for the new job , how much shd B get, given that the amounts distributed are in proportion to the work done by them
1800 2200 3300 2400
let them take 3n days to complete the work
work done by A Wn/10
B Wn/20
c Wn/30
amount of work done 1/10 : 1/20 :1/30
6:3:2
3*6600/11
1800
18552
@vbhvgupta said:
A b and c cna do a piece of work in 10, 20 and 30 days. they begin a new job of similar type and each of them work on it for one third of the total period of work. If they get 6600 for the new job , how much shd B get, given that the amounts distributed are in proportion to the work done by them1800 2200 3300 2400
days taken -> 1:2:3
get paid in -> 1/1:1/2:1/3 = 6:3:2
hence b gets 3/11*6600 = 1800...
18553

20 cubical blocks are arranged as shown. first 10 are arranged in a triangular pattern , then a layer of 6 arranged on in a triangular pattern on it then again layer of 3 on it and atlast 1 on tht al are in triangular form. the blocks of bottom levl are numbered 1 to 10 in some order.each block in lvl 2,3,4, assigned a number which is d sum of the numbers assigned to three blocks on which it rests. find d smallest posbl no which could be assigned to the top block

18554
@dream_IIMA said:
20 cubical blocks are arranged as shown. first 10 are arranged in a triangular pattern , then a layer of 6 arranged on in a triangular pattern on it then again layer of 3 on it and atlast 1 on tht al are in triangular form. the blocks of bottom levl are numbered 1 to 10 in some order.each block in lvl 2,3,4, assigned a number which is d sum of the numbers assigned to three blocks on which it rests. find d smallest posbl no which could be assigned to the top block

Is it 114?

regards
scrabbler
18555

@scrabbler yes expln plz

18556

I tried drawing it out with 4 rows
a
b c
d e f
g h i j
and then trying to apply the given rules. It turns out that by the time I reach the top as described, the middle number (e) will occur 6 times, the 6 around it (bcdfhi) will be 3 times each and the corner ones (agj) will occur only once. So to minimise 6 e + 3 (b+c+d+f+h+i) +1(a+g+j) I put e = 1, a, g, j, as 8, 9, 10 and the rest in between and got 114 total.

regards
scrabbler

18557
@scrabbler m nt gtng tht part of y 6 times nd 3 times plz expln tht
18558
@Exodia said:
Two different solutions of honey, milk and water are mixed with each other three times in varying proportions. The concentration of honey and milk in the three resulting solutions are found to be (10%, 16%), (12%, 12%) and (16%, x%) respectively. What is the value of x?(a) 4 (b) 7 (c) 8 (d) 10Plz answer along with explanation.
This could also be solved by using (loosely speaking) the logic of weighted averages/alligation:
10 - 12 - 16 differences are in the ratio 2 : 4 i.e. 1 :2 and hence
16 - 12 - x differences should also be 1 : 2 which gives x = 4.

regards
scrabbler
18559
@dream_IIMA said:
@scrabbler m nt gtng tht part of y 6 times nd 3 times plz expln tht
See attached....try to understand how the numbers add upwards.

regards
scrabbler
18560
@scrabbler humm got it thanks :)
18561
@Unternehmer yes
18562
@Estallar12 thanks

18563
@Subhashdec2 said:
n/8=1/4n=2 hours
@Subhashdec2 said:
plus i think initially the tank should be emptyso the rate of water is more coming from the pipe than going out of the leakso a full tank will never get empty



OA 6hrs

18564
@Logrhythm said:
days taken -> 1:2:3get paid in -> 1/1:1/2:1/3 = 6:3:2 hence b gets 3/11*6600 = 1800...
yar is line ka kya matlab hai...
each of them work on it for one third of the total period of work
18565

@vbhvgupta-it means that say if 't' is the time taken to complete the entire work, then each & every person worked for 't/3' period of time...