@nole said:@Estallar12answer is 4 (even in numbers u have got last two digits are 4 for all ) but still m not able too understand the solution.can u elaborate ?
Yeah. Got confused with the Language of the Question. It will be 4.
@chandrakant.k said:Starting off with an easy questionThe numbers x and y are three-digit positive integers, and x + y is a four-digit integer. The tens digit of x equals 7 and the tens digit of y equals 5. If x
@vijay_chandola said:On buying a camera, the shopkeeper gives three rolls of film free. On buying a camera and six rolls of film, the shopkeeper gives additional four rolls of film free. If the equivalent discount is the same in both cases, then how many rolls will be equal in value to a camera? 12, 15, 18, 24@chandrakant.k : Thanks for starting the thread! @ All: __/\__
3x /c = 4x / c+6x
18x^2 = 4cx-3cx
As x,c not equal zero
c=18x
Two different solutions of honey, milk and water are mixed with each other three times in varying proportions. The concentration of honey and milk in the three resulting solutions are found to be (10%, 16%), (12%, 12%) and (16%, x%) respectively. What is the value of x?
(a) 4 (b) 7 (c) 8 (d) 10
Plz answer along with explanation.
(a) 4 (b) 7 (c) 8 (d) 10
Plz answer along with explanation.
I have posted this many times before.some one please answer
A teacher wanted to adminster a multiple choice(each question having six choices) based quiz of high difficulty level to a class of sixty students.The quiz had sixty questions.The probability of selecting the correct answer for a good and brilliant student was 0.2 and 0.25 respectively.All the students were seated serially in 10 rows and 6 columns.
q) three good students were seated next to each other.What is the probability of them having the same incorrect choice for four consecutive questions ?
i did it like
to get one incorrect answer, probabilty is 1/5
so all INCORRECT for one student is 1/5*1/5*1/5*1/5
so overall for 3 students (1/5*1/5*1/5*1/5)^3 but it is not in options.where did i go wrong ?
answer is 4/3125
A teacher wanted to adminster a multiple choice(each question having six choices) based quiz of high difficulty level to a class of sixty students.The quiz had sixty questions.The probability of selecting the correct answer for a good and brilliant student was 0.2 and 0.25 respectively.All the students were seated serially in 10 rows and 6 columns.
q) three good students were seated next to each other.What is the probability of them having the same incorrect choice for four consecutive questions ?
i did it like
to get one incorrect answer, probabilty is 1/5
so all INCORRECT for one student is 1/5*1/5*1/5*1/5
so overall for 3 students (1/5*1/5*1/5*1/5)^3 but it is not in options.where did i go wrong ?
answer is 4/3125
@nole said:I have posted this many times before.some one please answerA teacher wanted to adminster a multiple choice(each question having six choices) based quiz of high difficulty level to a class of sixty students.The quiz had sixty questions.The probability of selecting the correct answer for a good and brilliant student was 0.2 and 0.25 respectively.All the students were seated serially in 10 rows and 6 columns.q) three good students were seated next to each other.What is the probability of them having the same incorrect choice for four consecutive questions ?i did it liketo get one incorrect answer, probabilty is 1/5so all INCORRECT for one student is 1/5*1/5*1/5*1/5so overall for 3 students (1/5*1/5*1/5*1/5)^3 but it is not in options.where did i go wrong ?answer is 4/3125
ye question to pehle bi solve kia hai kisi ne
Hello,could someone help me in understanding the concept of clocks used to solve this problem
At what time between 2 and 3 thaangle b/wthe hands ofclock is 60 degrees.
To solve this there is a direct formula in time material 11/2m-30h but I wanna know how to solve it without dis
@DeAdLy pata nai yar.this is XAT 2013 question,mai khud isko 3-4 bari post kar chuka hu,but I have not got the solution,so posted it again.
@Estallar12 ...there are 4 letters between A & E in the given word PAMPHLET ....so it can't be AE pair..??
@Exodia said:Two different solutions of honey, milk and water are mixed with each other three times in varying proportions. The concentration of honey and milk in the three resulting solutions are found to be (10%, 16%), (12%, 12%) and (16%, x%) respectively. What is the value of x?(a) 4 (b) 7 (c) 8 (d) 10Plz answer along with explanation.
Let percentage of Honey and Milk be y and z in one AND n and m in the other.
Using 10, 16 and 12,12 Solutions -
=> (y - 10)/(10 - n) = (z - 16)/(16 - m)
=> 16y - 160 + 10m - ym = 10z - 160 - nz + 16n
=> ym - nz = 16y - 10z + 10m - 16n
Make similar equations taking pairs of other solutions.
Overall we will get,
=> y - n / m - z = 1/2
and, y - n / m - z = 4/(12 - x)
Thus, 4/(12 - x ) = 1/2
Thus, X = 4. [Option A]
@nole said:I have posted this many times before.some one please answerA teacher wanted to adminster a multiple choice(each question having six choices) based quiz of high difficulty level to a class of sixty students.The quiz had sixty questions.The probability of selecting the correct answer for a good and brilliant student was 0.2 and 0.25 respectively.All the students were seated serially in 10 rows and 6 columns.q) three good students were seated next to each other.What is the probability of them having the same incorrect choice for four consecutive questions ?i did it liketo get one incorrect answer, probabilty is 1/5so all INCORRECT for one student is 1/5*1/5*1/5*1/5so overall for 3 students (1/5*1/5*1/5*1/5)^3 but it is not in options.where did i go wrong ?answer is 4/3125
I have not seen the whole explanation. but the question says probability of getting correct answer is 0.2=1/5, getting wrong should then be = 1-0.2=0.8=4/5 right?
@cynara said:I have not seen the whole explanation. but the question says probability of getting correct answer is 0.2=1/5, getting wrong should then be = 1-0.2=0.8=4/5 right?
XAT diya tha shayad tumne..
@ASR2013 said:Hello,could someone help me in understanding the concept of clocks used to solve this problemAt what time between 2 and 3 thaangle b/wthe hands ofclock is 60 degrees.To solve this there is a direct formula in time material 11/2m-30h but I wanna know how to solve it without dis
At 2 PM, Angle will be 2*30 = 60 Degrees.
Now, Hour Hand covers 30 Degrees in 60 minutes.
So, 1/2 Degree per minute.
Also, Minute hand covers 360 degrees in 60 minutes.
So, 6 degrees per minute.
Relative Degrees covered = 6 - 1/2 = 11/2 Degrees a minute.
11m/2 = 60.
=> m = 120/11 minutes.
Now, At 2 PM, angle = 60 degrees.
So, after 2*(120/11) = 240/11 minutes, it will again be 60 degrees.
@Unternehmer said:@Estallar12 ...there are 4 letters between A & E in the given word PAMPHLET ....so it can't be AE pair..??
Yeah.!
It will be only ONE pair PT.
Sorry!.
@cynara The line "probability of getting SAME incorrect question" confused me.yes probability of getting correct answer is 1/5,but then we can't say probaility of incorrect would be 0.8 because it is asking for probability of same incorrect . That's waht i understood i may be wrong.
but please if u get the solution do share it,i desperately want the answer.thanks in advance.
but please if u get the solution do share it,i desperately want the answer.thanks in advance.
@nole said:I have posted this before also,but want to know if answer can be arrived at logically ?The last two digits of N, a square of a natural number are both equal to x and x is not equal to 0.The last digit x must be a 1b 4c 6d can not be determined
squares of all numbers of the form (50k-12) and (50k+12) end in 44...
@Logrhythm what if square of some other number ends in say 55 or 66 ? for eg i know square of any number can not end with 3 or 8.similary can i refute for other numbers also ?
A b and c cna do a piece of work in 10, 20 and 30 days. they begin a new job of similar type and each of them work on it for one third of the total period of work. If they get 6600 for the new job , how much shd B get, given that the amounts distributed are in proportion to the work done by them
1800 2200 3300 2400